Principal bundle: Difference between revisions

From formulasearchengine
Jump to navigation Jump to search
en>RJFJR
link in cite book
Line 1: Line 1:
{{about|the classical approach to Green's functions|a modern discussion|fundamental solution}}
Roberto is the name I love to be called with although it is not the name forward my birth certificate. My colleagues say it's not really for me but what I love doing is to drive but Seriously been taking on new things lately. [http://search.un.org/search?ie=utf8&site=un_org&output=xml_no_dtd&client=UN_Website_en&num=10&lr=lang_en&proxystylesheet=UN_Website_en&oe=utf8&q=South+Carolina&Submit=Go South Carolina] is where my new home is. I used to be be unemployed but I am a cashier but the promotion don't comes. I've been working on particular website for some period now. Check it outdoors here: http://prometeu.net<br><br>Feel free to surf to my webpage: [http://prometeu.net clash of clans hack cydia]
In [[mathematics]], a '''Green's function''' is the [[impulse response]] of an [[inhomogeneous ordinary differential equation|inhomogeneous]] [[differential equation]] defined on a domain, with specified initial conditions or boundary conditions. Via the [[superposition principle]], the convolution of a Green's function with an arbitrary function ''f''(''x'') on that domain is the solution to the inhomogenous differential equation for ''f''(''x'').
 
Green's functions are named after the British [[mathematician]] [[George Green]], who first developed the concept in the 1830s.  In the modern study of linear [[partial differential equation]]s, Green's functions are studied largely from the point of view of [[fundamental solution]]s instead.
 
Under [[Green's function (many-body theory)|many-body theory]], the term is also used in [[physics]], specifically in [[quantum field theory]], [[aerodynamics]], [[aeroacoustics]], [[electrodynamics]] and [[statistical field theory]], to refer to various types of [[correlation function (quantum field theory)|correlation functions]], even those that do not fit the mathematical definition.
 
==Definition and uses==
A Green's function, ''G''(''x'',&nbsp;''s''),  of a [[linear differential operator]] ''L''&nbsp;=&nbsp;''L''(''x'') acting on [[distribution (mathematics)|distributions]] over a subset of the [[Euclidean space]] '''R'''<sup>''n''</sup>, at a point ''s'', is any solution of
 
{{NumBlk|1=:|2=<math>L^*G(x,s)=\delta(x-s),</math>|3=(1)|RawN=.}}
 
where <math>\delta</math> is the [[Dirac delta function]] and ''L*'' is the [[adjoint]] ''L''. In the case of a [[self-adjoint operator]], the equation can be written as
 
{{NumBlk|1=:|2=<math>LG(x,s)=\delta(x-s).</math>|3=(2)|RawN=.}}
 
This property of a Green's function can be exploited to solve differential equations of the form
 
{{NumBlk|1=:|2=<math>Lu(x)=f(x).</math>|3=(3)|RawN=.}}
 
If the [[kernel (linear operator)|kernel]] of ''L'' is non-trivial, then the Green's function is not unique. However, in practice, some combination of [[symmetry]], [[boundary condition]]s and/or other externally imposed criteria will give a unique Green's function. Also, Green's functions in general are [[Distribution (mathematics)|distributions]], not necessarily proper [[Function (mathematics)|functions]].
 
Green's functions are also useful tools in solving [[wave equation]]s and [[diffusion equation]]s. In [[quantum mechanics]], the Green's function of the [[Hamiltonian mechanics|Hamiltonian]] is a key concept with important links to the concept of [[density of states]].  As a side note, the Green's function as used in physics is usually defined with the opposite sign; that is,
 
:<math>LG(x,s)=-\delta(x-s).</math>
 
This definition does not significantly change any of the properties of the Green's function.
 
If the operator is [[translation invariant]], that is, when ''L'' has [[constant coefficients]] with respect to ''x'', then the Green's function can be taken to be a [[convolution operator]], that is,
 
:<math>G(x,s)=G(x-s).</math>
 
In this case, the Green's function is the same as the impulse response of [[LTI system theory|linear time-invariant system theory]].
 
==Motivation==
{{See also |Spectral theory}}
Loosely speaking, if such a function ''G'' can be found for the operator ''L'', then if we multiply the equation (1) for the Green's function by ''f''(''s''), and then perform an integration in the ''s'' variable, we obtain:
 
:<math>\int LG(x,s) f(s) \, ds = \int \delta(x-s)f(s) \, ds = f(x).</math>
 
The right-hand side is now given by the equation (3) to be equal to ''L u''(''x''), thus:
 
:<math>Lu(x)=\int LG(x,s) f(s) \, ds.</math>
 
Because the operator ''L''&nbsp;=&nbsp;''L''(''x'') is linear and acts on the variable&nbsp;''x'' alone (not on the variable of integration&nbsp;''s''), we can take the operator ''L'' outside of the integration on the right-hand side, obtaining
 
:<math>Lu(x)=L\left(\int G(x,s) f(s) \,ds\right),</math>
 
which suggests
 
{{NumBlk|1=:|2=<math>u(x)=\int G(x,s) f(s) \,ds.</math>|3=(3)|RawN=.}}
 
Thus, we can obtain the function ''u''(''x'') through knowledge of the Green's function in equation (1) and the source term on the right-hand side in equation (2). This process relies upon the linearity of the operator&nbsp;''L''.
 
In other words, the solution of equation (2), ''u''(''x''), can be determined by the integration given in equation (3). Although ''f''(''x'') is known, this integration cannot be performed unless ''G'' is also known. The problem now lies in finding the Green's function ''G'' that satisfies equation (1). For this reason, the Green's function is also sometimes called the fundamental solution associated to the operator&nbsp;''L''.
 
Not every operator ''L'' admits a Green's function. A Green's function can also be thought of as a [[right inverse]] of ''L''. Aside from the difficulties of finding a Green's function for a particular operator, the integral in equation&nbsp;(3), may be quite difficult to evaluate. However the method gives a theoretically exact result.
 
This can be thought of as an expansion of ''f'' according to a [[Dirac delta function]] basis (projecting ''f'' over δ(''x''&nbsp;−&nbsp;''s'')) and a superposition of the solution on each [[Projection (mathematics)|projection]]. Such an integral equation is known as a [[Fredholm integral equation]], the study of which constitutes [[Fredholm theory]].
 
==Green's functions for solving inhomogeneous boundary value problems==
The primary use of Green's functions in mathematics is to solve non-homogeneous [[boundary value problem]]s.  In modern [[theoretical physics]], Green's functions are also usually used as [[propagator]]s in [[Feynman diagram]]s (and the phrase ''Green's function'' is often used for any [[correlation function (quantum field theory)|correlation function]]).
 
===Framework===
Let ''L'' be the [[Sturm–Liouville theory|Sturm–Liouville]] operator, a linear differential operator of the form
:<math>L=\dfrac{d}{dx}\left[p(x) \dfrac{d}{dx}\right]+q(x)</math>
and let ''D'' be the [[boundary condition]]s operator
:<math>Du= \begin{cases}
\alpha_1 u'(0)+\beta_1 u(0) \\
\alpha_2 u'(l)+\beta_2 u(l).
\end{cases}</math>
 
Let ''f''(''x'') be a [[continuous function]] in [0,''l'']. We shall also suppose that the problem
 
:<math>\begin{align}
Lu &= f \\
Du &= 0
\end{align}</math>
 
is regular (i.e., only the [[Trivial (mathematics)|trivial]] solution exists for the [[homogenization (mathematics)|homogeneous]] problem).
 
===Theorem===
There is one and only one solution ''u''(''x'') that satisfies
 
:<math> \begin{align}
Lu & = f\\
Du & = 0,
\end{align}</math>
 
and it is given by
 
:<math>u(x)=\int_0^\ell f(s) G(x,s) \, ds,</math>
 
where ''G''(''x'',''s'') is a Green's function satisfying the following conditions:
# <math>G(x,s)</math> is continuous in <math>x</math> and <math>s</math>.
# For <math>x \ne s</math>, <math>L G(x, s)=0</math>.
# For <math>s \ne 0</math>, <math>D G(x, s)=0</math>.
# [[Derivative]] "jump": <math>G'(s_{+0}, s)-G'(s_{-0}, s)=1 / p(s)</math>.
# Symmetry: <math>G(x,s) = G(s, x)</math>.
 
==Finding Green's functions==
 
===Eigenvalue expansions===
If a [[differential operator]] ''L'' admits a set of [[eigenvectors]] <math>\Psi_n(x)</math> (i.e., a set of functions  <math>\Psi_n</math> and scalars <math>\lambda_n</math> such that <math>L \Psi_n=\lambda_n \Psi_n</math>) that is complete, then it is possible to construct a Green's function from these eigenvectors and [[eigenvalues]].
 
"Complete" means that the set of functions <math>\left\{ \Psi_n \right\}</math> satisfies the following [[completeness relation]]:
 
:<math>\delta(x-x')=\sum_{n=0}^\infty \Psi_n^\dagger(x) \Psi_n(x').</math>
 
Then the following holds:
 
:<math>G(x, x')=\sum_{n=0}^\infty \dfrac{\Psi_n^\dagger(x) \Psi_n(x')}{\lambda_n},</math>
 
where <math>\dagger</math> represents complex conjugation.
 
Applying the operator ''L'' to each side of this equation results in the completeness relation, which was assumed true.
 
The general study of the Green's function written in the above form, and its relationship to the [[function space]]s formed by the eigenvectors, is known as [[Fredholm theory]].
 
There are several other methods for finding Green's functions, including the [[method of images]], [[separation of variables]], and [[Laplace transforms]] (Cole 2011).
 
=== Table of Green's functions ===
The following table gives an overview of Green's functions of frequently appearing differential operators, where <math>\theta(t)</math> is the  [[Heaviside step function]],  <math>r=\sqrt{x^2+y^2+z^2}</math> and <math>\rho=\sqrt{x^2+y^2}</math>.<ref>some examples taken from Schulz, Hermann: Physik mit Bleistift. Frankfurt am Main: Deutsch, 2001. ISBN 3-8171-1661-6 (German)</ref>
{| class="wikitable"
|-
! Differential Operator <math>L</math> !! Green's Function <math>G</math> !! Example of application
|-
| <math>\partial_t + \gamma </math> || [[Heaviside step function|<math>\theta(t)</math>]]<math>\mathrm e^{-\gamma t}</math> ||
|-
| <math>\left(\partial_t + \gamma \right)^2</math> || <math>\theta(t)t\mathrm e^{-\gamma t}</math> ||
|-
| <math>\partial_t^2 + 2\gamma\partial_t + \omega_0^2</math> || <math>\theta(t)\mathrm e^{-\gamma t}\frac{1}{\omega}\sin(\omega t)</math> with <math>\omega=\sqrt{\omega_0^2-\gamma^2}</math>|| [[Harmonic oscillator#Damped harmonic oscillator|one-dimensional damped harmonic oscillator]]
|-
| [[Laplace operator#Two dimensions|<math>\Delta_\text{2D}</math>]]<math>=\partial_x^2 + \partial_y^2</math>  || <math>\frac{1}{2 \pi}\ln \rho</math> ||
|-
| [[Laplace operator#Three dimensions|<math>\Delta</math>]]<math>=\partial_x^2 + \partial_y^2 + \partial_z^2</math>  || <math>\frac{-1}{4 \pi r}</math> || [[Poisson equation]]
|-
| [[Helmholtz equation|Helmholtz operator]] <math>\Delta + k^2</math> || <math>\frac{-\mathrm e^{-ikr}}{4 \pi r}</math> || stationary [[Schrödinger equation]]
|-
| [[D'Alembert operator]] <math>\square = \frac{1}{c^2}\partial_t^2-\Delta</math> || <math>\frac{\delta(t-\frac{r}{c})}{4 \pi r}</math> || [[wave equation]]
|-
| <math>\partial_t - D\Delta</math> || <math>\theta(t)\left(\frac{1}{4\pi Dt}\right)^{3/2}\mathrm e^{-r^2/4Dt}</math> || [[diffusion]]
|}
 
==Green's functions for the Laplacian==
Green's functions for linear differential operators involving the [[Laplacian]] may be readily put to use using the second of [[Green's identities]].
 
To derive Green's theorem, begin with the [[divergence theorem]] (otherwise known as [[Gauss's theorem]]):
 
:<math>\int_V \nabla \cdot \vec A\ dV=\int_S \vec A \cdot d\hat\sigma.</math>
 
Let <math>\vec A=\phi\nabla\psi-\psi\nabla\phi</math> and substitute into Gauss' law.  Compute <math>\nabla\cdot\vec A</math> and apply the chain rule for the <math>\nabla</math> operator:
 
:<math>\begin{align}
\nabla\cdot\vec A &=\nabla\cdot(\phi\nabla\psi \;-\; \psi\nabla\phi)\\
&=(\nabla\phi)\cdot(\nabla\psi) \;+\; \phi\nabla^2\psi \;-\; (\nabla\phi)\cdot(\nabla\psi) \;-\; \psi\nabla^2\phi\\
&=\phi\nabla^2\psi \;-\; \psi\nabla^2\phi.
\end{align}</math>
 
Plugging this into the divergence theorem produces [[Green's theorem]]:
 
:<math>\int_V (\phi\nabla^2\psi-\psi\nabla^2\phi) dV=\int_S (\phi\nabla\psi-\psi\nabla\phi)\cdot d\hat\sigma.</math>
 
Suppose that the linear differential operator ''L'' is the [[Laplacian]], <math>\nabla^2</math>, and that there is a Green's function ''G'' for the Laplacian. The defining property of the Green's function still holds:
 
:<math>L G(x,x')=\nabla^2 G(x,x')=\delta(x-x').</math>
 
Let <math>\psi=G</math> in [[Green's theorem]].  Then:
 
:<math>\int_V \left[ \phi(x') \delta(x-x')-G(x,x') \nabla^2\phi(x')\right]\ d^3x' = \int_S \left[\phi(x')\nabla' G(x,x')-G(x,x')\nabla'\phi(x')\right] \cdot d\hat\sigma'.</math>
 
Using this expression, it is possible to solve [[Laplace's equation]] <math>\nabla^2\phi(x)=0</math> or [[Poisson's equation]] <math>\nabla^2\phi(x)=-\rho(x)</math>, subject to either [[Neumann boundary condition|Neumann]] or [[Dirichlet boundary condition|Dirichlet]] boundary conditions. In other words, we can solve for <math>\phi(x)</math> everywhere inside a volume where either (1) the value of <math>\phi(x)</math> is specified on the bounding surface of the volume (Dirichlet boundary conditions), or (2) the normal derivative of <math>\phi(x)</math> is specified on the bounding surface (Neumann boundary conditions).
 
Suppose the problem is to solve for <math>\phi(x)</math> inside the region. Then the integral
:<math>\int\limits_V {\phi(x')\delta(x-x')\ d^3x'}</math>
reduces to simply <math>\phi(x)</math> due to the defining property of the [[Dirac delta function]] and we have:
 
:<math>\phi(x)=\int_V G(x,x') \rho(x')\ d^3x'+\int_S \left[\phi(x')\nabla' G(x,x')-G(x,x')\nabla'\phi(x')\right] \cdot d\hat\sigma'.</math>
 
This form expresses the well-known property of [[harmonic function]]s that if the value or normal derivative is known on a bounding surface, then the value of the function inside the volume is known everywhere.
 
In [[electrostatics]], <math>\phi(x)</math> is interpreted as the [[electric potential]], <math>\rho(x)</math> as [[electric charge]] [[density]], and the normal derivative <math>\nabla\phi(x')\cdot d\hat\sigma'</math> as the normal component of the electric field.
 
If the problem is to solve a Dirichlet boundary value problem, the Green's function should be chosen such that <math>G(x,x')</math> vanishes when either ''x'' or ''x''′ is on the bounding surface.Thus only one of the two terms in the surface integral remains. If the problem is to solve a Neumann boundary value problem, the Green's function is chosen such that its normal derivative vanishes on the bounding surface, as it would seem to be the most logical choice. (See Jackson J.D. classical electrodynamics, page 39). However, application of Gauss's theorem to the differential equation defining the Green's function yields
 
:<math>\int_S \nabla' G(x,x') \cdot d\hat\sigma' = \int_V \nabla'^2 G(x,x') d^3x' = \int_V \delta (x-x') d^3x' = 1</math>
 
meaning the normal derivative of <math>G(x,x')</math> cannot vanish on the surface, because it must integrate to 1 on the surface.  (Again, see Jackson J.D. classical electrodynamics, page 39 for this and the following argument). The simplest form the normal derivative can take is that of a constant, namely <math>1/S</math>, where ''S'' is the surface area of the surface.  The surface term in the solution becomes
 
:<math>\int_S \phi(x')\nabla' G(x,x')\cdot d\hat\sigma' = \langle\phi\rangle_S </math>
 
where <math>\langle\phi\rangle_S </math> is the average value of the potential on the surface.  This number is not known in general, but is often unimportant, as the goal is often to obtain the electric field given by the gradient of the potential, rather than the potential itself.
 
With no boundary conditions, the Green's function for the Laplacian ([[Green's function for the three-variable Laplace equation]]) is:
 
:<math>G(x,x')=\dfrac{1}{|x-x'|}.</math>
 
Supposing that the bounding surface goes out to infinity, and plugging in this expression for the Green's function, this gives the familiar expression for electric potential in terms of electric charge density as
 
:<math>\phi(x)=\int_V \dfrac{\rho(x')}{|x-x'|} \, d^3x'.</math>
 
==Example==
<blockquote>'''Example.''' Find the Green function for the following problem:
 
:<math>\begin{align}
  Lu & = u'' + k^2 u = f(x)\\
  u(0)& = 0, \quad u\left(\tfrac{\pi}{2k}\right) = 0.
\end{align}</math></blockquote>
 
'''First step:''' The Green's function for the linear operator at hand is defined as the solution to
 
:<math>g''(x,s) + k^2 g(x,s) = \delta(x-s).</math>
 
If <math>x\ne s</math>, then the delta function gives zero, and the general solution is
 
:<math>g(x,s)=c_1 \cos kx+c_2 \sin kx.</math>
 
For <math>x<s</math>, the boundary condition at <math>x=0</math> implies
 
:<math>g(0,s)=c_1 \cdot 1+c_2 \cdot 0=0, \quad c_1 = 0</math>
 
The equation of <math>g\left(\tfrac{\pi}{2k},s\right)=0</math> is skipped because <math>x \ne \tfrac{\pi}{2k}</math>
if <math>x < s</math> and <math>s \ne \tfrac{\pi}{2k}</math>.
 
For <math>x>s</math>, the boundary condition at <math>x=\tfrac{\pi}{2k}</math> implies
 
:<math>g\left(\tfrac{\pi}{2k},s\right) = c_3 \cdot 0+c_4 \cdot 1=0, \quad c_4 = 0 </math>
 
The equation of <math>g(0,s)=0</math> is skipped for similar reasons.
 
To summarize the results thus far:
 
:<math>g(x,s)= \begin{cases}
  c_2 \sin kx, & \text{for }x<s\\
  c_3 \cos kx, & \text{for }s<x
\end{cases}</math>
 
'''Second step:''' The next task is to determine <math>c_{2}</math> and <math>c_{3}</math>.
 
Ensuring continuity in the Green's function at <math>x=s</math> implies
 
:<math>c_2 \sin ks=c_3 \cos ks</math>
 
One can ensure proper discontinuity in the first derivative by integrating the defining differential equation from <math>x=s-\epsilon</math> to <math>x=s+\epsilon</math> and taking the limit as <math>\epsilon</math> goes to zero:
 
:<math>c_3 \cdot \left(-k \sin ks\right)-c_2 \cdot \left( k \cos ks\right )=1</math>
 
The two (dis)continuity equations can be solved for <math>c_{2}</math> and <math>c_{3}</math> to obtain
 
: <math>c_2 = -\frac{\cos ks}{k}  \quad;\quad c_3 = -\frac{\sin ks}{k}</math>
 
So the Green's function for this problem is:
 
:<math>g(x,s)=\begin{cases}
  -\frac{\cos ks}{k} \sin kx, & x<s\\
  -\frac{\sin ks}{k} \cos kx, & s<x
\end{cases}</math>
 
==Further examples==
* Let ''n''&nbsp;=&nbsp;1 and let the subset be all of '''R'''. Let L be ''d''/''dx''. Then, the [[Heaviside step function]] ''H''(''x'' − ''x''<sub>0</sub>) is a Green's function of L at ''x''<sub>0</sub>.
* Let ''n''&nbsp;=&nbsp;2 and let the subset be the quarter-plane {(''x'', ''y'') : ''x'', ''y'' ≥ 0} and L be the [[Laplacian]]. Also, assume a [[Dirichlet boundary condition]] is imposed at ''x''&nbsp;=&nbsp;0 and a [[Neumann boundary condition]] is imposed at ''y''&nbsp;=&nbsp;0. Then the Green's function is
 
::<math>\begin{align}
G(x, y, x_0, y_0) =\dfrac{1}{2\pi} &\left[\ln\sqrt{(x-x_0)^2+(y-y_0)^2}-\ln\sqrt{(x+x_0)^2+(y-y_0)^2} \right. \\
&\left. + \ln\sqrt{(x-x_0)^2+(y+y_0)^2}- \ln\sqrt{(x+x_0)^2+(y+y_0)^2}\right]
\end{align}</math>
 
==See also==
* [[Discrete Laplace operator#Discrete Green's function|Discrete Green's functions]] can be defined on [[graph (mathematics)|graphs]] and grids.
* [[Propagator (Quantum Theory)|Feynman propagators]]
* [[Green's identities]]
* [[Impulse response]], the analog of a Green's function in [[signal processing]]
* [[Keldysh formalism]]
* [[Spectral theory]]
* [[Green's function (many-body theory)|Green's function in many-body theory]]
 
==References==
{{refbegin}}
* S. S. Bayin (2006), ''Mathematical Methods in Science and Engineering'', Wiley, Chapters 18 and 19.
* Eyges, Leonard, ''The Classical Electromagnetic Field'', Dover Publications, New York, 1972. ISBN 0-486-63947-9.  (Chapter 5 contains a very readable account of using Green's functions to solve boundary value problems in electrostatics.)
* A. D. Polyanin and V. F. Zaitsev, ''Handbook of Exact Solutions for Ordinary Differential Equations (2nd edition)'', Chapman & Hall/CRC Press, Boca Raton, 2003. ISBN 1-58488-297-2
* A. D. Polyanin, ''Handbook of Linear Partial Differential Equations for Engineers and Scientists'', Chapman & Hall/CRC Press, Boca Raton, 2002. ISBN 1-58488-299-9
* G. B. Folland, ''Fourier Analysis and Its Applications'', Wadsworth and Brooks/Cole Mathematics Series.
* K. D. Cole, J. V. Beck, A. Haji-Sheikh, and B. Litkouhi, Methods for obtaining Green's functions, '' Heat Conduction Using Green's Functions'', Taylor and Francis, 2011, pp.&nbsp;101–148.  ISBN 1-43981-354-6
*Green G, ''An Essay on the Application of Mathematical Analysis to the Theories of Electricity and Magnetism'' (Nottingham, England: T. Wheelhouse, 1828). [http://books.google.com/books?id=GwYXAAAAYAAJ&pg=PA10#v=onepage&q&f=false pages 10-12]
{{refend}}
{{reflist}}
 
==External links==
{{refbegin}}
* {{springer|title=Green function|id=p/g045090}}
* {{MathWorld | urlname=GreensFunction | title=Green's Function}}
* {{PlanetMath | urlname=GreensFunctionForDifferentialOperator | title=Green's function for differential operator}}
* {{planetmath reference | id=6355 | title=Green's function}}
* {{planetmath reference | id=7963 | title=GreenFunctionsAndConformalMapping}}
* [http://nanohub.org/resources/1877 Introduction to the Keldysh Nonequilibrium Green Function Technique] by A. P. Jauho
* [http://www.greensfunction.unl.edu/home/index.html Green's Function Library]
* [http://www.boulder.nist.gov/div853/greenfn/tutorial.html Tutorial on Green's functions]{{Dead link|date=February 2012}}
* [http://www.ntu.edu.sg/home/mwtang/bemsite.htm Boundary Element Method (for some idea on how Green's functions may be used with the boundary element method for solving potential problems numerically)]
* [http://en.citizendium.org/wiki/Green%27s_function At Citizendium]
* [http://academicearth.com/lectures/delta-function-and-greens-function MIT video lecture on Green's function]
* {{cite web|last=Bowley|first=Roger|title=George Green & Green's Functions|url=http://www.sixtysymbols.com/videos/georgegreen.htm|work=Sixty Symbols|publisher=[[Brady Haran]] for the [[University of Nottingham]]}}
{{refend}}
 
[[Category:Differential equations]]
[[Category:Generalized functions]]
[[Category:Concepts in physics]]

Revision as of 21:42, 28 February 2014

Roberto is the name I love to be called with although it is not the name forward my birth certificate. My colleagues say it's not really for me but what I love doing is to drive but Seriously been taking on new things lately. South Carolina is where my new home is. I used to be be unemployed but I am a cashier but the promotion don't comes. I've been working on particular website for some period now. Check it outdoors here: http://prometeu.net

Feel free to surf to my webpage: clash of clans hack cydia