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{{ | {{one source|date=December 2012}} | ||
In [[mathematics]], the '''smash product''' of two [[pointed space]]s (i.e. [[topological space]]s with distinguished basepoints) ''X'' and ''Y'' is the [[quotient space|quotient]] of the [[product space]] ''X'' × ''Y'' under the identifications (''x'', ''y''<sub>0</sub>) ∼ (''x''<sub>0</sub>, ''y'') for all ''x'' ∈ ''X'' and ''y'' ∈ ''Y''. The smash product is usually denoted ''X'' ∧ ''Y'' or ''X'' ⨳ ''Y''. The smash product depends on the choice of basepoints (unless both ''X'' and ''Y'' are [[homogeneous space|homogeneous]]). | |||
One can think of ''X'' and ''Y'' as sitting inside ''X'' × ''Y'' as the [[subspace (topology)|subspaces]] ''X'' × {''y''<sub>0</sub>} and {''x''<sub>0</sub>} × ''Y''. These subspaces intersect at a single point: (''x''<sub>0</sub>, ''y''<sub>0</sub>), the basepoint of ''X'' × ''Y''. So the union of these subspaces can be identified with the [[wedge sum]] ''X'' ∨ ''Y''. The smash product is then the quotient | |||
:<math>X \wedge Y = (X \times Y) / (X \vee Y). \, </math> | |||
The smash product has important applications in [[homotopy theory]], a branch of [[algebraic topology]]. In homotopy theory, one often works with a different [[category (mathematics)|category]] of spaces than the category of all topological spaces. In some of these categories the definition of the smash product must be modified slightly. For example, the smash product of two [[CW complex]]es is a CW complex if one uses the product of CW complexes in the definition rather than the product topology. Similar modifications are necessary in other categories. | |||
==Examples== | ==Examples== | ||
*The smash product of any pointed space ''X'' with a [[0-sphere]] is homeomorphic to ''X''. | |||
* | *The smash product of two circles is a quotient of the [[torus]] homeomorphic to the 2-sphere. | ||
*More generally, the smash product of two spheres ''S''<sup>''m''</sup> and ''S''<sup>''n''</sup> is [[homeomorphic]] to the sphere ''S''<sup>''m''+''n''</sup>. | |||
* | *The smash product of a space ''X'' with a circle is homeomorphic to the [[reduced suspension]] of ''X'': | ||
*:<math> \Sigma X \cong X \wedge S^1. \, </math> | |||
*The ''k''-fold iterated reduced suspension of ''X'' is homeomorphic to the smash product of ''X'' and a ''k''-sphere | |||
*:<math> \Sigma^k X \cong X \wedge S^k. \, </math> | |||
* In [[domain theory]], taking the product of two domains (so that the product is strict on its arguments). | |||
''' | |||
* | |||
==As a symmetric monoidal product== | |||
For any pointed spaces ''X'', ''Y'', and ''Z'' in an appropriate "convenient" category (e.g. that of [[compactly generated space]]s) there are natural (basepoint preserving) [[homeomorphism]]s | |||
:<math>\begin{align} | |||
X \wedge Y &\cong Y\wedge X, \\ | |||
(X\wedge Y)\wedge Z &\cong X \wedge (Y\wedge Z). | |||
\end{align}</math> | |||
However, for the naive category of pointed spaces, this fails. See the following discussion on MathOverflow.<ref>Omar Antolín-Camarena (mathoverflow.net/users/644), In which situations can one see that topological spaces are ill-behaved from the homotopical viewpoint?, http://mathoverflow.net/questions/76594 (version: 2011-09-28)</ref> | |||
These isomorphisms make the appropriate [[category of pointed spaces]] into a [[symmetric monoidal category]] with the smash product as the monoidal product and the pointed [[0-sphere]] (a two-point discrete space) as the unit object. One can therefore think of the smash product as a kind of [[tensor product]] in an appropriate category of pointed spaces. | |||
== | ==Adjoint relationship== | ||
[[Adjoint functors]] make the analogy between the tensor product and the smash product more precise. In the category of [[module (mathematics)|''R''-modules]] over a [[commutative ring]] ''R'', the tensor functor (– ⊗<sub>''R''</sub> ''A'') is left adjoint to the internal [[Hom functor]] Hom(''A'',–) so that: | |||
:<math>\mathrm{Hom}(X\otimes A,Y) \cong \mathrm{Hom}(X,\mathrm{Hom}(A,Y)).</math> | |||
In the [[category of pointed spaces]], the smash product plays the role of the tensor product. In particular, if ''A'' is [[locally compact Hausdorff]] then we have an adjunction | |||
:<math>\mathrm{Hom}(X\wedge A,Y) \cong \mathrm{Hom}(X,\mathrm{Hom}(A,Y))</math> | |||
where Hom(''A'',''Y'') is the space of based continuous maps together with the [[compact-open topology]]. | |||
{ | In particular, taking ''A'' to be the [[unit circle]] ''S''<sup>1</sup>, we see that the suspension functor Σ is left adjoint to the [[loop space]] functor Ω. | ||
{ | :<math>\mathrm{Hom}(\Sigma X,Y) \cong \mathrm{Hom}(X,\Omega Y).</math> | ||
{{ | ==References== | ||
{{Reflist}} | |||
*{{Hatcher AT}} | |||
{{DEFAULTSORT:Smash Product}} | |||
[[Category:Topology]] | |||
[[Category:Homotopy theory]] | |||
[[Category:Binary operations]] | |||
[[ | |||
[[ | |||
[[ |
Revision as of 16:13, 12 August 2014
Template:One source In mathematics, the smash product of two pointed spaces (i.e. topological spaces with distinguished basepoints) X and Y is the quotient of the product space X × Y under the identifications (x, y0) ∼ (x0, y) for all x ∈ X and y ∈ Y. The smash product is usually denoted X ∧ Y or X ⨳ Y. The smash product depends on the choice of basepoints (unless both X and Y are homogeneous).
One can think of X and Y as sitting inside X × Y as the subspaces X × {y0} and {x0} × Y. These subspaces intersect at a single point: (x0, y0), the basepoint of X × Y. So the union of these subspaces can be identified with the wedge sum X ∨ Y. The smash product is then the quotient
The smash product has important applications in homotopy theory, a branch of algebraic topology. In homotopy theory, one often works with a different category of spaces than the category of all topological spaces. In some of these categories the definition of the smash product must be modified slightly. For example, the smash product of two CW complexes is a CW complex if one uses the product of CW complexes in the definition rather than the product topology. Similar modifications are necessary in other categories.
Examples
- The smash product of any pointed space X with a 0-sphere is homeomorphic to X.
- The smash product of two circles is a quotient of the torus homeomorphic to the 2-sphere.
- More generally, the smash product of two spheres Sm and Sn is homeomorphic to the sphere Sm+n.
- The smash product of a space X with a circle is homeomorphic to the reduced suspension of X:
- The k-fold iterated reduced suspension of X is homeomorphic to the smash product of X and a k-sphere
- In domain theory, taking the product of two domains (so that the product is strict on its arguments).
As a symmetric monoidal product
For any pointed spaces X, Y, and Z in an appropriate "convenient" category (e.g. that of compactly generated spaces) there are natural (basepoint preserving) homeomorphisms
However, for the naive category of pointed spaces, this fails. See the following discussion on MathOverflow.[1]
These isomorphisms make the appropriate category of pointed spaces into a symmetric monoidal category with the smash product as the monoidal product and the pointed 0-sphere (a two-point discrete space) as the unit object. One can therefore think of the smash product as a kind of tensor product in an appropriate category of pointed spaces.
Adjoint relationship
Adjoint functors make the analogy between the tensor product and the smash product more precise. In the category of R-modules over a commutative ring R, the tensor functor (– ⊗R A) is left adjoint to the internal Hom functor Hom(A,–) so that:
In the category of pointed spaces, the smash product plays the role of the tensor product. In particular, if A is locally compact Hausdorff then we have an adjunction
where Hom(A,Y) is the space of based continuous maps together with the compact-open topology.
In particular, taking A to be the unit circle S1, we see that the suspension functor Σ is left adjoint to the loop space functor Ω.
References
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- ↑ Omar Antolín-Camarena (mathoverflow.net/users/644), In which situations can one see that topological spaces are ill-behaved from the homotopical viewpoint?, http://mathoverflow.net/questions/76594 (version: 2011-09-28)