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[[Image:Sylvester-square.svg|thumb|300px|Graphical demonstration of the convergence of the sum 1/2 + 1/3 + 1/7 + 1/43 + ... to 1. Each row of ''k'' squares of side length 1/''k'' has total area 1/''k'', and all the squares together exactly cover a larger square with area 1. Squares with side lengths 1/1807 or smaller are too small to see in the figure and are not shown.]]
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In [[number theory]], '''Sylvester's sequence''' is an [[integer sequence]] in which each member of the sequence is the product of the previous members, plus one. The first few terms of the sequence are:
:2, 3, 7, 43, 1807, 3263443, 10650056950807, 113423713055421844361000443 {{OEIS|id=A000058}}.
 
Sylvester's sequence is named after [[James Joseph Sylvester]], who first investigated it in 1880. Its values grow [[Double exponential function|doubly exponentially]], and the sum of its [[Reciprocal (mathematics)|reciprocal]]s forms a [[Series (mathematics)|series]] of [[unit fraction]]s that converges to 1 more rapidly than any other series of unit fractions with the same number of terms. The [[recurrence relation|recurrence]] by which it is defined allows the numbers in the sequence to be [[integer factorization|factored]] more easily than other numbers of the same magnitude, but, due to the rapid growth of the sequence, complete prime factorizations are known only for a few of its members. Values derived from this sequence have also been used to construct finite [[Egyptian fraction]] representations of 1, [[Sasakian manifold|Sasakian]] [[Einstein manifold]]s, and hard instances for [[online algorithm]]s.
 
== Formal definitions ==
Formally, Sylvester's sequence can be defined by the formula
:<math>s_n = 1 + \prod_{i = 0}^{n - 1} s_i.</math>
The [[empty product|product of an empty set]] is 1, so ''s''<sub>0</sub> = 2.
 
Alternatively, one may define the sequence by the [[recurrence relation|recurrence]]
:<math>\displaystyle s_i = s_{i-1}(s_{i-1}-1)+1,</math> with ''s''<sub>0</sub> = 2.
It is straightforward to show by induction that this is equivalent to the other definition.
 
== Closed form formula and asymptotics ==
The Sylvester numbers grow [[double exponential function|doubly exponentially]] as a function of ''n''. Specifically, it can be shown that
 
:<math>s_n = \left\lfloor E^{2^{n+1}}+\frac12 \right\rfloor,</math>
 
for a number ''E'' that is approximately 1.264084735305302.<ref>{{harvtxt|Graham|Knuth|Patashnik|1989}} set this as an exercise; see also {{harvtxt|Golomb|1963}}.</ref> This formula has the effect of the following [[algorithm]]:
:s<sub>0</sub> is the nearest integer to E<sup>2</sup>; s<sub>1</sub> is the nearest integer to E<sup>4</sup>; s<sub>2</sub> is the nearest integer to E<sup>8</sup>; for  s<sub>''n''</sub>, take E<sup>2</sup>, square it ''n'' more times, and take the nearest integer.
This would only be a practical algorithm if we had a better way of calculating E to the requisite number of places than calculating s<sub>''n''</sub> and taking its repeated square root.
 
The double-exponential growth of the Sylvester sequence is unsurprising if one compares it to the sequence of [[Fermat number]]s ''F''<sub>''n''</sub>; the Fermat numbers are usually defined by a doubly exponential formula, <math>2^{2^n}+1</math>, but they can also be defined by a product formula very similar to that defining Sylvester's sequence:
 
:<math>F_n = 2 + \prod_{i = 0}^{n - 1} F_i.</math>
 
== Connection with Egyptian fractions ==
The [[unit fraction]]s formed by the [[Multiplicative inverse|reciprocals]] of the values in Sylvester's sequence generate an [[Series (mathematics)|infinite series]]:
:<math>\sum_{i=0}^{\infty} \frac1{s_i} = \frac12 + \frac13 + \frac17 + \frac1{43} + \frac1{1807} + \cdots.</math>
The partial sums of this series have a simple form,
:<math>\sum_{i=0}^{j-1} \frac1{s_i} = 1 - \frac{1}{s_j-1} = \frac{s_j-2}{s_j-1}.</math>
This may be proved by induction, or more directly by noting that the recursion implies that
:<math>\frac{1}{s_i-1}-\frac{1}{s_{i+1}-1}=\frac{1}{s_i},</math>
so the sum [[Telescoping series|telescopes]]
:<math>\sum_{i=0}^{j-1} \frac{1}{s_i} = \sum_{i=0}^{j-1} \left( \frac{1}{s_i-1}-\frac{1}{s_{i+1}-1} \right) = \frac{1}{s_0-1} - \frac{1}{s_j-1} = 1 - \frac{1}{s_j-1}.</math>
Since this sequence of partial sums (''s''<sub>''j''</sub>-2)/(''s''<sub>''j''</sub>-1) converges to one, the overall series forms an infinite [[Egyptian fraction]] representation of the number one:
:<math>1 = \frac12 + \frac13 + \frac17 + \frac1{43} + \frac1{1807} + \cdots.</math>
One can find finite Egyptian fraction representations of one, of any length, by truncating this series and subtracting one from the last denominator:
:<math>1 = \tfrac12 + \tfrac13 + \tfrac16, \quad 1 = \tfrac12 + \tfrac13 + \tfrac17 + \tfrac1{42}, \quad 1 = \tfrac12 + \tfrac13 + \tfrac17 + \tfrac1{43} + \tfrac1{1806},\quad \dots.</math>
The sum of the first ''k'' terms of the infinite series provides the closest possible underestimate of 1 by any ''k''-term Egyptian fraction.<ref>This claim is commonly attributed to {{harvtxt|Curtiss|1922}}, but {{harvtxt|Miller|1919}} appears to be making the same statement in an earlier paper. See also {{harvtxt|Rosenman|1933}}, {{harvtxt|Salzer|1947}}, and {{harvtxt|Soundararajan|2005}}.</ref> For example, the first four terms add to 1805/1806, and therefore any Egyptian fraction for a number in the open interval (1805/1806,1) requires at least five terms.
 
It is possible to interpret the Sylvester sequence as the result of a [[greedy algorithm for Egyptian fractions]], that at each step chooses the smallest possible denominator that makes the partial sum of the series be less than one. Alternatively, the terms of the sequence after the first can be viewed as the denominators of the [[odd greedy expansion]] of 1/2.
 
== Uniqueness of quickly growing series with rational sums ==
As Sylvester himself observed, Sylvester's sequence seems to be unique in having such quickly growing values, while simultaneously having a series of reciprocals that converges to a rational number. This sequence provides an expample showing that double-exponential growth is not enough to cause an integer sequence to be an [[irrationality sequence]].<ref>{{citation |last=Guy | first=Richard K. | authorlink=Richard K. Guy | title=Unsolved problems in number theory | publisher=[[Springer-Verlag]] |edition=3rd | year=2004 |isbn=0-387-20860-7 | zbl=1058.11001 | contribution=E24 Irrationality sequences|page=346|url=http://books.google.com/books?id=1AP2CEGxTkgC&pg=PA346 }}.</ref>
 
To make this more precise, it follows from results of {{harvtxt|Badea|1993}} that, if a sequence of integers <math>a_n</math> grows quickly enough that
:<math>a_n\ge a_{n-1}^2-a_{n-1}+1,</math>
and if the series
:<math>A=\sum\frac1{a_i}</math>
converges to a rational number ''A'', then, for all ''n'' after some point, this sequence must be defined by the same recurrence
:<math>a_n= a_{n-1}^2-a_{n-1}+1</math>
that can be used to define Sylvester's sequence.
 
{{harvtxt|Erdős|1980}} [[Erdős conjecture|conjectured]] that, in results of this type, the inequality bounding the growth of the sequence could be replaced by a weaker condition,
:<math>\lim_{n\rightarrow\infty} \frac{a_n}{a_{n-1}^2}=1.</math>
{{harvtxt|Badea|1995}} surveys progress related to this conjecture; see also {{harvtxt|Brown|1979}}.
 
== Divisibility and factorizations ==
If ''i'' < ''j'', it follows from the definition that ''s''<sub>''j''</sub> ≡ 1 (mod ''s''<sub>''i''</sub>). Therefore, every two numbers in Sylvester's sequence are [[relatively prime]]. The sequence can be used to prove that there are infinitely many [[prime number]]s, as any prime can divide at most one number in the sequence. More strongly, no prime factor of a number in the sequence can be congruent to 5 (mod 6), and the sequence can be used to prove that there are infinitely many primes congruent to 7 (mod 12) {{harv|Guy|Nowakowski|1975}}.
 
{{unsolved|mathematics|Are all the terms in Sylvester's sequence squarefree?}}
Much remains unknown about the factorization of the numbers in the Sylvester's sequence. For instance, it is not known if all numbers in the sequence are [[Square-free integer|squarefree]], although all the known terms are.
 
As {{harvtxt|Vardi|1991}} describes, it is easy to determine which Sylvester number (if any) a given prime ''p'' divides: simply compute the recurrence defining the numbers modulo ''p'' until finding either a number that is congruent to zero (mod ''p'') or finding a repeated modulus.  Via this technique he found that 1166 out of the first three million primes are divisors of Sylvester numbers,<ref>This appears to be a typo, as Andersen finds 1167 prime divisors in this range.</ref> and that none of these primes has a square that divides a Sylvester number. A general result of {{harvtxt|Jones|2006}} implies that the set of prime factors of Sylvester numbers has density zero in the set of all primes.
 
The following table shows known factorizations of these numbers, (except the first four, which are all prime):<ref>All prime factors ''p'' of Sylvester numbers ''s''<sub>''n''</sub> with ''p'' &lt; 5{{e|7}} and ''n'' ≤ 200 are listed by Vardi. Ken Takusagawa lists the [http://kenta.blogspot.com/2006/01/factoring-sylvesters-sequence.html factorizations up to ''s''<sub>9</sub>] and the [http://kenta.blogspot.com/2006/04/sylvester-10th-factored.html factorization of ''s''<sub>10</sub>]. The remaining factorizations are from [http://users.cybercity.dk/~dsl522332/math/sylvester-factors.htm a list of factorizations of Sylvester's sequence] maintained by Jens Kruse Andersen. Retrieved 2012-07-25.</ref>
 
{| class="wikitable"
|-
! ''n''
! Factors of ''s''<sub>''n''</sub>
|-
|4
|13 × 139
|-
|5
|3263443, which is prime
|-
|6
|547 × 607 × 1033 × 31051
|-
|7
|29881 × 67003 × 9119521 × 6212157481
|-
|8
|5295435634831 × 31401519357481261 × 77366930214021991992277
|-
|9
|[[181 (number)|181]] × 1987 × 112374829138729 × 114152531605972711 × 35874380272246624152764569191134894955972560447869169859142453622851
|-
|10
|2287 × 2271427 × 21430986826194127130578627950810640891005487 × P156
|-
|11
|[[73 (number)|73]] × C416
|-
|12
|2589377038614498251653 × 2872413602289671035947763837 × C785
|-
|13
|52387 × 5020387 × 5783021473 × 401472621488821859737 × 287001545675964617409598279 × C1600
|-
|14
|13999 × 74203 × 9638659 × 57218683 × 10861631274478494529 × C3293
|-
|15
|17881 × 97822786011310111 × 54062008753544850522999875710411 × C6618
|-
|16
|128551 × C13335
|-
|17
|635263 × 1286773 × 21269959 × C26661
|-
|18
|50201023123 × 139263586549 × 60466397701555612333765567 × C53313
|-
|19
|C106721
|-
|20
|352867 × 6210298470888313 × C213419
|-
|21
|387347773 × 1620516511 × C426863
|-
|22
|91798039513 × C853750
|}
 
As is customary, P''n'' and C''n'' denote prime and [[composite numbers]] ''n'' digits long.
 
== Applications ==
{{harvtxt|Boyer|Galicki|Kollár|2005}} use the properties of Sylvester's sequence to define large numbers of [[Sasakian manifold|Sasakian]] [[Einstein manifold]]s having the [[differential topology]] of odd-dimensional [[hypersphere|spheres]] or [[exotic sphere]]s. They show that the number of distinct Sasakian Einstein [[Riemannian metric|metrics]] on a [[topological sphere]] of dimension 2''n'' &minus; 1 is at least proportional to ''s''<sub>''n''</sub> and hence has double exponential growth with ''n''.
 
As {{harvtxt|Galambos|Woeginger|1995}} describe, {{harvtxt|Brown|1979}} and {{harvtxt|Liang|1980}} used values derived from Sylvester's sequence to construct lower bound examples for [[online algorithm|online]] [[bin packing]] [[algorithm]]s. {{harvtxt|Seiden|Woeginger|2005}} similarly use the sequence to lower bound the performance of a two-dimensional cutting stock algorithm.<ref>In their work, Seiden and Woeginger refer to Sylvester's sequence as "Salzer's sequence" after the work of {{harvtxt|Salzer|1947}} on closest approximation.</ref>
 
[[Znám's problem]] concerns sets of numbers such that each number in the set divides but is not equal to the product of all the other numbers, plus one. Without the inequality requirement, the values in Sylvester's sequence would solve the problem; with that requirement, it has other solutions derived from recurrences similar to the one defining Sylvester's sequence. Solutions to Znám's problem have applications to the classification of surface singularities (Brenton and Hill 1988) and to the theory of [[nondeterministic finite automata]].<ref>{{harvtxt|Domaratzki|Ellul|Shallit|Wang|2005}}</ref>
 
{{harvtxt|Curtiss|1922}} describes an application of the closest approximations to one by ''k''-term sums of unit fractions, in lower-bounding the number of divisors of any [[perfect number]], and {{harvtxt|Miller|1919}} uses the same property to [[lower bound]] the size of certain [[Group (mathematics)|groups]].
 
== See also ==
* [[Cahen's constant]]
* [[Primary pseudoperfect number]]
 
== Notes ==
{{reflist}}
 
== References ==
{{refbegin|2}}
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  | mr = 1218459}}
* {{cite web
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  | title = On some criteria for irrationality for series of positive rationals: a survey
  | year = 1995
  | url = http://www.lacim.uqam.ca/~plouffe/OEIS/citations/caen.pdf}}
*{{cite journal
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* {{cite journal
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  | journal = [[Pacific Journal of Mathematics]]
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  | volume = 133
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* {{cite journal
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  | version = Tech. Rep. R-864
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* {{cite journal
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* {{cite journal
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* {{cite book
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* {{cite journal
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*{{cite journal
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* {{cite journal
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* {{cite journal
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* {{cite journal
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* {{cite journal
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  | arxiv = math.CA/0502247}}
* {{cite journal
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{{refend}}
 
== External links ==
* [http://www.mathpages.com/home/kmath455.htm Irrationality of Quadratic Sums], from K. S. Brown's MathPages.
* {{mathworld | title = Sylvester's Sequence | urlname = SylvestersSequence}}
 
{{good article}}
 
[[Category:Egyptian fractions]]
[[Category:Integer sequences]]
[[Category:Mathematical series]]
[[Category:Number theory]]
[[Category:Recurrence relations]]

Latest revision as of 23:53, 28 October 2014

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