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{{redirect6|Orthogonal projection|the technical drawing concept|Orthographic projection|a concrete discussion of orthogonal projections in finite-dimensional linear spaces |Vector projection}}
This is a strategy and as well as battle activation where for you must manage your hold tribe and also protect it. You have so as to build constructions which will provide protection for your individual soldiers along with each of our instruction. First really focus on your protection as well as the after its recently been quite taken treatment. You will need to move forward by means of the criminal offense arrange. As well as your Military facilities, you in addition need to keep in mind the way your group is certainly going. For instance, collecting articles as well as fostering your own tribe is the key to good improvements.<br><br>To appreciate coins and gems, creosote is the obtain the Clash amongst Clans hack equipment all by clicking on the earn button. Contingent towards the operating framework that you're utilizing, you will market the downloaded document whilst admin. Furnish one particular log in Id and choose the gadget. Shortly after this, you are to enter the quantity of diamond jewelry or coins that you should have and start off which the Clash of Clans compromise instrument.<br><br>Circumvent purchasing big title competitions near their launch dates. Waiting means that you're prone to achieve clash of clans cheats after using a patch or two has emerge to mend manifest holes and bugs may possibly impact your pleasure and so game play. Near keep an eye out there for titles from studios which are understood healthy patching and support.<br><br>There are no outcome in the least when you need to attacking other players on top of that losing, so just onset and savor it. Win or lose, yourself may lose the many troops you have associated with the attack since this company are only beneficial on one mission, nevertheless, a person will can steal more means with the enemy town than it cost which will make the troops. And you just produce more troops within you're barracks. It''s a great good idea to get them queued up until now you decide to attack and that means the customer are rebuilding your troops through the battle.<br><br>Attributes needed in-online game songs chance. If, nonetheless, you might exist annoyed by using the software soon after one hour approximately, don't be nervous to mute the telly or personal computer but play some audio of your very own. You will discover a far more exciting game playing experience performing this and therefore are a lot of unlikely to get the new frustration from actively actively.<br><br>Be mindful about letting your son or daughter play online video games, especially games with live sound. There can be [https://www.google.com/search?hl=en&gl=us&tbm=nws&q=foul+language foul language] in some channels, in addition a lot of bullying behavior. There may also be child predators in the chat rooms. Know what your child is going through and surveil these gossip times due to his or her own protection.<br><br>Here's more on [http://Prometeu.net/ clash Of Clans hacks] take a look at our own web site. Letrrrs try interpreting the  abstracts differently. Believe of it in offer of bulk with gemstone to skip 1 2nd. Skipping added a period of time expenses added money, and you get a more prominent deal. Think of it as a couple accretion discounts.
 
[[File:Orthogonal projection.svg|frame|right|The transformation ''P'' is the orthogonal projection onto the line ''m''.]]
In [[linear algebra]] and [[functional analysis]], a '''projection''' is a [[linear transformation]] ''P'' from a [[vector space]] to itself such that {{nowrap|1=''P''<sup>2</sup> = ''P''}}. That is, whenever ''P'' is applied twice to any value, it gives the same result as if it were applied once ([[Idempotence|idempotent]]). It leaves its image unchanged.<ref>Meyer, pp 386+387</ref>
Though abstract, this definition of "projection" formalizes and generalizes the idea of [[graphical projection]]. One can also consider the effect of a projection on a [[geometry|geometrical]] object by examining the effect of the projection on [[point (geometry)|point]]s in the object.
 
== Simple example ==
 
===Orthogonal projection===
For example, the function which maps the point (''x'', ''y'', ''z'') in three-dimensional space '''R'''<sup>3</sup> to the point (''x'', ''y'', 0) is a projection onto the ''x''–''y'' plane. This function is represented by the [[matrix (mathematics)|matrix]]
:<math> P = \begin{bmatrix} 1 & 0 & 0 \\  0 & 1 & 0 \\  0 & 0 & 0 \end{bmatrix}. </math>
 
The action of this matrix on an arbitrary vector is
:<math> P \begin{pmatrix} x \\ y \\ z \end{pmatrix} = \begin{pmatrix}
x \\ y \\  0 \end{pmatrix}.</math>
To see that ''P'' is indeed a projection, i.e., ''P'' = ''P''<sup>2</sup>, we compute:
<math> P^2 \begin{pmatrix} x \\ y \\ z \end{pmatrix} = P \begin{pmatrix} x \\ y \\ 0 \end{pmatrix} = \begin{pmatrix} x \\ y \\  0 \end{pmatrix} = P\begin{pmatrix} x \\ y \\ z \end{pmatrix}. </math>
 
===Oblique projection===
A simple example of a non-orthogonal (oblique) projection (for definition see below) is
:<math> P = \begin{bmatrix} 0 & 0  \\  \alpha & 1  \end{bmatrix}. </math>
 
Via [[matrix multiplication]], one sees that
 
:<math> P^2 = \begin{bmatrix} 0 & 0  \\  \alpha & 1  \end{bmatrix} \begin{bmatrix} 0 & 0  \\  \alpha & 1  \end{bmatrix}
= \begin{bmatrix} 0 & 0  \\  \alpha & 1  \end{bmatrix} = P. </math>
 
proving that ''P'' is indeed a projection.
 
The projection P is orthogonal if and only if <math> \alpha </math> = 0.
 
== Properties and classification ==
 
[[File:Oblique projection.svg|frame|right|The transformation ''T'' is the projection along ''k'' onto ''m''. The range of ''T'' is ''m'' and the null space is ''k''.]]
 
Let ''W'' be a finite dimensional vector space. Suppose the [[Linear subspace|subspace]]s ''U'' and ''V'' are the [[range of a matrix|range]] and [[null space|kernel]] of ''P'' respectively.
Then ''P'' has the following basic properties:
 
# ''P'' is the identity operator ''I'' on ''U'': <math>\forall x \in U: Px = x.</math>
# We have a [[direct sum of vector spaces|direct sum]] ''W'' = ''U'' ⊕ ''V''. Every vector ''x'' in ''W'' may be decomposed uniquely as ''x'' = ''u'' + ''v'' with <math>u = Px</math> and <math>v = x - Px = (I - P)x</math>, and where ''u'' is in ''U'' and ''v'' is in ''V''.
# ''P'' is [[idempotent]] and satisfies ''P''<sup>2</sup> = ''P''.
 
The range and kernel of a projection are ''complementary'', as are ''P'' and  ''Q'' = ''I''&nbsp;−&nbsp;''P''. The operator ''Q'' is also a projection and the range and kernel of P become the kernel and range of Q and vice-versa. We say ''P'' is a projection along ''V'' onto ''U'' (kernel/range) and  ''Q'' is a projection along ''U'' onto ''V''.
 
In infinite dimensional vector spaces
[[Spectrum (functional analysis)|spectrum]] of a projection is contained in {0, 1}, as <math> (\lambda I - P)^{-1}= \frac 1 \lambda I+\frac 1{\lambda(\lambda-1)} P</math>. Only 0 and 1 can be an [[eigenvalue]] of a projection. The corresponding eigenspaces are (respectively) the kernel and range of the projection.
Decomposition of a vector space into direct sums is not unique in general. Therefore, given a subspace ''V'', in general there are many projections whose range (or kernel) is ''V''.
 
If a projection is nontrivial it has [[minimal polynomial (linear algebra)|minimal polynomial]] <math>X^2-X=X(X- I)</math>, which factors into distinct roots, and thus ''P'' is [[diagonalizable]].
 
===Orthogonal projections===
 
When the vector space ''W'' has an [[inner product]] (is a [[Hilbert space]]) the concept of [[orthogonality]] can be used. An '''orthogonal projection''' is a projection for which the range ''U'' and the null space ''V'' are [[orthogonality|orthogonal subspaces]]. A projection is orthogonal if and only if it is [[self-adjoint operator|self-adjoint]]. Using the self-adjoint and idempotent properties of ''P'', for any ''x'' and ''y'' in ''W'' we have ''Px'' ∈ ''U'', ''y'' − ''Py'' ∈ ''V'', and
:<math> \langle Px, y-Py \rangle = \langle P^2x, y-Py \rangle = \langle Px, P(I-P)y \rangle = \langle Px, (P-P^2)y \rangle = 0 \,</math>
where <math>\langle\cdot,\cdot\rangle</math> is the [[inner product]] associated with ''W''. Therefore, ''Px'' and ''y'' − ''Py'' are orthogonal.<ref>Meyer, p. 433</ref>
For finite dimensional complex or real vector spaces, the [[standard inner product]] can be substituted for  <math>\langle\cdot,\cdot\rangle</math>.
 
A simple case occurs when the orthogonal projection is onto a line. If ''u'' is a [[unit vector]] on the line, then the projection is given by
:<math> P_u = u u^\mathrm{T}. \, </math>
This operator leaves ''u'' invariant, and it annihilates all vectors orthogonal to ''u'', proving that it is indeed the orthogonal projection onto the line containing ''u''.<ref>Meyer, p. 431</ref> A simple way to see this is to consider an arbitrary vector <math>x</math> as the sum of a component on the line (i.e. the projected vector we seek) and another perpendicular to it, <math>x=x_\parallel+x_\perp</math>. Applying projection, we get <math>P_ux=u u^\mathrm{T} x_\parallel+u u^\mathrm{T} x_\perp=u|x_\parallel|+u0=x_\parallel</math> by the properties of the [[dot product]] of parallel and perpendicular vectors.
 
This formula can be generalized to orthogonal projections on a subspace of arbitrary dimension. Let ''u''<sub>1</sub>, ..., ''u''<sub>''k''</sub> be an [[orthonormal basis]] of the subspace ''U'', and let ''A'' denote the ''n''-by-''k'' matrix whose columns are ''u''<sub>1</sub>, ..., ''u''<sub>''k''</sub>. Then the projection is given by
:<math> P_A = A A^\mathrm{T} \, </math><ref>Meyer, equation (5.13.4)</ref>
which can be rewritten as
<math> P_A = \sum_i \langle u_i,\cdot\rangle u_i.</math>
 
The matrix ''A''<sup>T</sup> is the [[partial isometry]] that vanishes on the orthogonal complement of ''U'' and ''A'' is the isometry that embeds ''U'' into the underlying vector space. The range of ''P<sub>A</sub>'' is therefore the ''final space'' of ''A''. It is also clear that ''A''<sup>T</sup>''A'' is the identity operator on ''U''.
 
The orthonormality condition can also be dropped. If ''u''<sub>1</sub>, ..., ''u''<sub>''k''</sub> is a (not necessarily orthonormal) basis, and ''A'' is the matrix with these vectors as columns, then the projection is
:<math>P_A = A (A^\mathrm{T} A)^{-1} A^\mathrm{T}. </math><ref>Meyer, equation (5.13.3)</ref>
 
The matrix ''A'' still embeds ''U'' into the underlying vector space but is no longer an isometry in general. The matrix (''A''<sup>T</sup>''A'')<sup>−1</sup> is a "normalizing factor" that recovers the norm. For example, the rank-1 operator ''uu''<sup>T</sup> is not a projection if ||''u''|| ≠ 1. After dividing by ''u''<sup>T</sup>''u'' = ||''u''||<sup>2</sup>, we obtain the projection ''u''(''u''<sup>T</sup>''u'')<sup>−1</sup>''u''<sup>T</sup> onto the subspace spanned by ''u''.
 
When the range space of the projection is generated by a [[Frame of a vector space|frame]] (i.e. the number of generators is greater than its dimension), the formula for the projection takes the form
<math>P_A = A (A^\mathrm{T} A)^+ A^\mathrm{T}</math>. Here <math>A^+</math> stands for the [[Moore–Penrose pseudoinverse]]. This is just one of many ways to construct the projection operator.
 
If a matrix <math>\, [A \ B]</math> is non-singular and ''A''<sup>T</sup> ''B'' = 0 (i.e., ''B'' is the  [[null space]] matrix of ''A''),<ref>see also [[Linear_least_squares_(mathematics)#Properties_of_the_least-squares_estimators|Properties of the least-squares estimators in Linear least squares]]</ref> the following holds:
:<math>I = [A \ B][A \ B]^{-1} \begin{bmatrix}A^\mathrm{T}\\B^\mathrm{T}\end{bmatrix}^{-1}\begin{bmatrix}A^\mathrm{T}\\B^\mathrm{T}\end{bmatrix} = [A \ B](\begin{bmatrix}A^\mathrm{T}\\B^\mathrm{T}\end{bmatrix}[A \ B])^{-1} \begin{bmatrix}A^\mathrm{T}\\B^\mathrm{T}\end{bmatrix}
= [A \ B] \begin{bmatrix}A^\mathrm{T}A & O \\ O & B^\mathrm{T}B\end{bmatrix}^{-1} \begin{bmatrix}A^\mathrm{T}\\B^\mathrm{T}\end{bmatrix}</math>
:<math>= A (A^\mathrm{T} A)^{-1} A^\mathrm{T} + B (B^\mathrm{T} B)^{-1} B^\mathrm{T}. </math>
 
If the orthogonal condition is enhanced to ''A''<sup>T</sup> ''W'' ''B'' = ''A''<sup>T</sup> ''W''<sup>T</sup> ''B'' = 0 with ''W'' being non-singular<!-- and symmetric-->, the following holds:
:<math>I = \begin{bmatrix}A & B\end{bmatrix} \begin{bmatrix}(A^\mathrm{T} W A)^{-1} A^\mathrm{T} \\ (B^\mathrm{T} W B)^{-1} B^\mathrm{T} \end{bmatrix} W .</math>
 
All these formulas also hold for complex inner product spaces, provided that the [[conjugate transpose]] is used instead of the transpose.
 
=== Oblique projections ===
 
The term ''oblique projections'' is sometimes used to refer to non-orthogonal projections. These projections are also used to represent spatial figures in two-dimensional drawings (see [[oblique projection]]), though not as frequently as orthogonal projections.
 
Oblique projections are defined by their range and null space. A formula for the matrix representing the projection with a given range and null space can be found as follows. Let the vectors ''u''<sub>1</sub>, ..., ''u''<sub>''k''</sub> form a basis for the range of the projection, and assemble these vectors in the ''n''-by-''k'' matrix ''A''. The range and the null space are complementary spaces, so the null space has dimension ''n''&nbsp;−&nbsp;''k''. It follows that the [[orthogonal complement]] of the null space has dimension ''k''. Let ''v''<sub>1</sub>, ..., ''v''<sub>''k''</sub> form a basis for the orthogonal complement of the null space of the projection, and assemble these vectors in the matrix ''B''. Then the projection is defined by
:<math> P = A (B^\mathrm{T} A)^{-1} B^\mathrm{T}. </math>
This expression generalizes the formula for orthogonal projections given above.<ref>Meyer, equation (7.10.39)</ref>
 
== Canonical forms ==
 
Any projection {{nowrap|''P'' {{=}} ''P''<sup>2</sup>}} on a vector space of dimension ''d'' over a field is a [[diagonalizable matrix]], since its [[minimal polynomial (linear algebra)|minimal polynomial]] is ''x''<sup>2</sup>&nbsp;&minus;&nbsp;''x'', which splits into distinct linear factors.  Thus there exists a basis in which ''P'' has the form
:<math>P = I_r\oplus 0_{d-r}</math>
where ''r'' is the rank of ''P''. Here ''I''<sub>''r''</sub> is the identity matrix of size ''r'', and 0<sub>''d''&minus;''r''</sub> is the zero matrix of size ''d''&nbsp;&minus;&nbsp;''r''. If the vector space is complex and equipped with an [[inner product]], then there is an ''orthonormal'' basis in which the matrix of ''P'' is<ref>{{ cite journal|last=Doković|first= D. Ž. |title=Unitary similarity of projectors|journal=Aequationes Mathematicae| volume =42| issue= 1| pages= 220–224|date=August 1991|url=http://www.springerlink.com/content/w3r57501226447m6/|doi=10.1007/BF01818492}}</ref>
 
:<math>P = \begin{bmatrix}1&\sigma_1 \\ 0&0\end{bmatrix} \oplus \cdots \oplus \begin{bmatrix}1&\sigma_k \\ 0&0\end{bmatrix} \oplus I_m \oplus 0_s</math> .
 
where {{nowrap|&sigma;<sub>1</sub> &ge; &sigma;<sub>2</sub> &ge; ... &ge; &sigma;<sub>''k''</sub> &gt; 0}}.  The integers ''k'', ''s'', ''m'' and the real numbers <math>\sigma_i</math> are uniquely determined.  Note that {{nowrap|2''k'' + ''s'' + ''m'' {{=}} ''d''}}.  The factor {{nowrap|''I''<sub>''m''</sub> ⊕ 0<sub>''s''</sub>}} corresponds to the maximal invariant subspace on which ''P'' acts as an ''orthogonal'' projection (so that ''P'' itself is orthogonal if and only if ''k''&nbsp;=&nbsp;0) and the &sigma;<sub>''i''</sub>-blocks correspond to the ''oblique'' components.
 
== Projections on normed vector spaces ==
 
When the underlying vector space ''X'' is a (not necessarily finite-dimensional) [[normed vector space]], analytic questions, irrelevant in the finite-dimensional case, need to be considered. Assume now ''X'' is a [[Banach space]].
 
Many of the algebraic notions discussed above survive the passage to this context. A given direct sum decomposition of ''X'' into complementary subspaces still specifies a projection, and vice versa. If ''X'' is the direct sum ''X'' = ''U'' ⊕ ''V'', then the operator defined by ''P''(''u'' + ''v'') = ''u'' is still a projection with range ''U'' and kernel ''V''. It is also clear that ''P''<sup>2</sup> = ''P''. Conversely, if ''P'' is projection on ''X'', i.e. ''P''<sup>2</sup> = ''P'', then it is easily verified that (''I'' − ''P'')<sup>2</sup> = (''I'' − ''P''). In other words, (''I'' − ''P'') is also a projection. The relation ''I'' = ''P'' + (''I'' − ''P'') implies ''X'' is the direct sum Ran(''P'') ⊕ Ran(''I'' − ''P'').
 
However, in contrast to the finite-dimensional case, projections need not be [[bounded linear operator|continuous]] in general. If a subspace ''U'' of ''X'' is not closed in the norm topology, then projection onto ''U'' is not continuous. In other words, the range of a continuous projection ''P'' must be a closed subspace. Furthermore, the kernel of a continuous projection (in fact, a continuous linear operator in general) is closed. Thus a ''continuous'' projection ''P'' gives a decomposition of ''X'' into two complementary ''closed'' subspaces: ''X'' = Ran(''P'') ⊕ Ker(''P'') = Ker(''I'' − ''P'') ⊕ Ker(''P'').
 
The converse holds also, with an additional assumption. Suppose ''U'' is a closed subspace of ''X''. ''If'' there exists a closed subspace ''V'' such that ''X'' = ''U'' ⊕ ''V'', then the projection ''P'' with range ''U'' and kernel ''V'' is continuous. This follows from the [[closed graph theorem]]. Suppose ''x<sub>n</sub>'' → ''x'' and ''Px<sub>n</sub>'' → ''y''. One needs to show ''Px'' = ''y''. Since ''U'' is closed and {''Px<sub>n</sub>''} ⊂ ''U'', ''y'' lies in ''U'', i.e. ''Py'' = ''y''. Also, ''x<sub>n</sub>'' − ''Px<sub>n</sub>'' = (''I'' − ''P'')''x<sub>n</sub>'' &rarr; ''x'' − ''y''. Because ''V'' is closed and {(''I'' − ''P'')''x<sub>n</sub>''} ⊂ ''V'', we have ''x'' − ''y'' ∈ ''V'', i.e. ''P''(''x'' − ''y'') = ''Px'' − ''Py'' = ''Px'' − ''y'' = 0, which proves the claim.
 
The above argument makes use of the assumption that both ''U'' and ''V'' are closed. In general, given a closed subspace ''U'', there need not exist a complementary closed subspace ''V'', although for [[Hilbert space]]s this can always be done by taking the [[orthogonal complement]]. For Banach spaces, a one-dimensional subspace always has a closed complementary subspace. This is an immediate consequence of [[Hahn–Banach theorem]]. Let ''U'' be the linear span of ''u''. By Hahn–Banach, there exists a bounded linear functional ''Φ'' such that ''φ''(''u'') = 1. The operator ''P''(''x'') = ''&phi;''(''x'')''u'' satisfies ''P''<sup>2</sup> = ''P'', i.e. it is a projection. Boundedness of ''&phi;'' implies continuity of ''P'' and therefore Ker(''P'') = Ran(''I'' − ''P'') is a closed complementary subspace of ''U''.
 
However, every continuous projection on a Banach space is an [[open mapping]], by the [[Open mapping theorem (functional analysis)|open mapping theorem]].
 
== Applications and further considerations ==
 
Projections (orthogonal and otherwise) play a major role in [[algorithm]]s for certain linear algebra problems:
* [[QR decomposition]] (see [[Householder transformation]] and [[Gram–Schmidt decomposition]]);
* [[Singular value decomposition]]
* Reduction to [[Hessenberg matrix|Hessenberg]] form (the first step in many [[eigenvalue algorithm]]s).
* [[Linear regression]]
 
As stated above, projections are a special case of idempotents. Analytically, orthogonal projections are non-commutative generalizations of [[characteristic polynomial|characteristic functions]]. Idempotents are used in classifying, for instance, [[semisimple algebra]]s, while measure theory begins with considering characteristic functions of measurable sets. Therefore, as one can imagine, projections are very often encountered in the context [[operator algebra]]s. In particular, a [[von Neumann algebra]] is generated by its complete [[lattice (order)|lattice]] of projections.
 
== Generalizations ==
More generally, given a map between normed vector spaces <math>T\colon V \to W,</math> one can analogously ask for this map to be an isometry on the orthogonal complement of the kernel: that <math>(\ker T)^\perp \to W</math> be an isometry; in particular it must be onto. The case of an orthogonal projection is when ''W'' is a subspace of ''V.'' In [[Riemannian geometry]], this is used in the definition of a [[Riemannian submersion]].
 
==See also==
*[[Centering matrix]], which is an example of a projection matrix.
*[[Orthogonalization]]
*[[Invariant subspace]]
*[[Trace (linear algebra)#Properties|Properties of trace]]
*[[Dykstra's projection algorithm]] to compute the projection onto an intersection of sets
 
==Notes==
{{reflist}}
 
==References==
 
* {{cite book|first1=N. |last1=Dunford |first2= J. T.|title=Linear Operators, Part I: General Theory|publisher= Interscience|year= 1958|last2=Schwartz}}
* {{cite book|first=Carl D.|last= Meyer|url=http://www.matrixanalysis.com/ |title=Matrix Analysis and Applied Linear Algebra|publisher=Society for Industrial and Applied Mathematics|year= 2000| isbn= 978-0-89871-454-8}}
 
==External links==
* [http://www.youtube.com/watch?v=osh80YCg_GM&feature=PlayList&p=38823D6325151CED&index=16 MIT Linear Algebra Lecture on Projection Matrices] at Google Video, from MIT OpenCourseWare
* [http://www.mtsu.edu/~csjudy/planeview3D/tutorial.html Planar Geometric Projections Tutorial] - a simple-to-follow tutorial explaining the different types of planar geometric projections.
 
{{linear algebra}}
 
[[Category:Functional analysis]]
[[Category:Linear algebra]]
[[Category:Linear operators]]
 
[[de:Projektion (Mathematik)]]
[[fi:Projektio (lineaarialgebra)]]

Latest revision as of 21:52, 26 December 2014

This is a strategy and as well as battle activation where for you must manage your hold tribe and also protect it. You have so as to build constructions which will provide protection for your individual soldiers along with each of our instruction. First really focus on your protection as well as the after its recently been quite taken treatment. You will need to move forward by means of the criminal offense arrange. As well as your Military facilities, you in addition need to keep in mind the way your group is certainly going. For instance, collecting articles as well as fostering your own tribe is the key to good improvements.

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