Quasiconformal mapping: Revision history

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25 September 2014

10 January 2014

  • curprev 14:4014:40, 10 January 2014 en>Timwestwood42 8,946 bytes +8,946 statement that quasiconformal groups form a group isn't clear. Since the composition f\circ f^{-1} = id, it would require that f^{-1} is 1/K-q.c. by the composition law stated previously.

29 June 2012

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