List of common physics notations

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In mathematics, in the realm of group theory, a group is algebraically closed if any finite set of equations and inequations that "make sense" in already have a solution in . This idea will be made precise later in the article.

Informal discussion

Suppose we wished to find an element of a group satisfying the conditions (equations and inequations):

Then it is easy to see that this is impossible because the first two equations imply . In this case we say the set of conditions are inconsistent with . (In fact this set of conditions are inconsistent with any group whatsoever.)

Now suppose is the group with the multiplication table:

Then the conditions:

have a solution in , namely .

However the conditions:

Do not have a solution in , as can easily be checked.

However if we extend the group to the group with multiplication table:

Then the conditions have two solutions, namely and .

Thus there are three possibilities regarding such conditions:

It is reasonable to ask whether there are any groups such that whenever a set of conditions like these have a solution at all, they have a solution in itself? The answer turns out to be "yes", and we call such groups algebraically closed groups.

Formal definition of an algebraically closed group

We first need some preliminary ideas.

If is a group and is the free group on countably many generators, then by a finite set of equations and inequations with coefficients in we mean a pair of subsets and of the free product of and .

This formalizes the notion of a set of equations and inequations consisting of variables and elements of . The set represents equations like:

The set represents inequations like

By a solution in to this finite set of equations and inequations, we mean a homomorphism , such that for all and for all . Where is the unique homomorphism that equals on and is the identity on .

This formalizes the idea of substituting elements of for the variables to get true identities and inidentities. In the example the substitutions and yield:

We say the finite set of equations and inequations is consistent with if we can solve them in a "bigger" group . More formally:

The equations and inequations are consistent with if there is a group and an embedding such that the finite set of equations and inequations and has a solution in . Where is the unique homomorphism that equals on and is the identity on .

Now we formally define the group to be algebraically closed if every finite set of equations and inequations that has coefficients in and is consistent with has a solution in .

Known Results

It is difficult to give concrete examples of algebraically closed groups as the following results indicate:

The proofs of these results are, in general very complex. However a sketch of the proof that a countable group can be embedded in an algebraically closed group follows.

First we embed in a countable group with the property that every finite set of equations with coefficients in that is consistent in has a solution in as follows:

There are only countably many finite sets of equations and inequations with coefficients in . Fix an enumeration of them. Define groups inductively by:

Now let:

Now iterate this construction to get a sequence of groups and let:

Then is a countable group containing . It is algebraically closed because any finite set of equations and inequations that is consistent with must have coefficients in some and so must have a solution in .

References

  • A. Macintyre: On algebraically closed groups, ann. of Math, 96, 53-97 (1972)
  • B.H. Neumann: A note on algebraically closed groups. J. London Math. Soc. 27, 227-242 (1952)
  • B.H. Neumann: The isomorphism problem for algebraically closed groups. In: Word Problems, pp 553–562. Amsterdam: North-Holland 1973
  • W.R. Scott: Algebraically closed groups. Proc. Amer. Math. Soc. 2, 118-121 (1951)