Accidental release source terms

From formulasearchengine
Revision as of 00:28, 12 February 2013 by en>Mbeychok (Don't know how or why two of the sub-section headers were italicized. Undid those italics.)
Jump to navigation Jump to search

In mathematics, a quotient category is a category obtained from another one by identifying sets of morphisms. The notion is similar to that of a quotient group or quotient space, but in the categorical setting.

Definition

Let C be a category. A congruence relation R on C is given by: for each pair of objects X, Y in C, an equivalence relation RX,Y on Hom(X,Y), such that the equivalence relations respect composition of morphisms. That is, if

f1,f2:XY

are related in Hom(X, Y) and

g1,g2:YZ

are related in Hom(Y, Z) then g1f1, g1f2, g2f1 and g2f2 are related in Hom(X, Z).

Given a congruence relation R on C we can define the quotient category C/R as the category whose objects are those of C and whose morphisms are equivalence classes of morphisms in C. That is,

Hom𝒞/(X,Y)=Hom𝒞(X,Y)/RX,Y.

Composition of morphisms in C/R is well-defined since R is a congruence relation.

There is also a notion of taking the quotient of an Abelian category A by a Serre subcategory B. This is done as follows. The objects of A/B are the objects of A. Given two objects X and Y of A, we define the set of morphisms from X to Y in A/B to be limHomA(X,Y/Y) where the limit is over subobjects XX and YY such that X/X,YB. Then A/B is an Abelian category, and there is a canonical functor Q:AA/B. This Abelian quotient satisfies the universal property that if C is any other Abelian category, and F:AC is an exact functor such that F(b) is a zero object of C for each bB, then there is a unique exact functor F:A/BC such that F=FQ. (See [Gabriel].)

Properties

There is a natural quotient functor from C to C/R which sends each morphism to its equivalence class. This functor is bijective on objects and surjective on Hom-sets (i.e. it is a full functor).

Examples

See also

References