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Display information for equation id:math.224631.40 on revision:224631

* Page found: Stirling's approximation (eq math.224631.40)

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Occurrences on the following pages:

Hash: c9d1284b7d7675fa7d771e015853741c

TeX (original user input): 

z^{\bar n} = z(z+1) \cdots (z+n-1);

TeX (checked): 

z^{\bar {n}}=z(z+1)\cdots (z+n-1);

LaTeXML (experimental; uses MathML) rendering

MathML (4.613 KB / 912 B) :

z n ¯ = z ⁢ ( z + 1 ) ⁢ ⋯ ⁢ ( z + n - 1 ) ; superscript 𝑧 ¯ 𝑛 𝑧 𝑧 1 ⋯ 𝑧 𝑛 1 {\displaystyle z^{{{\bar{n}}}}=z(z+1)\cdots(z+n-1);} 
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SVG (7.13 KB / 2.383 KB) :

z Superscript n overbar Baseline equals z times left-parenthesis z plus 1 right-parenthesis times midline-horizontal-ellipsis times left-parenthesis z plus n minus 1 right-parenthesis semicolon

SVG (MathML can be enabled via browser plugin) rendering

MathML (1.078 KB / 402 B) :

z n ¯ = z ( z + 1 ) ⋯ ( z + n − 1 ) ; {\displaystyle z^{\bar {n}}=z(z+1)\cdots (z+n-1);} 
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SVG (5.023 KB / 2.084 KB) :

{\displaystyle z^{\bar {n}}=z(z+1)\cdots (z+n-1);}

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