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In mathematics, the '''Farrell–Jones conjecture''',<ref>Farrell, F.T., Jones, L.E., Isomorphism conjectures in algebraic K-theory, ''J. Amer. Math. Soc.'', v. 6, pp. 249&ndash;297, 1993</ref> named after [[F. Thomas Farrell]] (now at [http://www.math.binghamton.edu/farrell/ SUNY Binghamton]) and [[Lowell Edwin Jones]] (now at [http://www.math.sunysb.edu/~lejones/ SUNY Stony Brook]) states that certain [[assembly map]]s are [[isomorphism]]s. These maps are given as certain [[homomorphism]]s.


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The motivation is the interest in the target of the assembly maps; this may be, for instance, the [[algebraic K-theory]] of a [[group ring]]
 
:<math>K_n(RG)</math>
 
or the [[L-theory]] of a group ring
 
:<math>L_n(RG)</math>,
 
where ''G'' is some [[group (mathematics)|group]].
 
The sources of the assembly maps are [[equivariant homology theory]] evaluated on the [[classifying space]] of ''G'' with respect to the family of [[virtually cyclic group|virtually cyclic subgroup]]s of ''G''. So assuming the Farrell–Jones conjecture is true, it is possible to restrict computations to virtually cyclic subgroups to get information on complicated objects such as <math>K_n(RG)</math> or <math>L_n(RG)</math>.
 
The [[Baum-Connes conjecture]] formulates a similar statement, for the [[topological K-theory]] of reduced group <math>C^*</math>-algebras <math>K^ {top}_n(C^r_*(G))</math>.
 
==Formulation==
 
One can find for any ring <math> R</math> equivariant homology theories <math>KR^?_*,LR^?_*</math> satisfying
 
: <math>KR_n^G(\{\cdot\})\cong K_n(R[G])</math> respectively <math>LR_n^G(\{\cdot\})\cong L_n(R[G]).</math>
 
Here <math>R[G]</math> denotes the [[group ring]].
 
The K-theoretic Farrell–Jones conjecture for a group ''G'' states that the map <math>p:E_{VCYC}(G)\rightarrow \{\cdot\}</math> induces an isomorphism on homology
 
:<math>KR_*^G(p):KR_*^G(E_{VCYC}(G))\rightarrow KR_*^G(\{\cdot\})\cong K_*(R[G]).</math>
 
Here <math>E_{VCYC}(G)</math> denotes the [[classifying spaces for families|classifying space]] of the group ''G'' with respect to the family of virtually cyclic subgroups, i.e. a ''G''-CW-complex whose [[isotropy group]]s are virtually cyclic and for any virtually cyclic subgroup of ''G'' the [[fixed point set]] is [[contractible]].
 
The L-theoretic Farrell–Jones conjecture is analogous.
 
== Computational aspects ==
The computation of the algebraic K-groups and the L-groups of a group ring <math>R[G]</math> is motivated by obstructions living in those groups (see for example [[Wall's finiteness obstruction]], [[surgery obstruction]], [[Whitehead torsion]]). So suppose a group <math>G</math> satisfies the Farrell–Jones conjecture for algebraic K-theory. Suppose furthermore we have already found a model <math>X</math> for the classifying space for virtually cyclic subgroups:
 
: <math> \emptyset=X^{-1}\subset X^0\subset X^1\subset \ldots \subset X </math>
 
Choose <math>G</math>-pushouts and apply the Mayer-Vietoris sequence to them:
 
: <math> KR_n^G(\coprod_{j\in I_i} G/H_j\times S^{i-1})\rightarrow KR_n^G(\coprod_{j\in I_i} G/H_j\times D^i)\oplus KR_n^G(X^{i-1})\rightarrow KR_n^G(X^i) </math><math>\rightarrow KR_{n-1}^G(\coprod_{j\in I_i} G/H_j\times S^{i-1})\rightarrow KR_{n-1}^G(\coprod_{j\in I_i} G/H_j\times D^i)\oplus KR_{n-1}^G(X^{i-1}) </math>
 
This sequence simplifies to:
 
: <math> \bigoplus_{j\in I_i}K_n(R[H_j])\oplus \bigoplus_{j\in I_i} K_{n-1}(RH_j)\rightarrow \bigoplus_{j\in I_i} K_n(RH_j)\oplus KR_n^G(X^{i-1})\rightarrow KR_n^G(X^i) </math><math>\rightarrow \bigoplus_{j\in I_i}K_{n-1}(RH_j)\oplus\bigoplus_{j\in I_i}K_{n-2}(RH_j)\rightarrow \bigoplus_{j\in I_i} K_{n-1}(RH_j)\oplus KR^G_{n-1}(X^{i-1}) </math>
 
This means that if any group satisfies a certain isomorphism conjecture one can compute its algebraic K-theory (L-theory) only by knowing the algebraic K-Theory (L-Theory) of virtually cyclic groups and by knowing a suitable model for <math> E_{VCYC}(G)</math>.
 
===Why the family of virtually cyclic subgroups ? ===
One might also try to take for example the family of finite subgroups into account. This family is much easier to handle. Consider the infinite cyclic group <math> \Z </math>. A model for <math>E_{FIN}(\Z)</math> is given by the real line <math>\R</math>, on which <math>\Z</math> acts freely by translations. Using the properties of equivariant K-theory we get
 
: <math>K_n^\Z(\R)=K_n(S^1)=K_n(pt)\oplus K_{n-1}(pt)=K_n(R)\oplus K_{n-1}(R).</math>
 
The [[Bass-Heller-Swan decomposition]] gives
 
: <math>K_n^\Z(pt)=K_n(R[\Z])\cong K_n(R)\oplus K_{n-1}(R)\oplus NK_n(R)\oplus NK_n(R).</math>
 
Indeed one checks that the assembly map is given by the canonical inclusion.
 
: <math>K_n(R)\oplus K_{n-1}(R)\hookrightarrow K_n(R)\oplus K_{n-1}(R)\oplus NK_n(R)\oplus NK_n(R)</math>
 
So it is an isomorphism if and only if <math>NK_n(R) =0</math>, which is the case if <math>R</math> is a [[regular ring]]. So in this case one can really use the family of finite subgroups. On the other hand this shows that the isomorphism conjecture for algebraic K-Theory and the family of finite subgroups is not true. One has to extend the conjecture to a larger family of subgroups which contains all the counterexamples. Currently no counterexamples for the Farrell–Jones conjecture are known. If there is a counterexample, one has to enlarge the family of subgroups to a larger family which contains that counterexample.
 
== Inheritances of isomorphism conjectures ==
The class of groups which satisfies the fibered Farrell–Jones conjecture contain the following groups
 
* virtually cyclic groups (definition)
* hyperbolic groups (see <ref>{{Citation | last1=Bartels | first1=Arthur | last2=Lück | first2 = Wolfgang | last3=Reich | first3=Holger| arxiv=math/0609685 | title=The K-theoretic Farrell-Jones Conjecture for hyperbolic groups| journal = Preprintreihe SFB 478 --- Geometrische Strukturen in der Mathematik | volume=434 | year= 2007 | place=Münster}}</ref>)
* CAT(0)-groups (see <ref>{{Citation | last1=Bartels | first1=Arthur | last2=Lück | first2 = Wolfgang | last3=Reich | first3=Holger| arxiv=0901.0442 | title=The Borel Conjecture for hyperbolic and CAT(0)-groups| journal = Preprintreihe SFB 478 --- Geometrische Strukturen in der Mathematik | volume=506 | year= 2009|place = Münster}}</ref>)
* solvable groups (see <ref>{{Citation | last1=Wegner | first1=Christian | arxiv=1308.2432 | title=The Farrell-Jones Conjecture for virtually solvable groups | year= 2013}}</ref>)
 
Furthermore the class has the following inheritance properties:
 
* closed under finite products of groups
* closed under taking subgroups.
 
== Meta-conjecture and fibered isomorphism conjectures ==
 
Fix an equivariant homology theory <math>H^?_*</math>. One could say, that a group '' G'' satisfies the isomorphism conjecture for a family of subgroups<math> F</math>, if and only if the map induced by the projection <math> E_F(G)\rightarrow \{\cdot\} </math> induces an isomorphism on homology:
 
: <math> H_*^G(E_F(G))\rightarrow H_*^G(\{\cdot\}) </math>
 
The group ''G'' satisfies the fibered isomorphism conjecture for the family of subgroups ''F'' if and only if for any group homomorphism <math> \alpha :H\rightarrow G</math> the group ''H'' satisfies the isomorphism conjecture for the family
 
: <math>\alpha^*F:=\{H'\le H|\alpha(H)\in F\}</math>.
 
One gets immediately that in this situation <math>H</math> also satisfies the fibered isomorphism conjecture for the family <math>\alpha^*F</math>.
 
===Transitivity principle===
 
The transitivity principle is a tool to change the family of subgroups to consider. Given two families <math>F\subset F'</math> of subgroups of <math> G</math>. Suppose every group <math> H\in F'</math> satisfies the (fibered) isomorphism conjecture with respect to the family <math> F|_H:=\{H'\in F|H'\subset H\}</math>.
Then the group <math>G</math> satisfies the fibered isomorphism conjecture with respect to the family <math>F</math> if and only if it satisfies the (fibered) isomorphism conjecture with respect to the family <math>F'</math>.
 
===Isomorphism conjectures and group homomorphisms===
 
Given any group homomorphism <math>\alpha:H\rightarrow G</math> and suppose that ''G"' satisfies the fibered isomorphism conjecture for a family ''F'' of subgroups. Then also ''H"' satisfies the fibered isomorphism conjecture for the family <math> \alpha^*F</math>. For example if <math> \alpha</math> has finite kernel the family <math> \alpha^*VCYC </math> agrees with the family of virtually cyclic subgroups of ''H''.
 
For suitable <math>\alpha</math> one can use the transitivity principle to reduce the family again.
 
== Connections to other conjectures==
 
===Novikov conjecture ===
 
There are also connections from the Farrell–Jones conjecture to the [[Novikov conjecture]]. It is known that if one of the following maps
 
: <math>H^G_*(E_{VCYC}(G),L^{\langle-\infty\rangle}_R)\rightarrow H^G_*(\{\cdot\},L^{\langle-\infty\rangle}_R)= L^{\langle-\infty\rangle}_*(RG)</math>
 
: <math> H^G_*(E_{FIN}(G),K^{top}) \rightarrow H^G_*(\{\cdot\},K^{top}) = K_n(C^*_r(G))</math>
 
is rationally injective then the Novikov-conjecture holds for <math>G</math>. See for example,.<ref>Ranicki, A. A., "On the Novikov conjecture", ''In Novikov conjectures , index theorems and rigidity, Vol. 1'', (Oberwolfach 2003), pp. 272–337. Cambridge Univ. Press, Cambridge.</ref><ref>Lück, W. and Reich, H, "The Baum-Connes and the Farrell-Jones conjectures in K- and L-theory", ''In Handbook of K-theory. Vol. 1,2'', pp. 703–842. Springer, Berlin, 2005.</ref>
 
===Bost conjecture ===
 
The Bost conjecture states that the assembly map
 
:<math> H^G_*(E_{FIN}(G),K^{top}_{l^1})\rightarrow H^G_*(\{\cdot\},K^{top}_{l^1})=K_*(l^1(G)) </math>
 
is an isomorphism. The ring homomorphism <math> l^1(G)\rightarrow C_r(G)</math> induces maps in K-theory <math>K_*(l^1(G))\rightarrow K_*(C_r(G))</math>. Composing the upper assembly map with this homomorphism one gets exactly the assembly map occurring in the [[Baum-Connes conjecture]].
 
:<math> H^G_*(E_{FIN}(G),K^{top}_{l^1})=H^G_*(E_{FIN}(G),K^{top})\rightarrow H^G_*(\{\cdot\},K^{top})=K_*(C_r(G))</math>
 
===Kaplansky conjecture ===
 
The Kaplansky conjecture predicts that for an integral domain <math>R</math> and a torsionfree group <math>G</math> the only idempotents in <math>R[G]</math> are <math>0,1</math>. Each such idempotent <math>p</math> gives a projective <math>R[G]</math> module by taking the image of the right multiplication with <math>p</math>. Hence there seems to be a connection between the Kaplansky conjecture and the vanishing of <math>K_0(R[G])</math>. There are theorems relating the [[Kaplansky conjecture]] to the Farrell–Jones conjecture (compare <ref>{{Citation | doi=10.1112/jtopol/jtm008 | last1=Bartels | first1=Arthur | last2=Lück | first2=Wolfgang | last3= Reich | first3=Holger | title=On the Farrell-Jones Conjecture and its applications | arxiv=math/0703548| journal=Journal of Topology | volume=1 | year=2008 | issue=1 | pages = 57–86}}</ref>).
 
==References==
<references/>
 
{{DEFAULTSORT:Farrell-Jones Conjecture}}
[[Category:Surgery theory]]
[[Category:K-theory]]
[[Category:Conjectures]]

Revision as of 22:57, 19 March 2013

In mathematics, the Farrell–Jones conjecture,[1] named after F. Thomas Farrell (now at SUNY Binghamton) and Lowell Edwin Jones (now at SUNY Stony Brook) states that certain assembly maps are isomorphisms. These maps are given as certain homomorphisms.

The motivation is the interest in the target of the assembly maps; this may be, for instance, the algebraic K-theory of a group ring

or the L-theory of a group ring

,

where G is some group.

The sources of the assembly maps are equivariant homology theory evaluated on the classifying space of G with respect to the family of virtually cyclic subgroups of G. So assuming the Farrell–Jones conjecture is true, it is possible to restrict computations to virtually cyclic subgroups to get information on complicated objects such as or .

The Baum-Connes conjecture formulates a similar statement, for the topological K-theory of reduced group -algebras .

Formulation

One can find for any ring equivariant homology theories satisfying

respectively

Here denotes the group ring.

The K-theoretic Farrell–Jones conjecture for a group G states that the map induces an isomorphism on homology

Here denotes the classifying space of the group G with respect to the family of virtually cyclic subgroups, i.e. a G-CW-complex whose isotropy groups are virtually cyclic and for any virtually cyclic subgroup of G the fixed point set is contractible.

The L-theoretic Farrell–Jones conjecture is analogous.

Computational aspects

The computation of the algebraic K-groups and the L-groups of a group ring is motivated by obstructions living in those groups (see for example Wall's finiteness obstruction, surgery obstruction, Whitehead torsion). So suppose a group satisfies the Farrell–Jones conjecture for algebraic K-theory. Suppose furthermore we have already found a model for the classifying space for virtually cyclic subgroups:

Choose -pushouts and apply the Mayer-Vietoris sequence to them:

This sequence simplifies to:

This means that if any group satisfies a certain isomorphism conjecture one can compute its algebraic K-theory (L-theory) only by knowing the algebraic K-Theory (L-Theory) of virtually cyclic groups and by knowing a suitable model for .

Why the family of virtually cyclic subgroups ?

One might also try to take for example the family of finite subgroups into account. This family is much easier to handle. Consider the infinite cyclic group . A model for is given by the real line , on which acts freely by translations. Using the properties of equivariant K-theory we get

The Bass-Heller-Swan decomposition gives

Indeed one checks that the assembly map is given by the canonical inclusion.

So it is an isomorphism if and only if , which is the case if is a regular ring. So in this case one can really use the family of finite subgroups. On the other hand this shows that the isomorphism conjecture for algebraic K-Theory and the family of finite subgroups is not true. One has to extend the conjecture to a larger family of subgroups which contains all the counterexamples. Currently no counterexamples for the Farrell–Jones conjecture are known. If there is a counterexample, one has to enlarge the family of subgroups to a larger family which contains that counterexample.

Inheritances of isomorphism conjectures

The class of groups which satisfies the fibered Farrell–Jones conjecture contain the following groups

  • virtually cyclic groups (definition)
  • hyperbolic groups (see [2])
  • CAT(0)-groups (see [3])
  • solvable groups (see [4])

Furthermore the class has the following inheritance properties:

  • closed under finite products of groups
  • closed under taking subgroups.

Meta-conjecture and fibered isomorphism conjectures

Fix an equivariant homology theory . One could say, that a group G satisfies the isomorphism conjecture for a family of subgroups, if and only if the map induced by the projection induces an isomorphism on homology:

The group G satisfies the fibered isomorphism conjecture for the family of subgroups F if and only if for any group homomorphism the group H satisfies the isomorphism conjecture for the family

.

One gets immediately that in this situation also satisfies the fibered isomorphism conjecture for the family .

Transitivity principle

The transitivity principle is a tool to change the family of subgroups to consider. Given two families of subgroups of . Suppose every group satisfies the (fibered) isomorphism conjecture with respect to the family . Then the group satisfies the fibered isomorphism conjecture with respect to the family if and only if it satisfies the (fibered) isomorphism conjecture with respect to the family .

Isomorphism conjectures and group homomorphisms

Given any group homomorphism and suppose that G"' satisfies the fibered isomorphism conjecture for a family F of subgroups. Then also H"' satisfies the fibered isomorphism conjecture for the family . For example if has finite kernel the family agrees with the family of virtually cyclic subgroups of H.

For suitable one can use the transitivity principle to reduce the family again.

Connections to other conjectures

Novikov conjecture

There are also connections from the Farrell–Jones conjecture to the Novikov conjecture. It is known that if one of the following maps

is rationally injective then the Novikov-conjecture holds for . See for example,.[5][6]

Bost conjecture

The Bost conjecture states that the assembly map

is an isomorphism. The ring homomorphism induces maps in K-theory . Composing the upper assembly map with this homomorphism one gets exactly the assembly map occurring in the Baum-Connes conjecture.

Kaplansky conjecture

The Kaplansky conjecture predicts that for an integral domain and a torsionfree group the only idempotents in are . Each such idempotent gives a projective module by taking the image of the right multiplication with . Hence there seems to be a connection between the Kaplansky conjecture and the vanishing of . There are theorems relating the Kaplansky conjecture to the Farrell–Jones conjecture (compare [7]).

References

  1. Farrell, F.T., Jones, L.E., Isomorphism conjectures in algebraic K-theory, J. Amer. Math. Soc., v. 6, pp. 249–297, 1993
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    In case you are in search of an actual estate or Singapore property agent on-line, you simply should belief your intuition. It's because you do not know which agent is nice and which agent will not be. Carry out research on several brokers by looking out the internet. As soon as if you end up positive that a selected agent is dependable and reliable, you can choose to utilize his partnerise in finding you a home in Singapore. Most of the time, a property agent is taken into account to be good if he or she locations the contact data on his website. This may mean that the agent does not mind you calling them and asking them any questions relating to new properties in singapore in Singapore. After chatting with them you too can see them in their office after taking an appointment.

    Have handed an trade examination i.e Widespread Examination for House Brokers (CEHA) or Actual Property Agency (REA) examination, or equal; Exclusive brokers are extra keen to share listing information thus making certain the widest doable coverage inside the real estate community via Multiple Listings and Networking. Accepting a severe provide is simpler since your agent is totally conscious of all advertising activity related with your property. This reduces your having to check with a number of agents for some other offers. Price control is easily achieved. Paint work in good restore-discuss with your Property Marketing consultant if main works are still to be done. Softening in residential property prices proceed, led by 2.8 per cent decline within the index for Remainder of Central Region

    Once you place down the one per cent choice price to carry down a non-public property, it's important to accept its situation as it is whenever you move in – faulty air-con, choked rest room and all. Get round this by asking your agent to incorporate a ultimate inspection clause within the possibility-to-buy letter. HDB flat patrons routinely take pleasure in this security net. "There's a ultimate inspection of the property two days before the completion of all HDB transactions. If the air-con is defective, you can request the seller to repair it," says Kelvin.

    15.6.1 As the agent is an intermediary, generally, as soon as the principal and third party are introduced right into a contractual relationship, the agent drops out of the image, subject to any problems with remuneration or indemnification that he could have against the principal, and extra exceptionally, against the third occasion. Generally, agents are entitled to be indemnified for all liabilities reasonably incurred within the execution of the brokers´ authority.

    To achieve the very best outcomes, you must be always updated on market situations, including past transaction information and reliable projections. You could review and examine comparable homes that are currently available in the market, especially these which have been sold or not bought up to now six months. You'll be able to see a pattern of such report by clicking here It's essential to defend yourself in opposition to unscrupulous patrons. They are often very skilled in using highly unethical and manipulative techniques to try and lure you into a lure. That you must also protect your self, your loved ones, and personal belongings as you'll be serving many strangers in your home. Sign a listing itemizing of all of the objects provided by the proprietor, together with their situation. HSR Prime Recruiter 2010
  5. Ranicki, A. A., "On the Novikov conjecture", In Novikov conjectures , index theorems and rigidity, Vol. 1, (Oberwolfach 2003), pp. 272–337. Cambridge Univ. Press, Cambridge.
  6. Lück, W. and Reich, H, "The Baum-Connes and the Farrell-Jones conjectures in K- and L-theory", In Handbook of K-theory. Vol. 1,2, pp. 703–842. Springer, Berlin, 2005.
  7. Many property agents need to declare for the PIC grant in Singapore. However, not all of them know find out how to do the correct process for getting this PIC scheme from the IRAS. There are a number of steps that you need to do before your software can be approved.

    Naturally, you will have to pay a safety deposit and that is usually one month rent for annually of the settlement. That is the place your good religion deposit will likely be taken into account and will kind part or all of your security deposit. Anticipate to have a proportionate amount deducted out of your deposit if something is discovered to be damaged if you move out. It's best to you'll want to test the inventory drawn up by the owner, which can detail all objects in the property and their condition. If you happen to fail to notice any harm not already mentioned within the inventory before transferring in, you danger having to pay for it yourself.

    In case you are in search of an actual estate or Singapore property agent on-line, you simply should belief your intuition. It's because you do not know which agent is nice and which agent will not be. Carry out research on several brokers by looking out the internet. As soon as if you end up positive that a selected agent is dependable and reliable, you can choose to utilize his partnerise in finding you a home in Singapore. Most of the time, a property agent is taken into account to be good if he or she locations the contact data on his website. This may mean that the agent does not mind you calling them and asking them any questions relating to new properties in singapore in Singapore. After chatting with them you too can see them in their office after taking an appointment.

    Have handed an trade examination i.e Widespread Examination for House Brokers (CEHA) or Actual Property Agency (REA) examination, or equal; Exclusive brokers are extra keen to share listing information thus making certain the widest doable coverage inside the real estate community via Multiple Listings and Networking. Accepting a severe provide is simpler since your agent is totally conscious of all advertising activity related with your property. This reduces your having to check with a number of agents for some other offers. Price control is easily achieved. Paint work in good restore-discuss with your Property Marketing consultant if main works are still to be done. Softening in residential property prices proceed, led by 2.8 per cent decline within the index for Remainder of Central Region

    Once you place down the one per cent choice price to carry down a non-public property, it's important to accept its situation as it is whenever you move in – faulty air-con, choked rest room and all. Get round this by asking your agent to incorporate a ultimate inspection clause within the possibility-to-buy letter. HDB flat patrons routinely take pleasure in this security net. "There's a ultimate inspection of the property two days before the completion of all HDB transactions. If the air-con is defective, you can request the seller to repair it," says Kelvin.

    15.6.1 As the agent is an intermediary, generally, as soon as the principal and third party are introduced right into a contractual relationship, the agent drops out of the image, subject to any problems with remuneration or indemnification that he could have against the principal, and extra exceptionally, against the third occasion. Generally, agents are entitled to be indemnified for all liabilities reasonably incurred within the execution of the brokers´ authority.

    To achieve the very best outcomes, you must be always updated on market situations, including past transaction information and reliable projections. You could review and examine comparable homes that are currently available in the market, especially these which have been sold or not bought up to now six months. You'll be able to see a pattern of such report by clicking here It's essential to defend yourself in opposition to unscrupulous patrons. They are often very skilled in using highly unethical and manipulative techniques to try and lure you into a lure. That you must also protect your self, your loved ones, and personal belongings as you'll be serving many strangers in your home. Sign a listing itemizing of all of the objects provided by the proprietor, together with their situation. HSR Prime Recruiter 2010