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In the mathematical theory of probability, a Borel right process, named after Émile Borel, is a particular kind of continuous-time random process.

Let E be a locally compact, separable, metric space. We denote by the Borel subsets of E. Let Ω be the space of right continuous maps from [0,) to E that have left limits in E, and for each t[0,), denote by Xt the coordinate map at t; for each ωΩ, Xt(ω)E is the value of ω at t. We denote the universal completion of by *. For each t[0,), let

t=σ{Xs1(B):s[0,t],B},
t*=σ{Xs1(B):s[0,t],B*},

and then, let

=σ{Xs1(B):s[0,),B},
*=σ{Xs1(B):s[0,),B*}.

For each Borel measurable function f on E, define, for each xE,

Uαf(x)=Ex[0eαtf(Xt)dt].

Since Ptf(x)=Ex[f(Xt)] and the mapping given by tXt is right continuous, we see that for any uniformly continuous function f, we have the mapping given by tPtf(x) is right continuous.

Therefore, together with the monotone class theorem, for any universally measurable function f, the mapping given by (t,x)Ptf(x), is jointly measurable, that is, ([0,))* measurable, and subsequently, the mapping is also (([0,))*)λμ-measurable for all finite measures λ on ([0,)) and μ on *. Here, (([0,))*)λμ is the completion of ([0,))* with respect to the product measure λμ. Thus, for any bounded universally measurable function f on E, the mapping tPtf(x) is Lebeague measurable, and hence, for each α[0,), one can define

Uαf(x)=0eαtPtf(x)dt.

There is enough joint measurability to check that {Uα:α(0,)} is a Markov resolvent on (E,*), which uniquely associated with the Markovian semigroup {Pt:t[0,)}. Consequently, one may apply Fubini's theorem to see that

Uαf(x)=Ex[0eαtf(Xt)dt].

The followings are the defining properties of Borel right processes:

  • Hypothesis Droite 1:
For each probability measure μ on (E,), there exists a probability measure Pμ on (Ω,*) such that (Xt,t*,Pμ) is a Markov process with initial measure μ and transition semigroup {Pt:t[0,)}.
  • Hypothesis Droite 2:
Let f be α-excessive for the resolvent on (E,*). Then, for each probability measure μ on (E,), a mapping given by tf(Xt) is Pμ almost surely right continuous on [0,).

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