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In [[number theory]], '''de Polignac's formula''', named after [[Alphonse de Polignac]], gives the [[prime decomposition]] of the [[factorial]] ''n''<nowiki>!</nowiki>, where ''n''&nbsp;≥&nbsp;1 is an [[integer]]. [[Leonard Eugene Dickson|L. E. Dickson]] attributes the formula to [[Adrien-Marie Legendre|Legendre]].<ref>[[Leonard Eugene Dickson]], ''[[History of the Theory of Numbers]]'', Volume 1, Carnegie Institution of Washington, 1919, page 263.</ref>
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==The formula==
Let ''n''&nbsp;≥&nbsp;1 be an integerThe prime decomposition of ''n''! is given by
 
:<math>n! = \prod_{\text{prime }p\le n} p^{s_p(n)}, </math>
 
where
 
:<math>s_p(n) = \sum_{j = 1}^\infty \left\lfloor\frac{n}{p^j}\right\rfloor, </math>
 
and the brackets represent the [[floor function]]. Note that the former product can equally well be taken only over primes less than or equal to ''n'', and the latter sum can equally well be taken for ''j'' ranging from ''1'' to log<sub>''p''</sub>(''n''), i.e :
 
:<math>s_p(n) = \sum_{j = 1}^{\lfloor \log_p(n) \rfloor} \left\lfloor\frac{n}{p^j}\right\rfloor </math>
 
Note that, for any [[real number]] ''x'', and any integer ''n'', we have:
 
:<math>\left\lfloor\frac{x}{n}\right\rfloor = \left\lfloor\frac{\lfloor x \rfloor}{n}\right\rfloor</math>
 
which allows one to more easily compute the terms ''s''<sub>''p''</sub>(''n'').
 
The small disadvantage of the De Polignac's formula is that '''we need to know all the primes up to ''n'''''.
In fact,
:<math>\displaystyle n! =  \prod_{i=1}^{\pi(n)} p_{i}^{s_{p_{i}}(n)} =  \prod_{i=1}^{\pi(n)} p_i^{ \sum_{j = 1}^{\lfloor \log_{p_i}(n) \rfloor} \left\lfloor\frac{n}{{p_i}^j}\right\rfloor  } </math>
 
where <math>\pi(n)</math> is a [[prime-counting function]] counting the number of prime numbers less than or equal to ''n''
 
== Notes and references ==
{{reflist}}
 
{{DEFAULTSORT:De Polignac's Formula}}
[[Category:Number theory]]
[[Category:Factorial and binomial topics]]

Revision as of 10:25, 1 March 2014

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