Wigner D-matrix: Difference between revisions

From formulasearchengine
Jump to navigation Jump to search
en>Maschen
try again
en>Archelon
 
Line 1: Line 1:
{{Unreferenced|date=April 2012}}
Irwin Butts is what my spouse loves to call me though I don't truly like becoming called like that. For many years he's been working as a receptionist. North Dakota is her beginning place but she will have to transfer one day or another. What I adore performing is to gather badges but I've been taking on new things recently.<br><br>my webpage - [http://raybana.com/chat/pg/profile/GIsaachse at home std testing]
In [[mathematics]], it can be shown that there exist '''[[magma (algebra)|magmas]] that are [[commutative]] but not [[associative]]'''. A simple example of such a magma is given by considering the children's game of [[rock, paper, scissors]].
 
==A commutative non-associative magma==
 
Let <math>M := \{ r, p, s \}</math> and consider the [[binary operation]] <math>\cdot : M \times M \to M</math> defined, loosely inspired by the [[rock-paper-scissors]] game, as follows:
 
:<math>r \cdot p = p \cdot r = p</math> &nbsp; "paper beats rock";
:<math>p \cdot s = s \cdot p = s</math> &nbsp; "scissors beat paper";
:<math>r \cdot s = s \cdot r = r</math> &nbsp; "rock beats scissors";
:<math>r \cdot r = r</math> &nbsp; "rock ties with rock";
:<math>p \cdot p = p</math> &nbsp; "paper ties with paper";
:<math>s \cdot s = s</math> &nbsp; "scissors tie with scissors".
 
By definition, the magma <math>(M, \cdot)</math> is commutative, but it is also non-associative, as the following shows:
 
:<math>r \cdot (p \cdot s) = r \cdot s = r</math>
 
but
 
:<math>(r \cdot p) \cdot s = p \cdot s = s.</math>
 
==A commutative non-associative algebra==
 
Using the above example, one can construct a commutative non-associative [[algebra over a field]] <math>K</math>: take <math>A</math> to be the three-dimensional [[vector space]] over <math>K</math> whose elements are written in the form
 
:<math>(x, y, z) = x r + y p + z s</math>,
 
for <math>x, y, z \in K</math>. Vector addition and scalar multiplication are defined component-wise, and vectors are multiplied using the above rules for multiplying the elements <math>r, p</math> and <math>s</math>. The set
 
:<math>\{ (1, 0, 0), (0, 1, 0), (0, 0, 1) \}</math> i.e. <math>\{ r, p, s \}</math>
 
forms a [[basis (linear algebra)|basis]] for the algebra <math>A</math>. As before, vector multiplication in <math>A</math> is commutative, but not associative.
 
[[Category:Non-associative algebra]]

Latest revision as of 17:27, 14 November 2014

Irwin Butts is what my spouse loves to call me though I don't truly like becoming called like that. For many years he's been working as a receptionist. North Dakota is her beginning place but she will have to transfer one day or another. What I adore performing is to gather badges but I've been taking on new things recently.

my webpage - at home std testing