Isodynamic point

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Goursat's lemma is an algebraic theorem about subgroups of the direct product of two groups.

It can be stated as follows.

Let G, G be groups, and let H be a subgroup of G×G such that the two projections p1:HG and p2:HG are surjective (i.e., H is a subdirect product of G and G). Let N be the kernel of p2 and N the kernel of p1. One can identify N as a normal subgroup of G, and N as a normal subgroup of G. Then the image of H in G/N×G/N is the graph of an isomorphism G/NG/N.

An immediate consequence of this is that the subdirect product of two groups can be described as a fiber product and vice versa.

Proof of Goursat's lemma

Before proceeding with the proof, N and N are shown to be normal in G×{e} and {e}×G, respectively. It is in this sense that N and N can be identified as normal in G and G', respectively.

Since p2 is a homomorphism, its kernel N is normal in H. Moreover, given gG, there exists h=(g,g)H, since p1 is surjective. Therefore, p1(N) is normal in G, viz:

gp1(N)=p1(h)p1(N)=p1(hN)=p1(Nh)=p1(N)g.

It follows that N is normal in G×{e} since

(g,e)N=(g,e)(p1(N)×{e})=gp1(N)×{e}=p1(N)g×{e}=(p1(N)×{e})(g,e)=N(g,e).

The proof that N is normal in {e}×G proceeds in a similar manner.

Given the identification of G with G×{e}, we can write G/N and gN instead of (G×{e})/N and (g,e)N, gG. Similarly, we can write G/N and gN, gG.

On to the proof. Consider the map HG/N×G/N defined by (g,g)(gN,gN). The image of H under this map is {(gN,gN)|(g,g)H}. This relation is the graph of a well-defined function G/NG/N provided gN=NgN=N, essentially an application of the vertical line test.

Since gN=N (more properly, (g,e)N=N), we have (g,e)NH. Thus (e,g)=(g,g)(g1,e)H, whence (e,g)N, that is, gN=N. Note that by symmetry, it is immediately clear that gN=NgN=N, i.e., this function also passes the horizontal line test, and is therefore one-to-one. The fact that this function is a surjective group homomorphism follows directly.

References