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| The '''van der Waals equation''' is an [[equation of state]] for a [[fluid]] composed of particles that have a non-zero volume and a pairwise attractive inter-particle [[force]] (such as the [[van der Waals force]]). It was derived in 1873 by [[Johannes Diderik van der Waals]], who received the Nobel prize in 1910 for "''his work on the equation of state for gases and liquids''". The equation is based on a modification of the [[ideal gas law]] and approximates the behavior of real fluids, taking into account the nonzero size of molecules and the attraction between them. | | The-green beans extract signifies of slimming down is 1 wise choice to do away with those additional fats. You can question why these beans are green. It's considering these beans haven't been roasted. The key reason why the standard coffee beans almost all of the folks are acquainted with are black in color is basically because these beans have already been roasted around 475 levels Fahrenheit. That procedure may in fact create the beans drop its fat-burning plus anti-oxidant aspect which it usually possess. For sure, the-green coffees have been inside its easiest state plus consequently might make persons shed weight usually.<br><br>It can be. However, due to the popularity of the [http://greencoffeeweightlossplan.com green coffee weight loss] extract, those businesses making quality extracts inside the U.S., containing at least 50% chlorogenic acid, can't discover the supply to meet the customer demand! So the statement enjoyed on various websites that they could run out of product, is not only a sales tactic. Running from supply arises quite frequently.<br><br>Always make certain the supplements you choose are produced in the USA or Europe. I may tell you which I have usually intended to buy a product, because the advertising found on the bottle was appealing, branded, plus had inside it what I sought or felt I required. However various brand manufacturers try to hide the truth that their treatments are prepared overseas inside Asia. So when you don't look at the box or bottle, carefully, you won't see that in print virtually too tiny to see... yes, there it happens to be... "Made inside China," where the standards for standard are frequently low or non-existent.<br><br>So far, all of this sounds a bit technical, and we absolutely simply like to learn when this stuff is any good. The answer is "Yes", this might be the real thing, plus I may tell you why. Many medical research have shown which Chlorogenic Acid slows fat intake from food usage, and also enhances fat metabolism. Don't look to brewed coffee because a source of Chlorogenic Acid, it is actually roasted proper out of the bean.<br><br>In addition to green coffee extract, you should probably commence consuming a fat loss supplement at some point. There are many kinds of weight loss supplement to choose from, however, the goal of taking these is to inspire a metabolism to function at a faster rate. It is much simpler to lose weight in the event you have this sort of metabolism. For more tricks and ideas regarding green coffee extract, click here.<br><br>Drive about town on a bright Spring day and look into open garages. In house after home, you'll see all kinds of pricey exercise equipment surrounded by boxes, pushed into a corner, covered with stuff, or out with all the garage sale goods.<br><br>Gourmet coffee roasters are available for buy with the click of a mouse. You are able to purchase these roasters online plus in many department plus specialty shops. What is fabulous regarding owning a roaster is the fact that we can roast only the beans you're going to use; consequently, you'll be drinking the most delicious and freshest coffee possible.<br><br>Hence, utilizing these coffee beans to a minimal in your daily diet will assist you face the challenge of clearing off those calories. Including the coffee bean remedy in the diet could merely become the break you want inside fat reduction. |
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| ==Equation==
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| [[Image:Waals2.svg|thumb|right|250px|The van der Waals isotherms: the model correctly predicts a mostly incompressible liquid phase, but the
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| oscillations in the [[phase transition]] zone do not fit experimental data.]]
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| The equation uses the following state variables: the [[pressure]] of the fluid ''p'', total volume of the container containing the fluid ''V'', number of moles ''n'', and [[temperature|absolute temperature]] of the system ''T''.
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| One form of the equation is
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| :<math>\left(p + \frac{a'}{v^2}\right)\left(v-b'\right) = kT</math>
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| where
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| :<math>v=V/N</math>
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| is the volume of the container shared between each particle (not the [[velocity]] of a particle),
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| :<math>N=N_A n</math>
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| is the total [[number of particles]], and
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| :<math>k=R/N_A</math>
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| is [[Boltzmann's constant]], given by the universal [[gas constant]] ''R'' and [[Avogadro's constant]] ''N<sub>A</sub>''.
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| Extra parameters are introduced: ''a'' is a measure for the attraction between the particles, and ''b'' is the average volume excluded from ''v'' by a particle.
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| The equation can be cast into the better known form | |
|
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| :<math>\left(p + \frac{n^2 a}{V^2}\right)\left(V-nb\right) = nRT</math>
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| where
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| :<math>a = N_A^2a' </math>
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| is a measure of the attraction between the particles,
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| :<math>b = N_A b' </math>
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| is the volume excluded by a mole of particles. | |
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| A careful distinction must be drawn between the volume ''available to'' a particle and the volume ''of'' a particle. In particular, in the first equation ''v'' refers to the empty space available per particle. That is, ''v'' is the volume ''V'' of the container divided by the total number ''nN<sub>A</sub>'' of particles. The parameter ''b'', on the other hand, is proportional to the proper volume of a single particle - the volume bounded by the [[atomic radius]]. This is the volume to be subtracted from ''v'' because of the space taken up by one particle. In van der Waals' original derivation, given below, ''b'' is four times the proper volume of the particle. Observe further that the pressure ''p'' goes to infinity when the container is completely filled with particles so that there is no void space left for the particles to move. This occurs when ''V'' = ''nb''.
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| ==Validity==
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| Above the [[critical temperature]] the van der Waals equation is an improvement of the ideal gas law, and for lower temperatures the equation is also qualitatively reasonable for the liquid state and the low-pressure gaseous state. However, the van der Waals model is not appropriate for rigorous quantitative calculations, remaining useful only for teaching and qualitative purposes.<ref>T. L. Hill, ''Statistical Thermodynamics'', Addison-Wesley, Reading (1960), p. 280</ref>
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| In the [[phase transition|first-order phase transition]] the range of (''P, V, T''), where the [[liquid]] [[phase (matter)|phase]] and the [[gas]] phase are in equilibrium, it does not exhibit the empirical fact that <var>p</var> is constant as a function of ''V'' for a given temperature: although this behavior can be easily inserted into the van der Waals model (see [[#Maxwell equal area rule|Maxwell's correction]] below), the result is no longer a simple analytical model, and others (such as those based on the [[principle of corresponding states]]) achieve a better fit with roughly the same work.
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| ==Derivation==
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| Most textbooks give two different [[Formal proof|derivations]]. One is the conventional derivation that goes back to van der Waals and the other is a statistical mechanics derivation. The latter has the major advantage that it makes explicit the intermolecular potential, which is neglected in the first derivation. The conventional van der Waals equation is a mechanical equation of state, which cannot be used to specify all thermodynamic functions, while the statistical mechanical derivation yields the partition function for the system, which does allow all thermodynamic functions to be specified, including the mechanical equation of state.
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| ===Conventional derivation===
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| Consider first one mole of gas which is composed of non-interacting point particles
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| that satisfy the [[ideal gas law]]
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| :<math> p = \frac{RT}{V_\mathrm{m}}.</math> | |
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| Next assume that all particles are hard spheres of the same finite radius ''r'' (the [[van der Waals radius]]). The effect of the finite volume of the particles is to decrease the available void space in which the particles are free to move. We must replace ''V'' by ''V'' − ''b'', where ''b'' is called the ''excluded volume''. The corrected equation becomes
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| :<math> p = \frac{RT}{V_\mathrm{m}-b}.</math>
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| The excluded volume <math>b</math> is not just equal to the volume occupied by the solid, finite-sized particles, but actually four times that volume. To see this, we must realize that a particle is surrounded by a sphere of radius ''r'' = 2''r'' (two times the original radius) that is forbidden for the centers of the other particles. If the distance between two particle centers were to be smaller than 2''r'', it would mean that the two particles penetrate each other, which, by definition, hard spheres are unable to do.
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| The excluded volume per particle (of average diameter ''d'' or radius ''r'') is
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| :<math>b' = 4\pi d^3/3 = 8\times (4\pi r^3/3) \quad \rightarrow \quad b'=4\times (4\pi r^3/3)</math>,
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| which was divided by 2 to prevent overcounting. So ''b′'' is four times the proper volume of the particle. It was a point of concern to Van der Waals that the factor four yields an upper bound; empirical values for ''b′'' are usually lower. Of course, molecules are not infinitely hard, as Van der Waals thought, and are often fairly soft.
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| Next, we introduce a pairwise attractive force between the particles. Van der Waals assumed that, not withstanding the existence of this force, the density of the fluid is homogeneous. Further he assumed that the range of the attractive force is so small that the great majority of the particles do not feel that the container is of finite size. Given the homogeneity of the fluid, the bulk of the particles do not experience a net force pulling them to the right or to the left. This is different for the particles in surface layers directly adjacent to the walls. They feel a net force from the bulk particles pulling them into the container, because this force is not compensated by particles on the side where the wall is (another assumption here is that there is no interaction between walls and particles, which is not true as can be seen from the phenomenon of droplet formation; most types of liquid show adhesion). This net force decreases the force exerted onto the wall by the particles in the surface layer. The net force on a surface particle, pulling it into the container, is proportional to the number density
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| :<math>C=N_\mathrm{A}/V_\mathrm{m}</math>.
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| The number of particles in the surface layers is, again by assuming homogeneity, also proportional to the density. In total, the force on the walls is decreased by a factor proportional to the square of the density, and the pressure (force per unit surface) is decreased by
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| :<math>a'C^2= a' \left(\frac{N_\mathrm{A}}{V_\mathrm{m}}\right)^2 = \frac{a}{V_\mathrm{m}^2} </math>,
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| so that
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| :<math> p = \frac{RT}{V_\mathrm{m}-b}-\frac{a}{V_\mathrm{m}^2} \Rightarrow
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| \left(p + \frac{a}{V_\mathrm{m}^2}\right)(V_\mathrm{m}-b) = RT.
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| </math>
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| Upon writing ''n'' for the number of moles and ''nV''<sub>m</sub> = ''V'', the equation obtains the second form given above,
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| :<math> \left(p + \frac{n^2 a}{V^2}\right)(V-nb) = nRT.
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| </math>
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| It is of some historical interest to point out that Van der Waals in his Nobel prize lecture gave credit to [[Laplace]] for the argument that pressure is reduced proportional to the square of the density.
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| <!--
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| This causes the average [[Helmholtz energy]] per particle to be reduced by an amount proportional to the fluid [[density]]. However, the pressure obeys the thermodynamic relation
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| :<math> p = - \left(\frac{\partial A^*}{\partial v}\right)_T </math>
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| where ''A*'' is the [[Helmholtz energy]] per particle. The attraction therefore reduces the pressure by an amount proportional to ''1/v²''. Denoting the constant of proportionality by ''a'', we obtain
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| :<math> p = \frac{kT}{v-b}-\frac{a}{v^2}</math>
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| which is the van der Waals equation.
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| -->
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| ===Statistical thermodynamics derivation===
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| The canonical [[partition function (statistical mechanics)|partition function]] ''Q'' of an ideal gas consisting of ''N = nN''<sub>A</sub> identical particles, is
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| :<math>
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| Q = \frac{q^N}{N!}\quad \hbox{with}\quad q = \frac{V}{\Lambda^3}
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| </math>
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| where <math>\Lambda</math> is the [[thermal de Broglie wavelength]],
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| :<math>
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| \Lambda = \sqrt{\frac{h^2}{2\pi m k T}}
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| </math>
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| with the usual definitions: ''h'' is [[Planck's constant]], ''m'' the mass of a particle, ''k'' [[Boltzmann's constant]] and ''T'' the absolute temperature. In an ideal gas ''q'' is the partition function of a single particle in a container of volume ''V''. In order to derive the van der Waals equation we assume now that each particle moves independently in an average potential field offered by the other particles. The averaging over the particles is easy because we will assume that the particle density of the van der Waals fluid is homogeneous.
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| The interaction between a pair of particles, which are hard spheres, is taken to be
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| :<math>
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| u(r) =
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| \begin{cases}
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| \infty &\hbox{when}\quad r < d, \\
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| -\epsilon \left(\frac{d}{r}\right)^6 & \hbox{when}\quad r \ge d,
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| \end{cases}
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| </math>
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| ''r'' is the distance between the centers of the spheres and ''d'' is the distance where the hard spheres touch each other (twice the van der Waals radius). The depth of the van der Waals well is <math>\epsilon</math>. | |
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| Because the particles are independent, the total partition function still factorizes,
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| :<math>Q = q^N/N!</math>,
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| but the intermolecular potential necessitates two modifications to ''q''. First, because of the finite size of the particles, not all of ''V'' is available, but only ''V − Nb''', where (just as in the conventional derivation above)
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| :<math> b' = 2\pi d^3/3 </math>.
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| Second, we insert a Boltzmann factor
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| exp['' - ϕ/2kT''] to take care of the average intermolecular potential. We divide here the potential by two because this interaction energy is shared between two particles. Thus
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| :<math>
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| q = \frac{(V-Nb') \, e^{-\phi/(2kT)}}{\Lambda^3}.
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| </math>
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| The total attraction felt by a single particle is
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| :<math>
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| \phi = \int_d^{\infty} u(r) \frac{N}{V} 4\pi r^2 dr ,
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| </math>
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| where we assumed that in a shell of thickness d''r'' there are ''N/V'' 4''π'' ''r''<sup>2</sup>''dr'' particles. This is a mean field approximation; the position of the particles is averaged. In reality the density close to the particle is different than far away as can be described by a pair correlation function. Furthermore it is neglected that the fluid is enclosed
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| between walls. Performing the integral we get
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| :<math>
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| \phi = -2 a' \frac{N}{V}\quad\hbox{with}\quad a' = \epsilon \frac{2\pi d^3}{3} =\epsilon b'.
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| </math>
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| Hence, we obtain,
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| :<math>
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| \ln Q = N \ln {(V-Nb')} + \frac{N^2 a'}{V kT} - N \ln {(\Lambda^3)} -\ln {N!}
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| </math>
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| From statistical thermodynamics we know that
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| :<math> p = kT \frac{\partial \ln Q}{\partial V}
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| </math>,
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| so that we only have to differentiate the terms containing V. We get
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| :<math>
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| p = \frac{NkT}{V-Nb'} - \frac{N^2 a'}{V^2} \Rightarrow
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| \left(p + \frac{N^2 a'}{V^2} \right)(V-Nb') = NkT \Rightarrow \left(p + \frac{n^2 a}{V^2} \right)(V-nb) = nRT.
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| </math>
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| == Other thermodynamic parameters ==
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| We reiterate that the extensive volume ''V'' is related to the volume per particle ''v=V/N'' where ''N = nN''<sub>A</sub> is the number of particles in the system.
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| The equation of state does not give us all the thermodynamic parameters of the system. We can take the equation for the [[Helmholtz energy]] ''A''
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| :<math>
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| A = -kT \ln Q.\,
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| </math> | |
| From the equation derived above for ln''Q'', we find
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| :<math>A(T,V,N)=-NkT\left[1+\ln\left(\frac{(V-Nb')T^{3/2}}{N\Phi}\right)\right]
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| -\frac{a' N^2}{V}.</math>
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| Where Φ is an undetermined constant, which may be taken from the [[Sackur-Tetrode equation]] for an ideal gas to be:
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| :<math>\Phi=T^{3/2}\Lambda^3=\left(\frac{h}{\sqrt{2\pi m k}}\right)^3</math>
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| This equation expresses ''A'' in terms of its [[Thermodynamic potential|natural variables]] ''V'' and ''T'' , and therefore gives us all thermodynamic information about the system. The mechanical equation of state was already derived above
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| :<math>p = -\left(\frac{\partial A}{\partial V}\right)_T
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| = \frac{NkT}{V-Nb'}-\frac{a' N^2}{V^2}.</math>
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| The entropy equation of state yields the [[entropy]] (''S'' )
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| :<math>S = -\left(\frac{\partial A}{\partial T}\right)_V
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| =Nk\left[ \ln\left(\frac{(V-Nb')T^{3/2}}{N\Phi}\right)+\frac{5}{2} \right]</math>
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| from which we can calculate the [[internal energy]]
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| :<math>U = A+TS = \frac{3}{2}\,NkT-\frac{a'N^2}{V}.</math>
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| Similar equations can be written for the other [[thermodynamic potential]] and the [[chemical potential]], but expressing any potential as a function of pressure ''p'' will require the solution of a third-order polynomial, which yields a complicated expression. Therefore, expressing the [[enthalpy]] and the [[Gibbs energy]] as functions of their natural variables will be complicated.
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| <!-- As I don't agree with U=A+TS and don't have patience to read thoroughly all related formulas, I offer another, more simple derivation of formula for internal energy:
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| : <math>dU = dQ-dA= TdS-PdV.</math>
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| : <math>\left(\frac{dU}{dV}\right)_{T=const}=T\frac{dS}{dV}-P=T\frac{dP}{dT}-P=T\frac{R}{\frac{V}{n}-b}-P=P+\frac{an^2}{V^2}-P=\frac{an^2}{V^2}</math>
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| :<math>\left(\frac{dU}{dT}\right)_{V=const}=\left(T\frac{dS}{dT}\right)_{V=const}=\left(\frac{dQ}{dT}\right)_{V=const}=\nu C_V</math>-->
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| ==Reduced form==
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| Although the material constants ''a'' and ''b'' in the usual form of the van der Waals equation differs for every single fluid considered, the equation can be recast into an invariant form applicable to ''all'' fluids.
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| Defining the following reduced variables (''f<sub>R</sub>'', ''f<sub>C</sub>'' are the reduced and [[critical variable]] versions of ''f'', respectively),
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| :<math>p_R=\frac{p}{p_C},\qquad
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| v_R=\frac{v}{v_C},\quad\hbox{and}\quad
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| T_R=\frac{T}{T_C}</math>,
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| where
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| :<math>
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| p_C=\frac{a'}{27b'^2}, \qquad \displaystyle{v_C=3b'},\quad\hbox{and}\quad kT_C=\frac{8a'}{27b'}
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| </math>
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| as shown by Salzman.<ref>W. R. Salzman, ''Critical Constants of the van der Waals Gas'',http://www.chem.arizona.edu/~salzmanr/480a/480ants/vdwcrit/vdwcrit.html</ref>
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| The first form of the van der Waals equation of state given above can be recast in the following reduced form: | |
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| :<math>\left(p_R + \frac{3}{v_R^2}\right)(v_R - 1/3) = (8/3) T_R</math>
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| This equation is ''invariant'' for all fluids; that is, the same reduced form equation of state applies, no matter what ''a'' and ''b'' may be for the particular fluid.
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| This invariance may also be understood in terms of the [[principle of corresponding states]]. If two fluids have the same reduced pressure, reduced volume, and reduced temperature, we say that their states are corresponding. The states of two fluids may be corresponding even if their measured pressure, volume, and temperature are very different. If the two fluids' states are corresponding, they exist in the same regime of the reduced form equation of state. Therefore, they will respond to changes in roughly the same way, even though their measurable physical characteristics may differ significantly.
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| ==Cubic equation==
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| The van der Waals equation is a cubic equation of state. That is we can write the equation into a cubic form of the volume. In the reduced formulation the cubic equation is:
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| :<math>{v_R^3}-\frac{1}{3}\left({1+\frac{8T_R}{p_R}}\right){v_R^2} +\frac{3}{p_R}v_R- \frac{1}{p_R}= 0</math>
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| At the critical temperature, where <math>T_R=p_R=1</math> we get as expected
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| :<math>{v_R^3}-3v_R^2 +3v_R- 1=\left(v_R -1\right)^3 = 0 \quad \Longleftrightarrow \quad v_R=1</math>
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| For ''T<sub>R</sub>'' < 1, there are 3 values for ''v<sub>R</sub>''.
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| For ''T<sub>R</sub>'' > 1, there is 1 real value for ''v<sub>R</sub>''.
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| <!--
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| ''Topics that this article should cover:''
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| ==Liquid-gas phase transition==
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| ==Fits to experimental data==
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| -->
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| == Application to compressible fluids ==
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| The equation is also usable as a [[PVT (physics)|PVT]] equation for [[compressible fluid]]s (e.g. [[polymers]]). In this case [[specific volume]] changes are small and it can be written in a simplified form:
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| :<math>(p+A)(V-B)=CT, \,</math>
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| where ''p'' is the [[pressure]], ''V'' is [[specific volume]], ''T'' is the [[temperature]] and ''A, B, C'' are parameters.
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| ==Maxwell equal area rule==
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| Below the critical temperature ''T<sub>R</sub>'' < 1 an isotherm of the van der Waals equation oscillates as shown. [[Image:MaxwellEqArea.svg|thumb|400px|Maxwell's rule eliminates the oscillating behavior of the [[isotherm (contour line)|isotherm]] in the [[phase transition]] zone by defining it as a certain [[Contour line#Barometric pressure|isobar]] in that zone. The above isotherm is for a reduced temperature of <math>T_R=0.9</math>. The Maxwell correction is at a vapor pressure of <math>P_V\approx 0.64700</math> between the reduced volume of the pure liquid <math>V_L\approx 0.60340</math> and the pure gas <math>V_G\approx 2.3488</math> at the vapor pressure.]] Along the red portion of the isotherm <math>\scriptstyle \left({{\partial P}/{\partial V}}\right)_{T,N}>0 </math> which is unstable; the van der Waals equation fails to describe real substances in this region because the equation always assumes that the fluid is uniform while between ''a'' and ''c'' on the isotherm it becomes more stable to be a coexistence of two different phases, a denser phase which we normally call ''liquid'' and a sparser phase which we normally call ''gas''. To fix this problem [[James Clerk Maxwell]] (1875) replaced the isotherm between ''a'' and ''c'' with a horizontal line positioned so that the areas of the two hatched regions are equal. The flat line portion of the isotherm now corresponds to liquid-vapor equilibrium. The portions ''a''–''d'' and ''c''–''e'' are interpreted as metastable states of super-heated liquid and super-cooled vapor respectively.<ref>Maxwell,J.C. ''The scientific papers of James Clerk Maxwell'' Dover 1965(c1890) p424</ref> The equal area rule can be expressed as:
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| :<math>P_V(V_G-V_L)=\int_{V_L}^{V_G}P\,dV</math>
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| where ''P<sub>V</sub>'' is the vapor pressure (flat portion of the curve), ''V<sub>L</sub>'' is the volume of the pure liquid phase at point ''a'' on the diagram, and ''V<sub>G</sub>'' is the volume of the pure gas phase at point ''c'' on the diagram. The sum of these two volumes will equal the total volume ''V''.
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| Maxwell justified the rule by saying that work done on the system in going from ''c'' to ''b'' should equal work released on going from ''a'' to ''b''. (The area on a ''PV'' diagram corresponds to mechanical work). That’s because the change in the free energy function ''A''(''T'',''V'') equals the work done during a reversible process, and the free energy function - being a state variable - should take on a unique value regardless of path. In particular, the value of ''A'' at point ''b'' should calculate the same regardless of whether the path came from left or right, or went straight across the horizontal isotherm or around the original van der Waals isotherm.
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| Maxwell’s argument is not totally convincing since it requires a reversible path through a region of thermodynamic instability. Nevertheless, more subtle arguments based on modern theories of phase equilibrium seem to confirm the Maxwell Equal Area construction and it remains a valid modification of the van der Waals equation of state.<ref>Cross, Michael ''First Order Phase Transitions'',http://www.pma.caltech.edu/~mcc/Ph127/b/Lecture3.pdf</ref>
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| The Maxwell equal area rule can also be derived from an assumption of equal [[chemical potential]] ''μ'' of coexisting liquid and vapour phases.<ref>A E Elhassan, R J B Craven, K M de Reuck, ''The Area Method for pure fluids and an analysis of the two-phase region'', Fluid Phase Equilibria 130 (1997) 167-187.</ref> On the isotherm shown in the above plot, points ''a'' and ''c'' are the only pair of points which fulfill the equilibrium condition of having equal pressure, temperature and chemical potential. It follows that systems with volumes intermediate between these two points will consist of a mixture of the pure liquid and gas with specific volumes equal to the pure liquid and gas phases at points ''a'' and ''c''.
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| The van der Waals equation may be solved for ''V<sub>G</sub>'' and ''V<sub>L</sub>'' as functions of the temperature and the vapor pressure ''P<sub>V</sub>''. Since:
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| :<math>P=\left(\frac{\partial A}{\partial V}\right)_{T,N}</math>
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| where ''A'' is the Helmholtz free energy, it follows that the equal area rule can be expressed as:
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| :<math>P_V=\frac{A(V_G,T,N)-A(V_L,T,N)}{V_G-V_L}</math>
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| Since the gas and liquid volumes are functions of ''P<sub>V</sub>'' and ''T'' only, this equation is then solved numerically to obtain ''P<sub>V</sub>'' as a function of temperature (and number of particles ''N''), which may then be used to determine the gas and liquid volumes.
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| == See also ==
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| * [[Equation of state]]
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| * [[Gas laws]]
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| * [[Ideal gas]]
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| * [[Inversion temperature]]
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| * [[Iteration]] To solve implicit equations like van der Waals
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| * [[Maxwell construction]]
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| * [[Real gas]]
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| * [[Theorem of corresponding states]]
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| * [[Van der Waals constants (data page)]]
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| ==References==
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| {{reflist}}
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| == External links ==
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| * [http://www.webqc.org/van_der_waals_gas_law.html Van der Waals Equation Solver]
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| * [http://faculty.wwu.edu/vawter/PhysicsNet/Topics/Thermal/vdWaalEquatOfState.html Some values of a and b in the 2nd equation]
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| {{Statistical mechanics topics}}
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| [[Category:Equations of state]]
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| [[Category:Gas laws]]
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| [[Category:Chemical engineering]]
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