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Display information for equation id:math.224292.2 on revision:224292

* Page found: Spectral theorem (eq math.224292.2)

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Hash: 632f0297f3f3f77bb4d31292ec9bd8c2

TeX (original user input): 

\lambda_1 \langle e_1, e_1 \rangle = \langle A (e_1), e_1 \rangle = \langle e_1, A(e_1) \rangle = \bar\lambda_1 \langle e_1, e_1 \rangle

TeX (checked): 

\lambda _{1}\langle e_{1},e_{1}\rangle =\langle A(e_{1}),e_{1}\rangle =\langle e_{1},A(e_{1})\rangle ={\bar {\lambda }}_{1}\langle e_{1},e_{1}\rangle

LaTeXML (experimental; uses MathML) rendering

MathML (11.356 KB / 1.544 KB) :

λ 1 ⁢ ⟨ e 1 , e 1 ⟩ = ⟨ A ⁢ ( e 1 ) , e 1 ⟩ = ⟨ e 1 , A ⁢ ( e 1 ) ⟩ = λ ¯ 1 ⁢ ⟨ e 1 , e 1 ⟩ subscript 𝜆 1 subscript 𝑒 1 subscript 𝑒 1 𝐴 subscript 𝑒 1 subscript 𝑒 1 subscript 𝑒 1 𝐴 subscript 𝑒 1 subscript ¯ 𝜆 1 subscript 𝑒 1 subscript 𝑒 1 {\displaystyle\lambda_{1}\langle e_{1},e_{1}\rangle=\langle A(e_{1}),e_{1}% \rangle=\langle e_{1},A(e_{1})\rangle={\bar{\lambda}}_{1}\langle e_{1},e_{1}\rangle} 
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lamda 1 times mathematical left-angle e 1 comma e 1 mathematical right-angle equals mathematical left-angle upper A times left-parenthesis e 1 right-parenthesis comma e 1 mathematical right-angle equals mathematical left-angle e 1 comma upper A times left-parenthesis e 1 right-parenthesis mathematical right-angle equals lamda overbar Subscript 1 Baseline times mathematical left-angle e 1 comma e 1 mathematical right-angle

SVG (MathML can be enabled via browser plugin) rendering

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λ 1 ⟨ e 1 , e 1 ⟩ = ⟨ A ( e 1 ) , e 1 ⟩ = ⟨ e 1 , A ( e 1 ) ⟩ = λ ¯ 1 ⟨ e 1 , e 1 ⟩ {\displaystyle \lambda _{1}\langle e_{1},e_{1}\rangle =\langle A(e_{1}),e_{1}\rangle =\langle e_{1},A(e_{1})\rangle ={\bar {\lambda }}_{1}\langle e_{1},e_{1}\rangle } 
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    <annotation encoding="application/x-tex">{\displaystyle \lambda _{1}\langle e_{1},e_{1}\rangle =\langle A(e_{1}),e_{1}\rangle =\langle e_{1},A(e_{1})\rangle ={\bar {\lambda }}_{1}\langle e_{1},e_{1}\rangle }</annotation>
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SVG (6.785 KB / 2.191 KB) :

{\displaystyle \lambda _{1}\langle e_{1},e_{1}\rangle =\langle A(e_{1}),e_{1}\rangle =\langle e_{1},A(e_{1})\rangle ={\bar {\lambda }}_{1}\langle e_{1},e_{1}\rangle }

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