# Diophantine equation

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Finding all right triangles with integer side-lengths is equivalent to solving the Diophantine equation ${\displaystyle a^{2}+b^{2}=c^{2}\,}$.

In mathematics, a Diophantine equation is a polynomial equation in two or more unknowns such that only the integer solutions are searched or studied (an integer solution is a solution such that all the unknowns take integer values). A linear Diophantine equation is an equation between two sums of monomials of degree zero or one. An exponential Diophantine equation is one in which exponents on terms can be unknowns.

Diophantine problems have fewer equations than unknown variables and involve finding integers that work correctly for all equations. In more technical language, they define an algebraic curve, algebraic surface, or more general object, and ask about the lattice points on it.

The word Diophantine refers to the Hellenistic mathematician of the 3rd century, Diophantus of Alexandria, who made a study of such equations and was one of the first mathematicians to introduce symbolism into algebra. The mathematical study of Diophantine problems that Diophantus initiated is now called Diophantine analysis.

While individual equations present a kind of puzzle and have been considered throughout history, the formulation of general theories of Diophantine equations (beyond the theory of quadratic forms) was an achievement of the twentieth century.

## Examples

In the following Diophantine equations, x, y, and z are the unknowns and the other letters are given constants:

 ${\displaystyle ax+by=1\,}$ This is a linear Diophantine equation. ${\displaystyle x^{n}+y^{n}=z^{n}\,}$ For n = 2 there are infinitely many solutions (x,y,z): the Pythagorean triples. For larger integer values of n, Fermat's Last Theorem states there are no positive integer solutions (x, y, z). ${\displaystyle x^{2}-ny^{2}=\pm 1\,}$ This is Pell's equation, which is named after the English mathematician John Pell. It was studied by Brahmagupta in the 7th century, as well as by Fermat in the 17th century. ${\displaystyle {\frac {4}{n}}={\frac {1}{x}}+{\frac {1}{y}}+{\frac {1}{z}}}$ The Erdős–Straus conjecture states that, for every positive integer n ≥ 2, there exists a solution in x, y, and z, all as positive integers. Although not usually stated in polynomial form, this example is equivalent to the polynomial equation 4xyz = yzn + xzn + xyn = n(yz + xz + xy).

## {{safesubst:#invoke:anchor|main}}Linear Diophantine equations

### One equation

The simplest linear Diophantine equation takes the form ax + by = c, where a, b and c are given integers. The solutions are completely described by the following theorem: This Diophantine equation has a solution (where x and y are integers) if and only if c is a multiple of the greatest common divisor of a and b. Moreover, if (x, y) is a solution, then the other solutions have the form (x + kv, y - ku), where k is an arbitrary integer, and u and v are the quotients of a and b (respectively) by the greatest common divisor of a and b.

Proof: If d is this greatest common divisor, Bézout's identity asserts the existence of integers e and f such that ae + bf = d. If c is a multiple of d, then c = dh for some integer h, and (eh, fh) is a solution. On the other hand, for every integers x and y, the greatest common divisor d of a and b divides ax + by. Thus, if the equation has a solution, then c must be a multiple of d. If a = ud and b = vd, then for every solution (x, y), we have

${\displaystyle a(x+kv)+b(y-ku)=ax+by+k(av-bu)=ax+by+k(udv-vdu)=ax+by}$,

showing that (x + kv, y - ku) is another solution. Finally, given two solutions such that ax1 + by1 = ax2 + by2 = c, one deduces that u (x2 - x1) + v (y2 - y1) = 0. As u and v are coprime, Euclid's lemma shows that there exists an integer k such that x2 - x1 = kv and y2 - y1 = -ku. Therefore x2 = x1 + kv and y2 = y1 - kv, which completes the proof.

### Chinese remainder theorem

The Chinese remainder theorem describes an important class of linear Diophantine systems of equations: let n1, ..., nk be k pairwise coprime integers greater than one, a1, ..., ak be k arbitrary integers, and N be the product n1 ··· nk. The Chinese remainder theorem asserts that the following linear Diophantine system has exactly one solution (x, x1, ..., xk) such that 0 ≤ x < N, and that the other solutions are obtained by adding to x a multiple of N:

{\displaystyle {\begin{aligned}x&=a_{1}+n_{1}\,x_{1}\\&\vdots \\x&=a_{k}+n_{k}\,x_{k}\end{aligned}}}

### System of linear Diophantine equations

More generally, every system of linear Diophantine equations may be solved by computing the Smith normal form of its matrix, in a way that is similar to the use of the Reduced row echelon form to solve a system of linear equations over a field. Using matrix notation every system of linear Diophantine equations may be written

${\displaystyle A\,X=C,}$

where A is a m×n matrix of integers, X is a n×1 column matrix of unknowns and C is a m×1 column matrix of integers.

The computation of the Smith normal form of A provides two unimodular matrices (that is matrices that are invertible over the integers, which have ±1 as determinant) U and V of respective dimensions m×m and n×n, such that the matrix

${\displaystyle B=\left[b_{i,j}\right]=UAV}$

is such that bi,i is not zero for i not greater than some integer k, and all the other entries are zero. The system to be solved may thus be rewritten as

${\displaystyle B\,(V^{-1}X)=UC.}$

Calling yi the entries of ${\displaystyle V^{-1}X}$ and di those of ${\displaystyle D=UC,}$ this leads to the system

bi,i yi = di for 1 ≤ ik,
0 yi = di for k < in.

This system is equivalent to the given one in the following sense: A column matrix of integers x is a solution of the given system if and only if x = V y for some column matrix of integers y such that By = D.

It follows that the system has a solution if and only if bi,i divides di for ik and di = 0 for i > k. If this condition is fulfilled, the solutions of the given system are

${\displaystyle V\,\left[{\begin{array}{c}{\frac {d_{1}}{b_{1,1}}}\\\vdots \\{\frac {d_{k}}{b_{k,k}}}\\h_{k+1}\\\vdots \\h_{n}\end{array}}\right]\,,}$

where hk+1, ..., hn are arbitrary integers.

## Diophantine analysis

### Typical questions

The questions asked in Diophantine analysis include:

1. Are there any solutions?
2. Are there any solutions beyond some that are easily found by inspection?
3. Are there finitely or infinitely many solutions?
4. Can all solutions be found in theory?
5. Can one in practice compute a full list of solutions?

These traditional problems often lay unsolved for centuries, and mathematicians gradually came to understand their depth (in some cases), rather than treat them as puzzles.

### Typical problem

The given information is that a father's age is 1 less than twice that of his son, and that the digits AB making up the father's age are reversed in the son's age (i.e. BA). This leads to the equation 10A + B = 2 (10B + A) - 1, thus 19B - 8A = 1. Inspection gives the result A = 7, B = 3, and thus AB = 73 years and BA = 37 years. One may easily show that there is not any other solution with A and B positive integers less than 10.

### 17th and 18th centuries

In 1637, Pierre de Fermat scribbled on the margin of his copy of Arithmetica: "It is impossible to separate a cube into two cubes, or a fourth power into two fourth powers, or in general, any power higher than the second into two like powers." Stated in more modern language, "The equation an + bn = cn has no solutions for any n higher than 2." And then he wrote, intriguingly: "I have discovered a truly marvelous proof of this proposition, which this margin is too narrow to contain." Such a proof eluded mathematicians for centuries, however, and as such his statement became famous as Fermat's Last Theorem. It wasn't until 1995 that it was proven by the British mathematician Andrew Wiles.

In 1657, Fermat attempted to solve the Diophantine equation 61x2 + 1 = y2 (solved by Brahmagupta over 1000 years earlier). The equation was eventually solved by Euler in the early 18th century, who also solved a number of other Diophantine equations.The smallest solution of this equation in positive integers is x = 226153980, y = 1766319049 (see Chakravala method).

### Hilbert's tenth problem

In 1900, in recognition of their depth, David Hilbert proposed the solvability of all Diophantine problems as the tenth of his celebrated problems. In 1970, a novel result in mathematical logic known as Matiyasevich's theorem settled the problem negatively: in general Diophantine problems are unsolvable.

### Diophantine geometry

Diophantine geometry, which is the application of techniques from algebraic geometry in this field, has continued to grow as a result; since treating arbitrary equations is a dead end, attention turns to equations that also have a geometric meaning. The central idea of Diophantine geometry is that of a rational point, namely a solution to a polynomial equation or a system of polynomial equations, which is a vector in a prescribed field K, when K is not algebraically closed.

### Modern research

One of the few general approaches is through the Hasse principle. Infinite descent is the traditional method, and has been pushed a long way.

The depth of the study of general Diophantine equations is shown by the characterisation of Diophantine sets as equivalently described as recursively enumerable. In other words, the general problem of Diophantine analysis is blessed or cursed with universality, and in any case is not something that will be solved except by re-expressing it in other terms.

The field of Diophantine approximation deals with the cases of Diophantine inequalities. Here variables are still supposed to be integral, but some coefficients may be irrational numbers, and the equality sign is replaced by upper and lower bounds.

The most celebrated single question in the field, the conjecture known as Fermat's Last Theorem, was solved by Andrew Wiles[1] but using tools from algebraic geometry developed during the last century rather than within number theory where the conjecture was originally formulated. Other major results, such as Faltings' theorem, have disposed of old conjectures.

### Infinite Diophantine equations

An example of an infinite diophantine equation is:

${\displaystyle N=A^{2}+2B^{2}+3C^{2}+4D^{2}+5E^{2}+....}$

which can be expressed as "How many ways can a given integer N be written as the sum of a square plus twice a square plus thrice a square and so on?" The number of ways this can be done for each N forms an integer sequence. Infinite Diophantine equations are related to theta functions and infinite dimensional lattices. This equation always has a solution for any positive N. Compare this to:

${\displaystyle N=A^{2}+4B^{2}+9C^{2}+16D^{2}+25E^{2}+....}$

which does not always have a solution for positive N.

## Exponential Diophantine equations

If a Diophantine equation has as an additional variable or variables occurring as exponents, it is an exponential Diophantine equation. One example is the Ramanujan–Nagell equation, 2n − 7 = x2. A general theory for such equations is not available; particular cases such as Catalan's conjecture have been tackled. However, the majority are solved via ad hoc methods such as Størmer's theorem or even trial and error.

## References

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