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[[File:Pell's equation.svg|thumb|360px|Pell's equation for ''n'' = 2 and six of its integer solutions]]
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'''Pell's equation''' is any [[Diophantine equation]] of the form
 
:<math>x^2-ny^2=1\,</math>
 
where ''n'' is a given [[Square number|nonsquare]] [[integer]] and integer solutions are sought for ''x'' and ''y''. In [[Cartesian coordinates]], the equation has the form of a [[hyperbola]]; solutions occur wherever the curve passes through a point whose ''x'' and ''y'' coordinates are both integers, such as the [[Triviality (mathematics)|trivial solution]] with ''x''&nbsp;=&nbsp;1 and ''y''&nbsp;=&nbsp;0. [[Joseph Louis Lagrange]] proved that, as long as ''n'' is not a [[square number|perfect square]], Pell's equation has infinitely many distinct integer solutions. These solutions may be used to accurately [[Diophantine approximation|approximate]] the [[square root]] of&nbsp;''n'' by [[rational number]]s of the form&nbsp;''x/y''.
 
The name of Pell's equation arose from [[Leonhard Euler]]'s [[Stigler's law of eponymy|mistakenly attributing]] its study to [[John Pell]]. Euler was aware of the work of [[Lord Brouncker]], the first European mathematician to find a general solution of the equation, but apparently confused Brouncker with Pell. This equation was first studied extensively in [[Indian mathematics|ancient India]], starting with [[Brahmagupta]], who developed the [[chakravala method|''chakravala'' method]] to solve Pell's equation and other quadratic indeterminate equations in his [[Brahmasphutasiddhanta|''Brahma Sphuta Siddhanta'']] in 628, about a thousand years before Pell's time. His ''Brahma Sphuta Siddhanta'' was translated into [[Arabic]] in 773 and was subsequently translated into [[Latin]] in 1126. [[Bhaskara II]] in the 12th century and [[Narayana Pandit]] in the 14th century both found general solutions to Pell's equation and other quadratic indeterminate equations. Solutions to specific examples of the Pell equation, such as the [[Pell number]]s arising from the equation with ''n'' = 2, had been known for much longer, since the time of [[Pythagoras]] in [[Greek mathematics|Greece]] and to a similar date in India.
 
For a more detailed discussion of much of the material here, see Lenstra (2002) and Barbeau (2003).
 
==History==
As early as 400 BC in India and Greece, mathematicians studied the numbers arising from the ''n''&nbsp;=&nbsp;2 case of Pell's equation,
 
:<math> x^2 - 2y^2=1 </math>
and from the closely related equation
:<math> x^2 - 2y^2 = -1 </math>
 
because of the connection of these equations to the square root of two.<ref name="knorr76"/> Indeed, if ''x'' and ''y'' are positive integers satisfying this equation, then ''x''/''y'' is an approximation of √2. The numbers ''x'' and ''y'' appearing in these approximations, called [[Pell number|side and diameter numbers]], were known to the [[Pythagoreans]], and [[Proclus]] observed that in the opposite direction these numbers obeyed one of these two equations.<ref name="knorr76"/> Similarly, [[Baudhayana]] discovered that ''x'' = 17, ''y'' = 12 and ''x'' = 577, ''y'' = 408 are two solutions to the Pell equation, and that 17/12 and 577/408 are very close approximations to the square root of two.
 
Later, Archimedes approximated the square root of 3 by the rational number 1351/780. Although he did not explain his methods, this approximation may be obtained in the same way, as a solution to Pell's equation.<ref name="knorr76">{{citation
  | last = Knorr | first = Wilbur R. | authorlink = Wilbur Knorr
| issue = 2
| journal = Archive for History of Exact Sciences
| mr = 0497462
| pages = 115–140
| title = Archimedes and the measurement of the circle: a new interpretation
| volume = 15
| year = 1976}}.</ref>
 
Around AD 250, [[Diophantus]] considered the equation
 
:<math> a^2 x^2+c=y^2,</math>
where ''a'' and ''c'' are fixed numbers and ''x'' and ''y'' are the variables to be solved for.
This equation is different in form from Pell's equation but equivalent to it.
Diophantus solved the equation for (''a'',''c'') equal to (1,1), (1,&minus;1), (1,12), and (3,9). [[Al-Karaji]], a 10th-century Persian mathematician, worked on similar problems to Diophantus.
 
In Indian mathematics, [[Brahmagupta]] discovered that
:<math>(x_1^2 - Ny_1^2)(x_2^2 - Ny_2^2) = (x_1x_2 + Ny_1y_2)^2 - N(x_1y_2 + x_2y_1)^2 = (x_1x_2 - Ny_1y_2)^2 - N(x_1y_2 - x_2y_1)^2</math>
(see [[Brahmagupta's identity]]). Using this, he was able to "compose" triples <math>(x_1, y_1, k_1)</math> and <math>(x_2, y_2, k_2)</math> that were solutions of <math>x^2 - Ny^2 = k</math>, to generate the new triple
:<math>(x_1x_2 + Ny_1y_2 \,,\, x_1y_2 + x_2y_1 \,,\, k_1k_2)</math> and <math>(x_1x_2 - Ny_1y_2 \,,\, x_1y_2 - x_2y_1 \,,\, k_1k_2).</math>
Not only did this give a way to generate infinitely many solutions to <math>x^2 - Ny^2 = 1</math> starting with one solution, but also, by dividing such a composition by <math>k_1k_2</math>, integer or "nearly integer" solutions could often be obtained. For instance, for <math>N=92</math>, Brahmagupta composed the triple <math>(10, 1, 8)</math> (since <math>10^2 - 92(1^2) = 8</math>) with itself to get the new triple <math>(192, 20, 64)</math>. Dividing throughout by 64 gave the triple <math>(24, 5/2, 1)</math>, which when composed with itself gave the desired integer solution <math>(1151, 120, 1)</math>. Brahmagupta solved many Pell equations with this method; in particular he showed how to obtain solutions starting from an integer solution of <math>x^2 - Ny^2 = k</math> for ''k''&nbsp;=&nbsp;±1, ±2, or ±4.<ref name=stillwell>{{citation | year=2002 | title = Mathematics and its history | authorlink1=John Stillwell | author1=John Stillwell | edition=2nd | publisher=Springer | isbn=978-0-387-95336-6 | pages=72–76 | url=http://books.google.com/?id=WNjRrqTm62QC&pg=PA72}}</ref>
 
The first general method for solving the Pell equation (for all ''N'') was given by [[Bhaskara II]] in 1150, extending the methods of Brahmagupta. Called the [[chakravala method|chakravala (cyclic) method]], it starts by composing any triple <math>(a,b,k)</math> (that is, one which satisfies <math>a^2 - Nb^2 = k</math>) with the trivial triple <math>(m, 1, m^2 - N)</math> to get the triple <math>(am + Nb, a+bm, k(m^2-N))</math>, which can be scaled down to
 
:<math>\left( \frac{am+Nb}{k} \,,\, \frac{a+bm}{k} \,,\, \frac{m^2-N}{k} \right).</math>
 
When ''m'' is chosen so that ''(a+bm)/k'' is an integer, so are the other two numbers in the triple. Among such ''m'', the method chooses one that minimizes ''(m²-N)/k'', and repeats the process. This method always terminates with a solution (proved by Lagrange in 1768). Bhaskara used it to give the solution ''x''=1766319049, ''y''=226153980 to the notorious ''N''=61 case.<ref name=stillwell/>
 
The general theory of Pell's equation, based on [[continued fractions]] and algebraic manipulations with numbers of the form <math>P+Q\sqrt{a},</math> was developed by [[Joseph Louis Lagrange|Lagrange]] in 1766–1769.<ref>"Solution d'un Problème d'Arithmétique", in [http://gdz.sub.uni-goettingen.de/no_cache/dms/load/img/?IDDOC=41029 J.-A. Serret (Ed.), ''Oeuvres de Lagrange'', vol. 1, pp. 671–731, 1867.]</ref>
 
==Solutions==
 
===Fundamental solution via continued fractions===
 
Let <math>\tfrac{h_i}{k_i}</math> denote the sequence of [[Convergent (continued fraction)|convergents]] to the [[continued fraction]] for <math>\sqrt{n}</math>. Then the pair (''x''<sub>1</sub>,''y''<sub>1</sub>) solving Pell's equation and minimizing ''x'' satisfies ''x''<sub>1</sub> = ''h<sub>i</sub>'' and ''y''<sub>1</sub> = ''k<sub>i</sub>'' for some ''i''. This pair is called the ''fundamental solution''. Thus, the fundamental solution may be found by performing the continued fraction expansion and testing each successive convergent until a solution to Pell's equation is found.
 
As {{harvtxt|Lenstra|2002}} describes, the time for finding the fundamental solution using the continued fraction method, with the aid of the [[Schönhage–Strassen algorithm]] for fast integer multiplication, is within a logarithmic factor of the solution size, the number of digits in the pair (''x''<sub>1</sub>,''y''<sub>1</sub>). However, this is not a [[polynomial time algorithm]] because the number of digits in the solution may be as large as √''n'', far larger than a polynomial in the number of digits in the input value ''n'' {{harv|Lenstra|2002}}.
 
===Additional solutions from the fundamental solution===
Once the fundamental solution is found, all remaining solutions may be calculated algebraically as
:<math>x_k + y_k\sqrt n = (x_1 + y_1\sqrt n)^k.</math>
Equivalently, we may calculate subsequent solutions via the [[recurrence relation]]s
:<math>\displaystyle x_{k+1} = x_1 x_k + n y_1 y_k,</math>
:<math>\displaystyle y_{k+1} = x_1 y_k + y_1 x_k.</math>
 
An alternative method to solving, once finding the first non-trivial solution, one could take the original equation <math>x^2 - ny^2 = 1</math> and factor the left hand side as a difference of squares, yielding <math>(x + y\sqrt n)(x - y\sqrt n) = 1.</math>  Once in this form, one can simply raise each side of the equation to the kth power, and recombining the factored form to a single difference statement.  The solution <math>s</math> will be of the form <math>(x-s)^k + n\cdot(y-s)^k = 1.</math>
 
===Concise representation and faster algorithms===
Although writing out the fundamental solution (''x''<sub>1</sub>,''y''<sub>1</sub>) as a pair of binary numbers may require a large number of bits, it may in many cases be represented more compactly in the form
:<math>x_1+y_1\sqrt n = \prod_{i=1}^t (a_i + b_i\sqrt n)^{c_i}</math>
using much smaller coefficients ''a''<sub>''i''</sub>, ''b''<sub>''i''</sub>, and ''c''<sub>''i''</sub>.
 
For instance, [[Archimedes' cattle problem]] may be solved using a Pell equation, the fundamental solution of which has 206545 digits if written out explicitly. However, instead of writing the solution as a pair of numbers, it may be written using the formula
:<math>x_1+y_1\sqrt n=u^{2329},</math>
where
:<math>u = x'_1+y'_1\sqrt{4729494} \, </math>
and <math>\scriptstyle x'_1</math> and <math>\scriptstyle y'_1</math> only have 45 and 41 decimal digits, respectively. Alternatively, one may write even more concisely
:<math>u = (300426607914281713365\sqrt{609}+84129507677858393258\sqrt{7766})^2.</math>
{{harv|Lenstra|2002}}.
 
Methods related to the [[quadratic sieve]] approach for [[integer factorization]] may be used to collect relations between prime numbers in the number field generated by √''n'', and to combine these relations to find a product representation of this type. The resulting algorithm for solving Pell's equation is more efficient than the continued fraction method, though it still does not take polynomial time. Under the assumption of the [[generalized Riemann hypothesis]], it can be shown to take time
:<math>\exp O(\sqrt{\log N\log\log N}),</math>
where ''N''&nbsp;=&nbsp;log&nbsp;''n'' is the input size, similarly to the quadratic sieve {{harv|Lenstra|2002}}.
 
===Quantum algorithms===
{{harvtxt|Hallgren|2007}} showed that a [[quantum computer]] can find a product representation, as described above, for the solution to Pell's equation in polynomial time. Hallgren's algorithm, which can be interpreted as an algorithm for finding the group of units of a real [[quadratic number field]], was extended to more general fields by {{harvtxt|Schmidt|Völlmer|2005}}.
 
==Example==
As an example, consider the instance of Pell's equation for ''n'' = 7; that is,
:<math>\displaystyle x^2 - 7 y^2 = 1.</math>
The sequence of convergents for the square root of seven are
:{| class="wikitable" style="text-align:center;"
|-
! ''h''&nbsp;/&nbsp;''k'' (Convergent)
! ''h''<sup>2</sup>&nbsp;&minus;7''k''<sup>2</sup> (Pell-type approximation)
|-
| 2&nbsp;/&nbsp;1
| &minus;3
|-
| 3&nbsp;/&nbsp;1
| +2
|-
| 5&nbsp;/&nbsp;2
| &minus;3
|-
| 8&nbsp;/&nbsp;3
| +1
|}
 
Therefore, the fundamental solution is formed by the pair (8,&nbsp;3). Applying the recurrence formula to this solution generates the infinite sequence of solutions
 
:(8,&nbsp;3); (127,&nbsp;48); (2024,&nbsp;765); (32257,&nbsp;12192); (514088,&nbsp;194307); (8193151;&nbsp;3096720); (130576328,&nbsp;49353213); ...
 
==Connections==
Pell's equation has connections to several other important subjects in mathematics.
 
===Algebraic number theory===
Pell's equation is closely related to the theory of [[algebraic number]]s, as the formula
:<math>x^2 - n y^2 = (x + y\sqrt n)(x - y\sqrt n)</math>
is the [[Field norm|norm]] for the [[Ring (mathematics)|ring]] <math>\mathbb{Z}[\sqrt{n}]</math> and for the closely related [[quadratic field]] <math>\mathbb{Q}(\sqrt{n})</math>. Thus, a pair of integers <math>(x, y)</math> solves Pell's equation if and only if <math>x + y \sqrt{n}</math> is a [[Unit (ring theory)|unit]] with norm 1 in <math>\mathbb{Z}[\sqrt{n}]</math>. [[Dirichlet's unit theorem]], that all units of <math>\mathbb{Z}[\sqrt{n}]</math> can be expressed as powers of a single [[Fundamental unit (number theory)|fundamental unit]] (and multiplication by a sign), is an algebraic restatement of the fact that all solutions to the Pell equation can be generated from the fundamental solution. The fundamental unit can in general be found by solving a Pell-like equation but it does not always correspond directly to the fundamental solution of Pell's equation itself.
 
===Chebyshev polynomials===
Demeyer (2007) mentions a connection between Pell's equation and the [[Chebyshev polynomials]]:
If ''T<sub>i</sub>''&nbsp;(''x'') and ''U<sub>i</sub>''&nbsp;(''x'') are the Chebyshev polynomials of the first and second kind, respectively, then these polynomials satisfy a form of Pell's equation in any [[polynomial ring]] ''R''[''x''], with ''n'' = ''x''<sup>2</sup>&nbsp;&minus;&nbsp;1:
 
:<math>T_i^2 - (x^2-1) U_{i-1}^2 = 1. \, </math>
 
Thus, these polynomials can be generated by the standard technique for Pell equations of taking powers of a fundamental solution:
 
:<math>T_i + U_{i-1} \sqrt{x^2-1} = (x + \sqrt{x^2-1})^i. \, </math>
 
It may further be observed that, if (''x<sub>i</sub>'',''y<sub>i</sub>'') are the solutions to any integer Pell equation, then ''x<sub>i</sub>'' = ''T<sub>i</sub>'' (''x''<sub>1</sub>) and ''y<sub>i</sub>'' = ''y''<sub>1</sub>''U''<sub>''i''&nbsp;&minus;&nbsp;1</sub>(''x''<sub>1</sub>) (Barbeau, chapter 3).
 
===Continued fractions===
A general development of solutions of Pell's equation in terms of [[continued fraction]]s can be presented, as the solutions ''x'' and ''y'' are approximates to the square root of ''n'' and thus are a special case of continued fraction approximations for [[quadratic irrational]]s.
 
The relationship to the continued fractions implies that the solutions to Pell's equation form a [[semigroup]] subset of the [[modular group]]. Thus, for example, if ''p'' and ''q'' satisfy Pell's equation, then
 
:<math>\begin{pmatrix} p & q \\ nq & p \end{pmatrix}</math>
 
is a matrix of unit [[determinant]].  Products of such matrices take exactly the same form, and thus all such products yield solutions to Pell's equation. This can be understood in part to arise from the fact that successive convergents of a continued fraction share the same property: If ''p''<sub>''k''&minus;1</sub>/''q''<sub>''k''&minus;1</sub> and ''p''<sub>''k''</sub>/''q''<sub>''k''</sub> are two successive  convergents of a continued fraction, then the matrix
 
:<math>\begin{pmatrix} p_{k-1} & p_{k} \\ q_{k-1} & q_{k} \end{pmatrix}</math>
 
has determinant (&minus;1)<sup>''k''</sup>.
 
[[Størmer's theorem]] applies Pell equations to find pairs of consecutive [[smooth number]]s. As part of this theory, [[Carl Størmer|Størmer]] also investigated divisibility relations among solutions to Pell's equation; in particular, he showed that each solution other than the fundamental solution has a [[prime factor]] that does not divide&nbsp;''n''.
 
As Lenstra (2002) describes, Pell's equation can also be used to solve [[Archimedes' cattle problem]].
 
==The negative Pell equation==
The negative Pell equation is given by
 
:<math> x^2 - ny^2 = -1. \, </math>  (eq.1)
 
It has also been extensively studied; it can be solved by the same method of using continued fractions and will have solutions when the period of the continued fraction has odd length. However we do not know which roots have odd period lengths so we do not know when the negative Pell equation is solvable. But we can eliminate certain ''n'' since a necessary but not sufficient condition for solvability is that ''n'' is not divisible by a prime of form 4m+3. Thus, for example, x<sup>2</sup>-3py<sup>2</sup> = -1 is never solvable, but x<sup>2</sup>-5py<sup>2</sup> = -1 may be, such as when p = 1 or 13, though not when p = 41.
 
{{harvtxt|Cremona|Odoni|1989}} demonstrate that the proportion of square-free ''n'' divisible by ''k'' primes of the form 4m+1 for which the negative Pell equation is soluble is at least 40%. If it does have a solution, then it can be shown that its fundamental solution leads to the fundamental one for the positive case by squaring both sides of eq. 1,
 
:<math> (x^2 - ny^2)^2 = (-1)^2 \, </math>
 
to get,
 
:<math> (x^2 + ny^2)^2 - n(2xy)^2 = 1. \, </math>
 
Or, since ny<sup>2</sup> = x<sup>2</sup>+1 from eq.1, then,
 
:<math> (2x^2 + 1)^2 - n(2xy)^2 = 1 \, </math>
 
showing that fundamental solutions to the positive case are bigger than those for the negative case.
 
==Transformations==
I. The related equation,
 
:<math> u^2 - dv^2 = \pm 2 \, </math>  (eq.2)
 
can be used to find solutions to the positive Pell equation for certain&nbsp;''d''.  [[Adrien-Marie Legendre|Legendre]] proved that all primes of form ''d''&nbsp;=&nbsp;4''m''&nbsp;+&nbsp;3 solve one case of eq.2, with the form 8''m''&nbsp;+&nbsp;3 solving the negative, and 8''m''&nbsp;+&nbsp;7 for the positive.  Their fundamental solution then leads to the one for ''x''<SUP>2</SUP>&minus;''dy''<SUP>2</SUP>&nbsp;=&nbsp;1.  This can be shown by squaring both sides of eq.&nbsp;2,
 
:<math> (u^2 - dv^2)^2 = (\pm 2)^2 \, </math>
 
to get,
 
:<math> (u^2 + dv^2)^2 - d(2uv)^2 = 4. \, </math>
 
Since <math> dv^2 = u^2 \mp 2 </math> from eq.2, then,
 
:<math> (2u^2 \mp 2)^2 - d(2uv)^2 = 4 \, </math>
 
or simply,
 
:<math> (u^2 \mp 1)^2 - d(uv)^2 = 1 \, </math>
 
showing that fundamental solutions to eq.2 are smaller than eq.1. For example, u<SUP>2</SUP>-3v<SUP>2</SUP> = -2 is {''u'',''v''} = {1,1}, so ''x''<SUP>2</SUP>&nbsp;&minus;&nbsp;3''y''<SUP>2</SUP>&nbsp;=&nbsp;1 has {''x'',''y''} = {2,1}.  On the other hand, ''u''<SUP>2</SUP>&nbsp;&minus;&nbsp;7''v''<SUP>2</SUP> =&nbsp;2 is {''u'',''v''} = {3,1}, so ''x''<SUP>2</SUP>&nbsp;&minus;&nbsp;7y<SUP>2</SUP> = 1 has {''x'',''y''}&nbsp;=&nbsp;{8,3}.
 
II. Another related equation,
 
:<math> u^2 - dv^2 = \pm 4 \, </math>  (eq.3)
 
can also be used to find solutions to Pell equations for certain ''d'', this time for the positive and negative case.  For the following transformations,<ref>[http://sites.google.com/site/tpiezas/008  A Collection of Algebraic Identities: Pell Equations.]</ref> if fundamental {''u'',''v''} are both [[odd number|odd]], then it leads to fundamental {x,y}.
 
1. If u<SUP>2</SUP>&nbsp;&minus;&nbsp;dv<SUP>2</SUP> = &minus;4, and {x,y} = {(''u''<SUP>2</SUP>&nbsp;+&nbsp;3)''u''/2, (''u''<SUP>2</SUP>&nbsp;+&nbsp;1)''v''/2}, then ''x''<SUP>2</SUP>&nbsp;&minus;&nbsp;''dy''<SUP>2</SUP>&nbsp;=&nbsp;&minus;1.
 
Ex. Let ''d'' = 13, then {''u'',''v''} = {3, 1} and {''x'',''y''} = {18, 5}.
 
2. If ''u''<SUP>2</SUP>&nbsp;&minus;&nbsp;''dv''<SUP>2</SUP> =&nbsp;4, and {''x'',''y''} = {(''u''<SUP>2</SUP>&nbsp;&minus;&nbsp;3)''u''/2, (''u''<SUP>2</SUP>&nbsp;&minus;&nbsp;1)''v''/2}, then ''x''<SUP>2</SUP>&nbsp;&minus;&nbsp;''dy''<SUP>2</SUP>&nbsp;=&nbsp;1.
 
Ex. Let ''d'' = 13, then {u,v} = {11, 3} and {x,y} = {649, 180}.
 
3. If ''u''<SUP>2</SUP>&nbsp;&minus;&nbsp;''dv''<SUP>2</SUP> = &minus;4, and {''x'',''y''} = {(''u''<SUP>4</SUP>&nbsp;+&nbsp;4''u''<SUP>2</SUP>&nbsp;+&nbsp;1)(''u''<SUP>2</SUP>&nbsp;+&nbsp;2)/2, (''u''<SUP>2</SUP>&nbsp;+&nbsp;3)(''u''<SUP>2</SUP>&nbsp;+&nbsp;1)''uv''/2}, then ''x''<SUP>2</SUP>&nbsp;&minus;&nbsp;''dy''<SUP>2</SUP>&nbsp;=&nbsp;1.
 
Ex. Let ''d'' = 61, then {''u'',''v''} = {39, 5} and {''x'',''y''} = {1766319049, 226153980}.
 
Especially for the last transformation, it can be seen how solutions to {''u'',''v''} are ''much'' smaller than {''x'',''y''}, since the latter are [[sextic]] and [[quintic]] polynomials in terms of&nbsp;''u''.
 
==Notes==
<references/>
 
==References==
*{{Citation
| last = Barbeau | first = Edward J.
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| publisher = Springer-Verlag
| year = 2003
| mr = 1949691
| isbn = 0-387-95529-1}}.
*{{Citation
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|last1=Whitford
|year=1912
|url=http://name.umdl.umich.edu/ABV2773.0001.001
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|publisher = Columbia University
}}
*{{Citation | last1=Cremona | first1=John E. | last2=Odoni | first2=R. W. K. | title=Some density results for negative Pell equations; an application of graph theory | doi=10.1112/jlms/s2-39.1.16 | year=1989 | journal=Journal of the London Mathematical Society. Second Series | issn=0024-6107 | volume=39 | issue=1 | pages=16–28}}.
*{{Citation
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*{{Citation
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*{{Citation
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| title = Solving the Pell Equation
| journal = [[Notices of the American Mathematical Society]]
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| postscript = .}}.
*{{Citation
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*{{Citation
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| year = 2005}}.
* Wildberger, N.J., ''Divine Proportions : Rational Trigonometry to Universal Geometry'', Wild Egg Books, Sydney, 2005.
 
==Further reading==
* {{cite book | zbl=1043.11027 | last=Williams | first=H. C. | authorlink= | chapter=Solving the Pell equation | pages=325-363 | editor1-last=Bennett | editor1-first=M. A. | editor2-last=Berndt | editor2-first=B.C. | editor2-link=Bruce C. Berndt | editor3-last=Boston | editor3-first=N. | editor3-link=Nigel Boston | editor4-last=Diamond | editor4-first=H.G. | editor5-last=Hildebrand | editor5-first=A.J. | editor6-last=Philipp | editor6-first=W. | title=Surveys in number theory: Papers from the millennial conference on number theory | location=Natick, MA | publisher=A K Peters | year=2002 | isbn=1-56881-162-4 }}
 
==External links==
*[http://www-groups.dcs.st-and.ac.uk/~history/HistTopics/Pell.html Pell's equation]
 
{{Use dmy dates|date=September 2010}}
 
{{DEFAULTSORT:Pell's Equation}}
[[Category:Diophantine equations]]
[[Category:Continued fractions]]

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