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[[File:ImaginaryUnit5.svg|thumb|right|'''{{mvar|i}}''' in the [[complex plane|complex]] or [[Cartesian plane|cartesian]] plane. Real numbers lie on the horizontal axis, and imaginary numbers lie on the vertical axis]]
== overwhelmed win over the soul of the house ==
The '''imaginary unit''' or '''unit imaginary number''', denoted as '''{{mvar|i}}''', is a [[mathematics|mathematical]] concept which extends the [[real number]] system {{math|ℝ}} to the [[complex number]] system {{math|ℂ}}, which in turn provides at least one [[Root of a function|root]] for every [[polynomial]] {{math|''P''(''x'')}} (see [[algebraic closure]] and [[fundamental theorem of algebra]]). The imaginary unit's core property is that {{math|''i''<sup>2</sup> {{=}} −1}}. The term "[[imaginary number|imaginary]]" is used because there is no [[real number]] having a negative [[square (algebra)|square]].


There are in fact two complex square roots of −1, namely {{mvar|i}} and {{math|−''i''}}, just as there are two complex square roots of every other real number, except [[zero]], which has one double square root.
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In contexts where {{mvar|i}} is ambiguous or problematic, {{mvar|j}} or the Greek [[iota|{{math|ι}}]] (see [[#Alternative notations|alternative notations]]) is sometimes used. In the disciplines of [[electrical engineering]] and [[control systems engineering]], the imaginary unit is often denoted by {{mvar|j}} instead of {{mvar|i}}, because {{mvar|i}} is commonly used to denote [[electric current]] in these disciplines.
== 'Come on ==


For the history of the imaginary unit, see [[Complex number#History|Complex number: History]].
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==Definition==
== and under this acid itch ==
{| class="wikitable" style="float: right; margin-left: 1em; text-align: center;"
! The powers of {{mvar|i}}<br /> return cyclic values:
|-
|{{math|...}} (repeats the pattern<br /> from blue area)
|-
|{{math|1=''i''<sup>−3</sup> = ''i''}}
|-
|{{math|1=''i''<sup>−2</sup> = −1}}
|-
|{{math|1=''i''<sup>−1</sup> = −''i''}}
|-
|style="background:#cedff2;" | {{math|1=''i''<sup>0</sup> = 1}}
|-
|style="background:#cedff2;" | {{math|1=''i''<sup>1</sup> = ''i''}}
|-
|style="background:#cedff2;" | {{math|1=''i''<sup>2</sup> = −1}}
|-
|style="background:#cedff2;" | {{math|1=''i''<sup>3</sup> = −''i''}}
|-
|{{math|1=''i''<sup>4</sup> = 1}}
|-
|{{math|1=''i''<sup>5</sup> = ''i''}}
|-
|{{math|1=''i''<sup>6</sup> = −1}}
|-
|{{math|...}} (repeats the pattern<br /> from the blue area)
|}


The imaginary number {{mvar|i}} is defined solely by the property that its [[Square (algebra)|square]] is −1:
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:<math>i^2 = -1 \ . </math>
== 'But you want me to pan the door completely closed hand ==


With {{mvar|i}} defined this way, it follows directly from algebra that {{mvar|i}} and {{math|−''i''}} are both [[square root]]s of −1.
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Although the construction is called "imaginary", and although the concept of an imaginary number may be intuitively more difficult to grasp than that of a real number, the construction is perfectly valid from a mathematical standpoint. Real number operations can be extended to imaginary and complex numbers by treating {{mvar|i}} as an unknown quantity while manipulating an expression, and then using the definition to replace any occurrence of {{math|''i''<sup>2</sup>}} with −1. Higher integral powers of {{mvar|i}} can also be replaced with {{math|−''i''}}, 1, {{mvar|i}}, or −1:
<ul>
 
    
:<math>i^3 = i^2 i = (-1) i = -i \,</math>
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:<math>i^4 = i^3 i = (-i) i = -(i^2) = -(-1) = 1 \,</math>
 
:<math>i^5 = i^4 i = (1) i = i \,</math>
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Similarly, as with any non-zero real number:
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:<math>i^0 = i^{1-1} = i^1i^{-1} = i^1\frac{1}{i} = i\frac{1}{i} = \frac{i}{i} = 1 \,</math>
</ul>
 
As a complex number, {{mvar|i}} is equal to {{math|0&nbsp;+&nbsp;''i''}}, having a unit imaginary component and no real component (i.e., the real component is zero). In [[polar form]], {{mvar|i}} is {{math|1&nbsp;[[Euler's formula|cis]]&nbsp;<sup>π</sup>/<sub>2</sub>}}, having an [[absolute value]] (or magnitude) of 1 and an [[argument (complex analysis)|argument]] (or angle) of <sup>π</sup>/<sub>2</sub>. In the [[complex plane]] (also known as the [[Cartesian plane]]), {{mvar|i}} is the point located one unit from the origin along the imaginary axis (which is at a right angle to the real axis).
 
=={{anchor|i and -i}} {{mvar|i}} and {{math|−''i''}}==
 
Being a [[quadratic polynomial]] with no [[multiple root]], the defining equation {{math|''x''<sup>2</sup> {{=}} −1}} has ''two'' distinct solutions, which are equally valid and which happen to be [[additive inverse|additive]] and [[multiplicative inverse]]s of each other. More precisely, once a solution {{mvar|i}} of the equation has been fixed, the value {{math|−''i''}}, which is distinct from {{mvar|i}}, is also a solution. Since the equation is the only definition of {{mvar|i}}, it appears that the definition is ambiguous (more precisely, not [[well-defined]]). However, no ambiguity results as long as one or other of the solutions is chosen and labelled as "{{mvar|i}}", with the other one then being labelled as {{math|−''i''}}. This is because, although {{math|−''i''}} and {{mvar|i}} are not ''quantitatively'' equivalent (they ''are'' negatives of each other), there is no ''algebraic'' difference between {{mvar|i}} and {{math|−''i''}}. Both imaginary numbers have equal claim to being the number whose square is −1. If all mathematical textbooks and published literature referring to imaginary or complex numbers were rewritten with {{math|−''i''}} replacing every occurrence of {{math|+''i''}} (and therefore every occurrence of {{math|−''i''}} replaced by {{math|−(−''i'') {{=}} +''i'')}}, all facts and theorems would continue to be equivalently valid. The distinction between the two roots {{mvar|x}} of {{math|''x''<sup>2</sup> + 1 {{=}} 0}} with one of them labelled with a minus sign is purely a notational relic; neither root can be said to be more primary or fundamental than the other, and neither of them is "positive" or "negative".
 
The issue can be a subtle one. The most precise explanation is to say that although the complex [[field (algebra)|field]], defined as {{math|'''ℝ'''[''x'']/(''x''<sup>2</sup> + 1)}}, (see [[complex number]]) is [[unique]] [[up to]] [[isomorphism]], it is ''not'' unique up to a ''unique'' isomorphism &mdash; there are exactly 2 [[automorphism|field automorphisms]] of {{math|'''ℝ'''[''x'']/(''x''<sup>2</sup> + 1)}} which keep each real number fixed: the identity and the automorphism sending {{mvar|''x''}} to {{math|−''x''}}. See also [[Complex conjugate]] and [[Galois group]].
 
A similar issue arises if the complex numbers are interpreted as 2 × 2 real [[Matrix (mathematics)|matrices]] (see [[Complex_number#Matrix_representation_of_complex_numbers|matrix representation of complex numbers]]), because then both
 
:<math>X = \begin{pmatrix}
0 &  -1 \\
1 & \;\;0
\end{pmatrix} </math> &nbsp;&nbsp;&nbsp; and &nbsp;&nbsp;&nbsp; <math>X = \begin{pmatrix}
\;\;0 & 1 \\
-1  & 0
\end{pmatrix}
</math>
 
are solutions to the matrix equation
 
:<math> X^2 = -I = - \begin{pmatrix}
  1 & 0 \\
  0 & 1
  \end{pmatrix} = \begin{pmatrix}
  -1  & \;\;0 \\
  \;\;0 & -1
  \end{pmatrix}. \ </math>
 
In this case, the ambiguity results from the geometric choice of which "direction" around the [[unit circle]] is "positive" rotation. A more precise explanation is to say that the [[automorphism group]] of the [[orthogonal group|special orthogonal group]] SO (2, {{math|'''ℝ'''}}) has exactly 2 elements &mdash; the identity and the automorphism which exchanges "CW" (clockwise) and "CCW" (counter-clockwise) rotations. See [[orthogonal group]].
 
All these ambiguities can be solved by adopting a more rigorous [[Complex number#Formal construction|definition of complex number]], and explicitly ''choosing'' one of the solutions to the equation to be the imaginary unit. For example, the ordered pair (0, 1), in the usual construction of the complex numbers with two-dimensional vectors.
 
==Proper use==
The imaginary unit is sometimes written {{math|{{sqrt|−1}}}} in advanced mathematics contexts (as well as in less advanced popular texts). However, great care needs to be taken when manipulating formulas involving [[Nth root|radicals]]. The notation is reserved either for the principal square root function, which is ''only'' defined for real {{math|''x'' ≥ 0}}, or for the principal branch of the complex square root function. Attempting to apply the calculation rules of the principal (real) square root function to manipulate the principal branch of the complex square root function will produce false results:
 
:<math>-1 = i \cdot i = \sqrt{-1} \cdot \sqrt{-1} = \sqrt{(-1) \cdot (-1)} = \sqrt{1} = 1</math> &nbsp;&nbsp;&nbsp;''(incorrect)''.
 
Attempting to correct the calculation by specifying both the positive and negative roots only produces ambiguous results:
:<math>-1 = i \cdot i = \pm \sqrt{-1} \cdot \pm \sqrt{-1} = \pm \sqrt{(-1) \cdot (-1)} = \pm \sqrt{1} = \pm 1</math>&nbsp;&nbsp;&nbsp;''(ambiguous)''.
 
Similarly:
:<math>\frac{1}{i} = \frac{\sqrt{1}}{\sqrt{-1}} = \sqrt{\frac{1}{-1}} = \sqrt{\frac{-1}{1}} = \sqrt{-1} = i</math> &nbsp;&nbsp;&nbsp;''(incorrect)''.
 
The calculation rules
:<math>\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}</math>
and
:<math>\frac{\sqrt{a}} {\sqrt{b}} = \sqrt{\frac{a}{b}}</math>
are only valid for real, non-negative values of {{mvar|a}} and {{mvar|b}}.
 
These problems are avoided by writing and manipulating {{math|''i''{{sqrt|7}}}}, rather than expressions like {{math|{{sqrt|−7}}}}. For a more thorough discussion, see [[Square root]] and [[Branch point]].
 
== Properties ==
 
=== Square roots ===
[[Image:Imaginary2Root.svg|thumb|right|200px|The two square roots of {{mvar|i}} in the complex plane]]
The square root of {{mvar|i}} can be expressed as either of two complex numbers<ref group=nb>To find such a number, one can solve the equations
:{{math|(''x'' + ''iy'')<sup>2</sup> {{=}} ''i''}}
:{{math|''x''<sup>2</sup> + 2''ixy'' − ''y''<sup>2</sup> {{=}} ''i''}}
 
Because the real and imaginary parts are always separate, we regroup the terms:
 
:{{math|''x''<sup>2</sup> − ''y''<sup>2</sup> + 2''ixy'' {{=}} 0 + ''i''}}
 
and get a system of two equations:
 
:{{math|''x''<sup>2</sup> ''y''<sup>2</sup> {{=}} 0}}
:{{math|2''xy'' {{=}} 1}}
 
Substituting {{math|1=''y'' = 1/2''x''}} into the first equation, we get
 
:{{math|''x''<sup>2</sup> − 1/4''x''<sup>2</sup> {{=}} 0}}
:{{math|''x''<sup>2</sup> {{=}} 1/4''x''<sup>2</sup>}}
:{{math|4''x''<sup>4</sup> {{=}} 1}}
 
Because {{mvar|x}} is a real number, this equation has two real solutions for {{mvar|x}}: {{math|''x'' {{=}} 1/{{sqrt|2}}}} and {{math|''x'' {{=}} −1/{{sqrt|2}}}}. Substituting both of these results into the equation {{math|2''xy'' {{=}} 1}} in turn, we will get the same results for {{math|''y''}}. Thus, the square roots of {{mvar|i}} are the numbers {{math|1/{{sqrt|2}} + ''i''/{{sqrt|2}}}} and {{math|−1/{{sqrt|2}} − ''i''/{{sqrt|2}}}}.
 
([http://www.math.utoronto.ca/mathnet/questionCorner/rootofi.html University of Toronto Mathematics Network: What is the square root of i?] URL retrieved March 26, 2007.)</ref>
 
:<math> \pm \sqrt{i} = \pm \left( \frac{\sqrt{2}}{2} + \frac{\sqrt{2}}{2}i \right) = \pm \frac{\sqrt{2}}2 (1 + i). </math>
 
Indeed, squaring the right-hand side gives
 
:<math>
\begin{align}
\left( \pm \frac{\sqrt{2}}2 (1 + i) \right)^2 \ & = \left( \pm \frac{\sqrt{2}}2 \right)^2 (1 + i)^2 \ \\
  & = \frac{1}{2} (1 + 2i + i^2) \\
  & = \frac{1}{2} (1 + 2i - 1) \ \\
  & = i. \ \\
\end{align}
</math>
 
This result can also be derived with [[Euler's formula]]
 
:<math>e^{ix} = \cos(x) + i\sin(x) \,</math>
 
by substituting {{math|''x'' {{=}} &pi;/2}}, giving
 
:<math>e^{i(\pi/2)} = \cos(\pi/2) + i\sin(\pi/2) = 0 + i1 = i\,\! .</math>
 
Taking the square root of both sides gives
 
:<math> \pm \sqrt{i} = e^{i(\pi/4)} \,\! ,</math>
 
which, through application of Euler's formula to {{math|''x'' {{=}} &pi;/4}}, gives
 
:<math>
\begin{align}
\pm \sqrt{i} & = \cos(\pi/4) + i\sin(\pi/4) \\
  & = \frac{1}{\pm \sqrt{2}} + \frac{i}{\pm \sqrt{2}}\\
  & = \frac{1+i}{\pm \sqrt{2}}\\
  & = \pm \frac{\sqrt{2}}2 (1 + i).\\
\end{align}
</math>
 
Similarly, the square root of {{math|−''i''}} can be expressed as either of two complex numbers using Euler's formula:
 
:<math>e^{ix} = \cos(x) + i\sin(x) \,</math>
 
by substituting {{math|''x'' {{=}} 3&pi;/2}}, giving
 
:<math>e^{i(3\pi/2)} = \cos(3\pi/2) + i\sin(3\pi/2) = 0 - i1 = -i\,\! .</math>
 
Taking the square root of both sides gives
 
:<math> \pm \sqrt{-i} = e^{i(3\pi/4)} \,\! ,</math>
 
which, through application of Euler's formula to {{math|''x'' {{=}} 3&pi;/4}}, gives
 
:<math>  
\begin{align}
\pm \sqrt{-i} & = \cos(3\pi/4) + i\sin(3\pi/4) \\
  & = -\frac{1}{\pm \sqrt{2}} + i\frac{1}{\pm \sqrt{2}}\\
   & = \frac{-1 + i}{\pm \sqrt{2}}\\
  & = \pm \frac{\sqrt{2}}2 (i - 1).\\
\end{align}
</math>
 
Multiplying the square root of {{mvar|i}} by {{mvar|i}} also gives:
 
:<math>
\begin{align}
\pm \sqrt{-i} = (i)\cdot (\pm\frac{1}{\sqrt{2}}(1 + i)) \\
& = \pm\frac{1}{\sqrt{2}}(1i + i^{2})\\
& = \pm\frac{\sqrt{2}}{2}(i - 1)\\
\end{align}
</math>
 
=== Multiplication and division ===
Multiplying a complex number by {{mvar|i}} gives:
:<math>i\,(a + bi) = ai + bi^2 = -b + ai.</math>
(This is equivalent to a 90° counter-clockwise rotation of a vector about the origin in the complex plane.)
 
Dividing by {{mvar|i}} is equivalent to multiplying by the [[Multiplicative inverse|reciprocal]] of {{mvar|i}}:
:<math>\frac{1}{i} = \frac{1}{i} \cdot \frac{i}{i} = \frac{i}{i^2} = \frac{i}{-1} = -i.</math>
 
Using this identity to generalize division by {{mvar|i}} to all complex numbers gives:
:<math>\frac{a + bi}{i} = -i\,(a + bi) = -ai - bi^2 = b - ai. </math>
(This is equivalent to a 90° clockwise rotation of a vector about the origin in the complex plane.)
 
=== Powers ===
The powers of {{mvar|i}} repeat in a cycle expressible with the following pattern, where {{math|n}} is any integer:
 
:<math>i^{4n} = 1\,</math>
:<math>i^{4n+1} = i\,</math>
:<math>i^{4n+2} = -1\,</math>
:<math>i^{4n+3} = -i.\,</math>
 
This leads to the conclusion that
:<math>i^n = i^{n \bmod 4}\,</math>
 
where ''mod'' represents the [[modulo operation]].  Equivalently:
 
:<math>i^n = \cos(n\pi/2)+i\sin(n\pi/2)</math>
 
==== {{mvar|i}} raised to the power of {{mvar|i}} ====
Making use of [[Euler's formula]], {{math|''i''<sup>''i''</sup>}} is
:<math>i^i = \left( e^{i (\pi/2 + 2k \pi)} \right)^i = e^{i^2 (\pi/2 + 2k \pi)} = e^{- (\pi/2 + 2k \pi)}</math>
 
where <math>k \in \mathbb{Z}</math>, the set of [[integer]]s.
 
The [[principal value]] (for {{math|1=''k'' = 0}}) is {{math|''e''<sup>−π/2</sup>}} or approximately 0.207879576...<ref>"The Penguin Dictionary of Curious and Interesting Numbers" by David Wells, Page 26.</ref>
 
=== Factorial ===
The [[factorial]] of the imaginary unit {{mvar|i}} is most often given in terms of the [[gamma function]] evaluated at {{math|1 + ''i''}}:
:<math>i! = \Gamma(1+i) \approx 0.4980 - 0.1549i.</math>
 
Also,
:<math>|i!| = \sqrt{\pi \over \sinh \pi} </math><ref>"[http://www.wolframalpha.com/input/?i=abs(i!) abs(i!)]", ''WolframAlpha''.</ref>
 
=== Other operations ===
Many mathematical operations that can be carried out with real numbers can also be carried out with {{mvar|i}}, such as exponentiation, roots, logarithms, and trigonometric functions. However, it should be noted that all of the following functions are [[Complex function|complex]] [[multi-valued function]]s, and it should be clearly stated which branch of the [[Riemann surface]] the function is defined on in practice. Listed below are results for the most commonly chosen branch.
 
A number raised to the {{math|n''i''}} power is:
:<math> \!\ x^{ni} = \cos(\ln x^n) + i \sin(\ln x^n ).</math>
 
The {{math|n''i''<sup>th</sup>}} root of a number is:
:<math> \!\ \sqrt[ni]{x} = \cos(\ln \sqrt[n]{x} ) - i \sin(\ln \sqrt[n]{x} ).</math>
 
The [[imaginary-base logarithm]] of a number is:
:<math> \log_i(x) = {{2 \ln x } \over i\pi}.</math>
As with any [[complex logarithm]], the log base {{mvar|i}} is not uniquely defined.
 
The cosine of {{mvar|i}} is a real number:
:<math> \cos(i) = \cosh(1) = {{e + 1/e} \over 2} = {{e^2 + 1} \over 2e} \approx 1.54308064... .</math>
 
And the sine of {{mvar|i}} is purely imaginary:
:<math> \sin(i) = i\sinh(1) \,  = {{e - 1/e} \over 2} \, i = {{e^2 - 1} \over 2e} \, i \approx 1.17520119 \, i... .</math>
 
== Alternative notations ==
*In [[electrical engineering]] and related fields, the imaginary unit is often denoted by {{mvar|j}} to avoid confusion with [[current (electricity)|electrical current]] as a function of time, traditionally denoted by {{math|''i''(''t'')}} or just {{mvar|i}}. The [[Python (programming language)|Python programming language]] also uses {{mvar|j}} to mark the imaginary part of a complex number. [[MATLAB]] associates both {{mvar|i}} and {{mvar|j}} with the imaginary unit, although {{math|1''i''}} or {{math|1''j''}} is preferable, for speed and improved robustness.<ref>{{cite web | title= MATLAB Product Documentation| url=http://www.mathworks.com/help/techdoc/ref/i.html}}</ref>
*Some texts use the Greek letter [[iota]] ({{math|ι}}) for the imaginary unit, to avoid confusion, esp. with index and subscripts.
*Each of {{mvar|i}}, {{mvar|j}}, and {{mvar|k}} is an imaginary unit in the [[quaternion]]s. In [[bivector (complex)|bivector]]s and [[biquaternion]]s an additional imaginary unit {{mvar|h}} is used.
 
==Matrices==
When [[2 × 2 real matrices]] ''m'' are used for a source, and the number one (1) is identified with the [[identity matrix]], and minus one (&minus;1) with the negative of the identity matrix, then there are many solutions to ''m''<sup>2</sup> = &minus;1. In fact, there are many solutions to ''m''<sup>2</sup> = +1 and ''m''<sup>2</sup> = 0 also. Any such m can be taken as a basis vector, along with 1, to form a planar algebra.
 
==See also==
*[[Complex plane]]
*[[Imaginary number]]
*[[Multiplicity (mathematics)]]
*[[Root of unity]]
 
==Notes==
{{reflist|group=nb}}
 
== References ==
{{reflist|2}}
 
== Further reading ==
*{{cite book |first=Paul J. |last=Nahin |title=An Imaginary Tale: The Story of √−1 |location=Chichester |publisher=Princeton University Press |year=1998 |isbn=0-691-02795-1 }}
 
==External links==
*[http://mathdl.maa.org/mathDL/46/?pa=content&sa=viewDocument&nodeId=2245&bodyId=2439 Euler's work on Imaginary Roots of Polynomials] at [http://mathdl.maa.org/convergence/1/ Convergence]
 
[[Category:Complex numbers]]
[[Category:Algebraic numbers]]
[[Category:Mathematical constants]]

Revision as of 21:08, 2 March 2014

overwhelmed win over the soul of the house

Kind of near-blind reverence, like pious believers like.

when cumulative prestige to some level, but also in the hearts quietly sublimation, and no doubt, these alliance members fear for Xiao Yan, also in this カシオ 腕時計 スタンダード sublimation, the more カシオ電波ソーラー腕時計レディース fanatical, in this case, 'medicine' old, who are somewhat surprised, but it did not stop, people always need to have a faith, because this belief, they will have a high degree of cohesion, and Tianfu alliance among the ability to be this belief, apparently with only Xiao Yan

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'Come on

Tsing Yi with the girls in the juvenile behind.

'Come on, Ling old, say good-bye.'

Xiao Yan raised his head, looked before the mountain, he could feel the breath of a large number of forceful, where fast cohesion, and, in the カシオ腕時計 g-shock other two directions Mountains, also came bursts of spatial fluctuations, it カシオ ソーラー 腕時計 seems Yan Lei II strong family is dispatched

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looked back duo Xiao Yan Ling shadow is smile, muttered to himself.

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and under this acid itch

Gu fine blood into the body, Xiao Yan is covered with the skin immediately harnessed into a bright Jinmang, casio 時計 the vast energy in the body as カシオ 腕時計 チタン the storm swept in general open, had exhausted the meridians, almost in an instant, that is once again being gurgle vindictive, quickly filled.

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'But you want me to pan the door completely closed hand

Means, still useless. '

'is not it?' Han busy mouth slightly, her eyes are as cold as ice.

'But you want me to pan the door completely closed hand, non-stick Dan' medicine 'sell this one, is also OK! long as you promise me a proposal.' Xiao Yan suddenly took on the face a little casio 腕時計 データバンク sneer, looking across カシオ 腕時計 バンド the Korea idle.

four hundred and ninetieth chapters conflict (under)

four hundred and ninetieth chapters conflict

'proposal? What proposal?'

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