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{{For|the wavefunction of a particle in a periodic potential|Bloch wave}}
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In physics and chemistry, specifically in [[nuclear magnetic resonance]] (NMR), [[magnetic resonance imaging]] (MRI), and [[electron spin resonance]] (ESR), the '''Bloch equations''' are a set of macroscopic equations that are used to calculate the nuclear magnetization '''M''' = (''M''<sub>''x''</sub>, ''M''<sub>''y''</sub>, ''M''<sub>''z''</sub>) as a function of time when [[relaxation (NMR)|relaxation times]] ''T''<sub>1</sub> and ''T''<sub>2</sub> are present. These are [[Phenomenology (science)|phenomenological]] equations that were introduced by [[Felix Bloch]] in 1946.<ref>[[Felix Bloch|F Bloch]], ''Nuclear Induction'', Physical Review '''70''', 460-473 (1946)</ref> Sometimes they are called the [[equations of motion]] of nuclear magnetization.
 
==Bloch equations in laboratory (stationary) frame of reference==
Let '''M'''(''t'') = (''M<sub>x</sub>''(''t''), ''M<sub>y</sub>''(''t''), ''M<sub>z</sub>''(''t'')) be the nuclear magnetization. Then the Bloch equations read:
 
:<math>\frac {d M_x(t)} {d t} = \gamma ( \bold {M} (t) \times \bold {B} (t)  ) _x - \frac {M_x(t)} {T_2}</math>
:<math>\frac {d M_y(t)} {d t} = \gamma ( \bold {M} (t) \times \bold {B} (t)  ) _y - \frac {M_y(t)} {T_2}</math>
:<math>\frac {d M_z(t)} {d t} = \gamma ( \bold {M} (t) \times \bold {B} (t)  ) _z - \frac {M_z(t) - M_0} {T_1}</math>
 
where γ is the [[gyromagnetic ratio]] and '''B'''(''t'') = (''B''<sub>''x''</sub>(''t''), ''B''<sub>''y''</sub>(''t''), ''B''<sub>0</sub> + Δ''B''<sub>''z''</sub>(t)) is the [[magnetic field]] experienced by the nuclei.
The ''z'' component of the magnetic field '''B''' is sometimes composed of two terms:
*one, ''B''<sub>0</sub>, is constant in time,
*the other one, Δ''B''<sub>''z''</sub>(t), may be time dependent. It is present in [[MRI|magnetic resonance imaging]] and helps with the spatial decoding of the NMR signal.
'''M'''(''t'') &times; '''B'''(''t'') is the [[cross product]] of these two vectors.
''M''<sub>0</sub> is the steady state nuclear magnetization (that is, for example, when t → ∞); it is in the ''z'' direction.
 
===Physical background===
With no relaxation (that is both ''T''<sub>1</sub> and ''T''<sub>2</sub> → ∞) the above equations simplify to:
 
:<math>\frac {d M_x(t)} {d t} = \gamma ( \bold {M} (t) \times \bold {B} (t)  ) _x</math>
:<math>\frac {d M_y(t)} {d t} = \gamma ( \bold {M} (t) \times \bold {B} (t)  ) _y</math>
:<math>\frac {d M_z(t)} {d t} = \gamma ( \bold {M} (t) \times \bold {B} (t)  ) _z</math>
 
or, in vector notation:
 
:<math>\frac {d \bold {M}(t)} {d t} = \gamma  \bold {M} (t) \times \bold {B} (t)  </math>
 
This is the equation for [[Larmor precession]] of the nuclear magnetization ''M'' in an external magnetic field '''B'''.
 
The relaxation terms,
 
:<math>\left ( -\frac {M_x} {T_2},  -\frac {M_y} {T_2}, -\frac {M_z - M_0} {T_1} \right ) </math>
 
represent an established physical process of transverse and longitudinal relaxation of nuclear magnetization '''M'''.
 
===Bloch equations are macroscopic equations===
These equations are not ''microscopic'': they do not describe the equation of motion of individual nuclear magnetic moments. These are governed and described by laws of [[quantum mechanics]].
 
Bloch equations are ''macroscopic'': they describe the equations of motion of macroscopic nuclear magnetization that can be obtained by summing up all nuclear magnetic moment in the sample.
 
===Alternative forms of Bloch equations===
 
Opening the vector product brackets in the Bloch equations leads to:
 
:<math>\frac {d M_x(t)} {d t} = \gamma \left ( M_y (t) B_z (t) - M_z (t) B_y (t) \right ) - \frac {M_x(t)} {T_2}</math>
:<math>\frac {d M_y(t)} {d t} = \gamma \left ( M_z (t) B_x (t) - M_x (t) B_z (t) \right ) - \frac {M_y(t)} {T_2}</math>
:<math>\frac {d M_z(t)} {d t} = \gamma \left ( M_x (t) B_y (t) - M_y (t) B_x (t) \right ) - \frac {M_z(t) - M_0} {T_1}</math>
 
The above form is further simplified assuming
 
:<math>M_{xy} = M_x + iM_y \text{  and  } B_{xy} = B_x + iB_y\, </math> <!--- do not delete "\,": It improved display of the formula in certain browsers.--->
 
where ''i'' = √(-1). After some algebra one obtains:
 
:<math>\frac {d M_{xy}(t)} {d t} = -i \gamma \left ( M_{xy} (t) B_z (t) - M_z (t) B_{xy} (t) \right ) -
\frac {M_{xy}} {T_2} </math>.
:<math>\frac {d M_z(t)} {d t} = i \frac{\gamma}{2} \left ( M_{xy} (t) \overline{B_{xy} (t)} -
\overline {M_{xy}} (t) B_{xy} (t) \right )
- \frac {M_z - M_0} {T_1}</math>
 
where
 
:<math>\overline {M_{xy}} = M_x - i M_y </math>.
 
is the complex conjugate of ''M<sub>xy</sub>''. The real and imaginary parts of ''M<sub>xy</sub>'' correspond to ''M<sub>x</sub>'' and ''M<sub>y</sub>'' respectively.
''M<sub>xy</sub>'' is sometimes called '''transverse nuclear magnetization'''.
 
==Bloch equations in rotating frame of reference==
In a rotating frame of reference, it is easier to understand the behaviour of the nuclear magnetization '''M'''. This is the motivation:
 
===Solution of Bloch equations with ''T''<sub>1</sub>, ''T''<sub>2</sub> → &infin;===
Assume that:
*at ''t'' = 0 the transverse nuclear magnetization ''M''<sub>xy</sub>(0) experiences a constant magnetic field '''B'''(''t'') = (0, 0, ''B''<sub>0</sub>);
*''B''<sub>0</sub> is positive;
*there are no longitudinal and transverse relaxations (that is ''T''<sub>1</sub> and ''T''<sub>2</sub> → ∞).
 
Then the Bloch equations are simplified to:
 
:<math>\frac{d M_{xy}(t)} {d t} = -i \gamma  M_{xy} (t) B_{0}</math>,
:<math>\frac{d M_z(t)} {d t} = 0 </math>.
 
These are two (not coupled) [[linear differential equations]]. Their solution is:
 
:<math>M_{xy}(t) = M_{xy} (0) e^{-i \gamma B_{0} t}</math>,
:<math>M_z(t) = M_0 = \text{const} \,</math>. <!-- do not delete "\,", it improved display of the formula on certain browsers. --->
 
Thus the transverse magnetization, ''M''<sub>xy</sub>, rotates around the ''z'' axis with [[angular frequency]] ω<sub>0</sub> = γ''B''<sub>0</sub> in clockwise direction (this is due to the negative sign in the exponent).
The longitudinal magnetization, ''M''<sub>z</sub> remains constant in time. This is also how the transverse magnetization appears to an observer in the '''laboratory frame of reference''' (that is to a '''stationary observer''').
 
''M''<sub>xy</sub>(''t'') is translated in the following way into observable quantities of ''M''<sub>x</sub>(''t'') and ''M''<sub>y</sub>(''t''): Since
 
:<math>M_{xy}(t) = M_{xy} (0) e^{-i \gamma B_{z0} t} = M_{xy} (0) \left [ \cos (\omega _0 t) - i \sin (\omega_0 t) \right ]</math>
 
then
 
:<math>M_{x}(t) = \text {Re} \left (M_{xy} (t) \right ) = M_{xy} (0) \cos (\omega _0 t)</math>,
:<math>M_{y}(t) = \text {Im} \left (M_{xy} (t) \right ) = -M_{xy} (0) \sin (\omega _0 t)</math>,
 
where Re(''z'') and Im(''z'') are functions that return the real and imaginary part of complex number ''z''. In this calculation it was assumed that ''M''<sub>xy</sub>(0) is a real number.
 
===Transformation to rotating frame of reference===
 
This is the conclusion of the previous section: in a constant magnetic field ''B''<sub>0</sub> along ''z'' axis the transverse magnetization ''M''<sub>xy</sub> rotates around this axis in clockwise direction with angular frequency ω<sub>0</sub>. If the observer were rotating around the same axis in  clockwise direction with angular frequency  Ω, ''M''<sub>xy</sub> it would appear to him  rotating with angular frequency  ω<sub>0</sub> - Ω. Specifically, if the observer were rotating around the same axis in
clockwise direction with angular frequency ω<sub>0</sub>, the transverse magnetization ''M''<sub>xy</sub> would appear to him stationary.
 
This can be expressed mathematically in the following way:
* Let (''x'', ''y'', ''z'') the Cartesian coordinate system of the '''laboratory''' (or '''stationary''') '''frame of reference''', and
* (''x''&prime;, ''y''&prime;, ''z''&prime;) = (''x''&prime;, ''y''&prime;, ''z'') be a Cartesian coordinate system that is rotating around the ''z'' axis of the laboratory frame of reference with angular frequency Ω. This is called the '''rotating frame of reference'''. Physical variables in this frame of reference will be denoted by a prime.
 
Obviously:
 
:<math>M_z' (t) = M_z(t)\,</math>.<!--- do not delete "\,": it improves display of the formula in certain browsers. --->
 
What is ''M<sub>xy</sub>''&prime;(''t'')? Expressing the argument at the beginning of this section in a mathematical way:
 
:<math>M_{xy}'(t) = e^{+i \Omega t} M_{xy}(t)\,</math>.<!--- do not delete "\,": it improves display of the formula in certain browsers. --->
 
===Equation of motion of transverse magnetization in rotating frame of reference===
 
What is the equation of motion of ''M<sub>xy</sub>''&prime;(''t'')?
 
:<math>\frac {d M_{xy}'(t)} {d t} = \frac {d \left ( M_{xy}(t) e^{+i \Omega t} \right )} {d t} =
e^{+i \Omega t} \frac {d M_{xy}(t) } {d t} + i \Omega e^{+i \Omega t} M_{xy} =
e^{+i \Omega t} \frac {d M_{xy}(t) } {d t} + i \Omega M_{xy}'
</math>
 
Substitute from the Bloch equation in laboratory frame of reference:
 
:<math>\begin{align} \frac {d M_{xy}'(t)} {d t} & = e^{+i \Omega t} \left [-i \gamma \left ( M_{xy} (t) B_z (t) - M_z (t) B_{xy} (t) \right ) -
\frac {M_{xy}} {T_2} \right ] + i \Omega M_{xy}' \\
 
& = \left [-i \gamma \left ( M_{xy} (t) e^{+i \Omega t} B_z (t) - M_z (t) B_{xy} (t) e^{+i \Omega t}\right ) -
\frac {M_{xy} e^{+i \Omega t} } {T_2} \right ] + i \Omega M_{xy}' \\
 
& = -i \gamma \left ( M_{xy}' (t) B_z' (t) - M_z' (t) B_{xy}' (t) \right ) + i \Omega M_{xy}' -
\frac {M_{xy}'} {T_2} \\
 
\end{align}
</math>
 
But by assumption in the previous section: ''B''<sub>z</sub>&prime;(''t'') = ''B''<sub>z</sub>(''t'') = ''B''<sub>0</sub> + Δ''B''<sub>z</sub>(''t''). Substituting into the equation above:
 
:<math>\begin{align} \frac {d M_{xy}'(t)} {d t} & =  -i \gamma \left ( M_{xy}' (t) (B_0 + \Delta B_z(t)) - M_z (t) B_{xy}' (t) \right ) + i \Omega M_{xy}' -
\frac {M_{xy}'} {T_2} \\
 
& =  -i \gamma  B_0 M_{xy}'(t) - i \gamma  \Delta B_z(t) M_{xy}'(t) + i \gamma  B_{xy}' (t) M_z (t)+ i \Omega M_{xy}' -
\frac {M_{xy}'} {T_2} \\
 
& =  i (\Omega - \omega_0) M_{xy}'(t) - i \gamma  \Delta B_z(t) M_{xy}'(t) + i \gamma  B_{xy}' (t) M_z (t) -
\frac {M_{xy}'} {T_2} \\
 
\end{align}
</math>
 
This is the meaning of terms on the right hand side of this equation:
* ''i'' (Ω - ω) ''M''<sub>xy</sub>&prime;(''t'') is the Larmor term in the frame of reference rotating with angular frequency Ω. Note that it becomes zero when Ω = ω<sub>0</sub>.
* The -''i'' γ Δ''B''<sub>z</sub>(''t'') ''M''<sub>xy</sub>&prime;(''t'') term describes the effect of magnetic field inhomogeneity (as expressed  by  Δ''B''<sub>z</sub>(''t'')) on the transverse nuclear magnetization; it is used to explain ''T''<sub>2</sub><sup>*</sup>. It is also the term that is behind [[MRI]]: it is generated by the gradient coil system.
* The ''i'' γ Δ''B''<sub>xy</sub>&prime;(''t'') ''M''<sub>z</sub>(''t'') describes the effect of RF field (the Δ''B''<sub>xy</sub>&prime;(''t'') factor) on nuclear magnetization. For an example see below.
* - ''M''<sub>xy</sub>&prime;(''t'') / ''T''<sub>2</sub> describes the loss of coherency of transverse magnetization.
 
Similarly, the equation of motion of ''M<sub>z</sub>'' in the rotating frame of reference is:
:<math>\frac {d M_z(t)} {d t} = i \frac{\gamma}{2} \left ( M'_{xy} (t) \overline{B'_{xy} (t)} -
\overline {M'_{xy}} (t) B'_{xy} (t) \right )
- \frac {M_z - M_0} {T_1}</math>
 
==Simple solutions of Bloch equations==
 
===Relaxation of transverse nuclear magnetization ''M<sub>xy</sub>''===
Assume that:
* The nuclear magnetization is exposed to constant external magnetic field in the ''z'' direction ''B''<sub>z</sub>&prime;(''t'') = ''B''<sub>z</sub>(''t'') = ''B''<sub>0</sub>. Thus  ω<sub>0</sub> = γ''B''<sub>0</sub> and Δ''B''<sub>z</sub>(''t'') = 0.
* There is no RF, that is ''B''<sub>xy</sub>' = 0.
* The rotating frame of reference  rotates with an angular frequency Ω = ω<sub>0</sub>.
 
Then in the rotating frame of reference, the equation of motion for the transverse nuclear magnetization, ''M''<sub>xy</sub>'(''t'') simplifies to:
 
:<math>\frac {d M_{xy}'(t)} {d t} =  - \frac {M_{xy}'} {T_2}
</math>
 
This is a linear ordinary differential equation and its solution is
 
:<math> M_{xy}'(t) = M_{xy}'(0) e^{-t / T_2}</math>.
 
where ''M''<sub>xy</sub>'(0) is the transverse nuclear magnetization in the rotating frame at time ''t'' = 0. This is the initial condition for the differential equation.
 
Note that when the rotating frame of reference rotates ''exactly'' at the Larmor frequency (this is the physical meaning of the above assumption Ω = ω<sub>0</sub>), the vector of transverse nuclear magnetization, ''M''<sub>xy</sub>(''t'') appears to be stationary.
 
===90 and 180° RF pulses===
Assume that:
* Nuclear magnetization is exposed to constant external magnetic field in ''z'' direction ''B''<sub>z</sub>&prime;(''t'') = ''B''<sub>z</sub>(''t'') = ''B''<sub>0</sub>. Thus  ω<sub>0</sub> = γ''B''<sub>0</sub> and Δ''B''<sub>z</sub>(''t'') = 0.
* At ''t'' = 0 an RF pulse of constant amplitude and frequency ω<sub>0</sub> is applied. That is ''B'<sub>xy</sub>''(''t'') = ''B'<sub>xy</sub>'' is constant. Duration of this pulse is τ.
* The rotating frame of reference  rotates with an angular frequency Ω = ω<sub>0</sub>.
* ''T''<sub>1</sub> and ''T''<sub>2</sub> → ∞. Practically this means that τ ≪ ''T''<sub>1</sub> and ''T''<sub>2</sub>.
 
Then for 0 ≤ ''t'' ≤ τ:
 
:<math>\begin{align} \frac {d M_{xy}'(t)} {d t} = i \gamma  B_{xy}' M_z (t)
\end{align}
</math>
:<math>\frac {d M_z(t)} {d t} = i \frac{\gamma}{2} \left ( M'_{xy} (t) \overline{B'_{xy}} -
\overline {M'_{xy}} (t) B'_{xy} \right )
</math>
 
===Relaxation of longitudinal nuclear magnetization ''M<sub>z</sub>''===
{{Empty section|date=February 2011}}
 
==See also==
*The [[Bloch–Torrey equation]] is a generalization of the Bloch equations, which includes added terms due to the transfer of magnetization by diffusion.<ref>
{{cite journal
| doi=10.1103/PhysRev.104.563
| last=Torrey | first=H C
| title=Bloch Equations with Diffusion Terms
|year=1956
|journal=Physical Review
|volume=104
|issue=3
| pages=563–565
| bibcode=1956PhRv..104..563T}} (1956)</ref>
 
==References==
{{Reflist}}
 
==Further reading==
* [[Charles Kittel]], ''Introduction to Solid State Physics'', John Wiley & Sons, 8th edition (2004), ISBN 978-0-471-41526-8. Chapter 13 is on Magnetic Resonance.
 
{{DEFAULTSORT:Bloch Equations}}
[[Category:Nuclear magnetic resonance]]
[[Category:Magnetic resonance imaging]]

Latest revision as of 13:37, 4 May 2014

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